Try increased capacitance from larger wire diameter, larger surface (plate)
area.
Capacitance goes up, inductance (length) has to come down in order to
maintain resonance - LC circuit in standing wave environment.

73 Yuri, K3BU, VE3BMV, VE1BY

"Pierre Desjardins" wrote in message
...
Hi to all.. It is well know that a reduction in the diameter of the
wire must be compensated by a higher antenna length to maintain
resonance.

I am looking for an explanation of the reason for this. Why the total
reactance becomes more capacitive? I know math formula showing the
variation of the inductance of the wire vs its diameter, but I a
looking for the real reason, not the mathematical consequence.

I suspect that a higher diam cause higher transormation of AC to
electromagnetic energy on a segment delta(l) so that a shorter
physical length would be needed to include the full electrical 180
degrees of a dipole.. but not really sure of this.

Any comment would be welcome

Thanks, and 73 de Pierre ve2pid