Home |
Search |
Today's Posts |
#11
![]() |
|||
|
|||
![]()
Bob,
Sorry for the strong words, but the intent remains the same. I don't know what happens to the source impedance when the load is changed, because the system is undefined. However, read carefully the definition at the beginning of your paper. The Maximum Power Transfer Theorem: The maximum power will be absorbed by one network from another joined to it at two terminals, when the impedance of the receiving network is varied, if the impedance looking into the two networks at the junction are conjugates of each other [1] |
#12
![]() |
|||
|
|||
![]()
Gene Fuller wrote:
"I don`t know what happens to the source impedance when the load is changed, because the system is undefined." Yes. Maximum power transfer is accomplished by making the load impedance the conjugate of the generator impedance as defined by Thevenin`s theorem. The value of the Thevinen impedance is that which might be measured by a generator`s open-circuit voltage devided by its short-circuit current. You don`t need to know the generator`s specifics other than, drop in the output voltage is proportional to the current delivered. The current which flows in a linear load impedance connected to a Thevenin generator is the open-circuit voltage divided by the sum of the generator`s internal impedance and the load impedance. These may be complex impedances. At maximum power transfer, internal and load impedances are equal in resistance and their reactances are conjugate (opposite and equal). There is no requirement that resistance in either the generator or load be dissipative, and frequently, lossless resistance is a part of the generator impedance so that we can get maximum possible power into the load without losing 50% in the generator. Best regards, Richard Harrison, KB5WZI |
#13
![]() |
|||
|
|||
![]()
On Tue, 02 Mar 2004 15:37:25 GMT, Gene Fuller
wrote: Bob, Sorry for the strong words, but the intent remains the same. I don't know what happens to the source impedance when the load is changed, because the system is undefined. However, read carefully the definition at the beginning of your paper. The Maximum Power Transfer Theorem: The maximum power will be absorbed by one network from another joined to it at two terminals, when the impedance of the receiving network is varied, if the impedance looking into the two networks at the junction are conjugates of each other [1] . . . [1] W. L. Everitt, "Communication Engineering", McGraw-Hill, 1937 The maximum power transfer theorem describes the impact from change of the load impedance. It is not the Grand Unified Theory for all the universe. If someone tries to expand this elegant concept to all sorts of pathological cases then it is likely that confusion will ensue. The MPTT analysis is straightforward if the problem is well defined. The ongoing argument in amateur radio circles is about the source characteristics of amplifiers and tank circuits. The MPTT does not address that argument, but rather it is a victim of the silliness. Including the down-home touch of steam engines adds nothing to the technical content. Dear Gene, No problem, I will try to understand where you're coming from. Obviously, there have been some experiences in your tour of duty that have caused you some heartburn - it happens with all of us. Relative to your points about amplifiers, etc., I hope to have my article on that topic available before the end of this month. Actually, it has been "almost ready" for several days now, but there are some things that need to "cook" awhile before I release it. As soon as you get into the details of a Class-B linear, you're up to your butt in alligators, not to mention all of the myths surrounding them and the matching problem. I'll do my best to keep it "on topic" - Hi! 73, Bob |
#14
![]() |
|||
|
|||
![]()
From the design side, MPTT is defined at an interface, and minimizes
"reflected power" at that interface, and that is it. The other items about matching are also quite important, such as stability, loading, impedance transfer (both directions), bandwidth, Qs, loaded Qs etc. But that is Not MPTT. There is a tradeoff between these, if one can also obtain mptt, great, but close is good too. mptt is just one of several parameters needed to optimize a match. At times there are too many unknowns and the matching is experimental (class C) .................................................. ........................... ........................ "Robert Lay W9DMK" wrote in message ... On Mon, 01 Mar 2004 22:23:56 GMT, Gene Fuller wrote: What a load of crap! The only difficulty in the MPTT occurs when some folks create new definitions and new constraints that are not shared by others in the discussion. Allowing the problem to float at will means that the solutions will float as well. The longstanding MPTT argument in amateur radio circles is not really about power transfer and conjugate matching. The argument is typically about what happens to the source impedance under varying load conditions. Steam engines? Gear boxes? Yeah, sure, they help a lot. That's a fair question, Gene - what does happen to the source impedance under varying load conditions? While you're at it, could you please explain how you would separate the issues of maximum power transfer and conjugate matching from the question of what happens to the source impedance under varying load conditions? I have no problem in supplying copies of the article to anyone who requests a particular format by e-mail - available choices are pdf, html, or Word for Windows 97 or 2003. The complete file is approximately 1 MB in any of the formats. 73, Bob |
#15
![]() |
|||
|
|||
![]() "John Smith" said - MPTT is defined at an interface, and minimizes "reflected power" at that interface, and that is it. =============================== Indeed it is. R+jX one way and R-jX the other. Why the vast amount of palaver and bickering about such an obvious and elementary notion defeats the imagination. |
#16
![]() |
|||
|
|||
![]()
Reg Edwards wrote:
Indeed it is. R+jX one way and R-jX the other. Why the vast amount of palaver and bickering about such an obvious and elementary notion defeats the imagination. Reg, you are in a room with a transmission line passing through it. You measure all voltages, currents, and powers. How do use your "obvious and elementary notions" to tell if the transmission line is conjugately matched or not? How do you measure the impedance looking toward a typical amateur radio transmitter without changing the very thing you are trying to measure? Many have tried and many have failed. -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
#17
![]() |
|||
|
|||
![]()
Check for reflected power in either direction.
If none, then it is conjugally matched exactly. If it is about -14 dB down, that is good and close enough. One can try to measure Tx output Z (looking into Tx) and then the Z looking backup the antenna line, and try matching the two as a start, but reflected power quicker, faster, more accurate. (also I agree with you in trying to measure Tx output Z (looking into the output) tried and got a mess many times,...) "Cecil Moore" wrote in message ... Reg Edwards wrote: Indeed it is. R+jX one way and R-jX the other. Why the vast amount of palaver and bickering about such an obvious and elementary notion defeats the imagination. Reg, you are in a room with a transmission line passing through it. You measure all voltages, currents, and powers. How do use your "obvious and elementary notions" to tell if the transmission line is conjugately matched or not? How do you measure the impedance looking toward a typical amateur radio transmitter without changing the very thing you are trying to measure? Many have tried and many have failed. -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
#18
![]() |
|||
|
|||
![]()
Cecil,
Are you suggesting that a steam engine is needed in addition to "obvious and elementary notions"? Let's see, how about a nice triple expansion engine fed from a Scotch boiler fueled with the finest Welsh coal. Don't forget to raise steam slowly, and make sure you don't tie down the safety valve. 8-) 73, Gene W4SZ Cecil Moore wrote: Reg Edwards wrote: Indeed it is. R+jX one way and R-jX the other. Why the vast amount of palaver and bickering about such an obvious and elementary notion defeats the imagination. Reg, you are in a room with a transmission line passing through it. You measure all voltages, currents, and powers. How do use your "obvious and elementary notions" to tell if the transmission line is conjugately matched or not? How do you measure the impedance looking toward a typical amateur radio transmitter without changing the very thing you are trying to measure? Many have tried and many have failed. |
#19
![]() |
|||
|
|||
![]()
On Tue, 2 Mar 2004 14:40:02 -0600, "John Smith"
wrote: Check for reflected power in either direction. Hi John, You would be surprised how hard that is for some, especially when an argument about the direction of current flow becomes part of the turmoil. If none, then it is conjugally matched exactly. Still too simple, not enough gristle to chew on. ;-) If it is about -14 dB down, that is good and close enough. In three sentences you've said enough to resolve the matter. But not enough to end the debate.... 73's Richard Clark, KB7QHC |
#20
![]() |
|||
|
|||
![]()
Well sed!
Jack K9CUN |
Reply |
Thread Tools | Search this Thread |
Display Modes | |
|
|
![]() |
||||
Thread | Forum | |||
Complex Z0 [Corrected] | Antenna | |||
Derivation of the Reflection Coefficient? | Antenna | |||
The Cecilian Gambit, a variation on the Galilean Defense revisited | Antenna |