Radio913 wrote:
What is the center of the Smith Chart when characteristic impedance
Zo= 50 + j50?
I suspect that the standard Smith Chart is incapable of handling
a Z0 = 50 + j50. On the standard Smith Chart, would the center of
the SWR spiral be 1 + j for a Z0 = 50 +j50? If so, that would make
for some interesting impedance transformations.
--
73, Cecil
http://www.qsl.net/w5dxp
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