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Old September 30th 03, 11:21 AM
Frank
 
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Spurious Noise yI5eb.34774$Ms2.224@fed1read03...

^ Just FYI:
^ CW Bandwidth = wpm X 4 (e.g., 40 WPM = 160 Hz)
^ From the ARRL License Manual 1976:
^ "With proper shaping, the necessary keying bandwidth is equal to 4
^ times the speed in words per minute for International Morse Code;
^ e.g. at 25 words per minute, the bandwidth is approximately 100
^ cycles."

Thank you. SSB is about twice that right? And isn't SSB the narrowest voice
emission?

Frank