On Mon, 6 Sep 2004 10:39:54 -0400, "Tam/WB2TT" wrote:
Hi Roy,
Going back to the Slick discussions of last winter, Was that you who made
the statement that you can have 100% re reflection from a transmitter, even
if it has a 50 Ohm output impedance? At first I thought this was all wet,
but after making some low power experiments, I am convinced it is true.
Tam/WB2TT
Yep , Tam, it's correct. The internal resistance in Class B and C amps has two
parts, 1) the cathode-to-plate resistance, which is dissipative, and 2) the
non-dissipative resistance established by the V/I ratio within the pi-network
tank circuit--a high resistance at the input and a low resistance at the output.
The V/I ratio also establishes the slope of the load line. Consequently, the
reflected power reaching the network output is not absorbed, but instead adds to
the power delivered by the generator. Although powers are not generally
considered to add, they do in this case, because their respective voltage and
current phasors add. If the reflected voltage and current phasors are not in
phase with those from he source, the only result is that the source is
mismatched to the load and reduces its delivery of power. Readjusting the tuning
and loading controls brings the out-of-phase phasors in phase, establishes a
conjugate match and the source again delivers the maximum available power.
Walt, W2DU
|