Richard Clark wrote in
:

On Thu, 01 Mar 2007 20:45:44 GMT, Owen Duffy wrote:

Any notion that reflected power *must* flow back to the source and is
dissipated as heat will not lead to the correct solution of this
problem.

Hi Owen,

Why must it flow back, when the generator itself presents a huge
mismatch to the line? The laws of reflection work at both ends of the
line and to force the presumption that initial reflected power would
flow through this discontinuity without reflection is a strained
expectation. However, I see by the alteration that follows, that we
now have a fully matching source:

As an exercise, think of a generator that has a Thevenin equivalent of
some voltage V and a series impedance of R+j0, connected to a half wave
of lossless transmission line where Zo=R. To give a numerical example,
lets make V=100 and R=50, so Vr=50 and "reflected power"=50. How much
of
the "reflected power" is dissipated in the generator. In this case, the
generator dissipates less heat than were it terminated in 50 ohms.

"reflected power"= 50 what? Watts? So be it. Your intent may not to
be incomplete nor difficult, but what is wrong with specifying the
load? Do we get a line length?

The line is stated as a half wave of lossless line, why do you need to
know more about its length?

The load you are looking for isn't there, the line ends in an open
circuit. Sorry for the confusion, I should have been explicit that there
was no load, just o/c.

The misunderstandings will frustrate your analysis, so try again.

Owen