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Old December 5th 07, 06:11 AM posted to rec.radio.amateur.antenna
Tom Donaly Tom Donaly is offline
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First recorded activity by RadioBanter: Jul 2006
Posts: 274
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Tom Donaly wrote:
Keith Dysart wrote:
On Dec 4, 9:06 pm, "Tom Donaly" wrote:
50 ohm Shorted line 8.5655 meters long. Frequency = 7 Mhz. 2 volt 50 ohm
generator. Current at input = 12.361 milliamps. Current at short =
40 milliamps. Divide the current at the imput of the line by the current
at the short and take the arc sine (in radian mode)


arc cosine, perhaps?

of the result. This
is 1.2566. Now take Beta = .14671 and multiply it by the length 8.5655.
This also equals 1.2566, which is the angular length of the shorted
line. Will someone explain how this works to Cecil?


Cecil either knows this, in which case it is unnecessary to explain
it,
or he does not, in which case it will be impossible.

...Keith

Right. I lied.
73,
Tom Donaly, KA6RUH

To amplify:
Arc Cosine is correct. And the comment on Cecil is right on the mark.
The same thing can be accomplished, above, using an open stub and
measuring the voltage at both ends. All this is just theoretical,
though, because line loss will skew the results. Besides, why try to
measure current or voltage when all you have to do is measure length
and frequency?
73,
Tom Donaly, KA6RUH