On Dec 4, 9:06 pm, "Tom Donaly" wrote:
50 ohm Shorted line 8.5655 meters long. Frequency = 7 Mhz. 2 volt 50 ohm
generator. Current at input = 12.361 milliamps. Current at short =
40 milliamps. Divide the current at the imput of the line by the current
at the short and take the arc sine (in radian mode)

arc cosine, perhaps?

of the result. This
is 1.2566. Now take Beta = .14671 and multiply it by the length 8.5655.
This also equals 1.2566, which is the angular length of the shorted
line. Will someone explain how this works to Cecil?

Cecil either knows this, in which case it is unnecessary to explain
it,
or he does not, in which case it will be impossible.

....Keith