"Cecil Moore" wrote in message
.. .
Dave wrote:
math please??? where do you get 4.17watts?? to me it looks like a 50 ohm
load on a 50 ohm meter so zero reflected power.

Here's the setup.

100W--tuner--75 ohm coax--Bird--1/2WL 75 ohm coax--50 ohm load

Assumptions: Losses are negligible. The tuner provides a Z0-match
so 100 watts is delivered to the load, i.e. all reflected power
is re-reflected. I think this was actually the case for the experiment.
Also assume that the impedance bump caused by the insertion of the
Bird is negligible, i.e. the same net voltage and net current exists
whether the Bird is in or out of the circuit.

STOP!

you can not assume this, especially if you consider the actual results of
the experiment. the bird is a 50 ohm transmission line segment and it is
seeing a 50 ohm load. the 50 ohm load plus 1/2 wave of anything is 50 ohms.
so as far as the bird knows there is no reflected power and the real world
reading is correct.