On Thu, 30 Jun 2005 13:28:24 -0500, Cecil Moore
wrote:
You will get interference rings
[Hecht rolling his eyes] for a target that is smaller than a
wavelength?
Must be another failure of Hecht (or Hecht pupil).
of 400w/unit-area and
rings of 0w/unit-area all averaging out to 200w total.
Which, of course, cannot be found in the formula:
Itot = I1 + I2 + 2*Sqrt(I1*I2)cos(theta)
nor its correction:
Itot = I1 + I2 +2*SQRT(I1*I2)cos(theta)
If the sources are incapable of supplying the extra power,
Which, in the end was a non sequitur.
For every P1+P2+2*SQRT(P1*P2), i.e. constructive interference,
Which, of course, cannot be found in the formula:
Itot = I1 + I2 + 2*Sqrt(I1*I2)cos(theta)
nor its correction:
Itot = I1 + I2 +2*SQRT(I1*I2)cos(theta)
there is a P1+P2-2*SQRT(P1*P2), i.e. destructive interference.
Which, of course, cannot be found in the formula:
Itot = I1 + I2 + 2*Sqrt(I1*I2)cos(theta)
nor its correction:
Itot = I1 + I2 +2*SQRT(I1*I2)cos(theta)

When combined with the adhominem (which, of course, reveals another
inaccuracy, one of assignment):
Please spare us your ignorance and read the book.
is possibly the best advice (once the assignment is corrected), given
the continuing goof-ups.