Richard Clark wrote:
how does a transmitter happen to always be "in-phase" to any
reflection?

It doesn't. The reflected voltage can obviously be 90 degrees
out of phase with the forward voltage in which case, the
interference term equals zero, and the superposed voltage is
SQRT(Vf^2+Vr^2), i.e. greater than Vf. (The argument reminds
me of Gary Coffman's one-dimensional "spitting up the fire
hose" argument.)
--
73, Cecil http://www.qsl.net/w5dxp


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