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William E. Sabin wrote:
Roy Lewallen wrote: In the fourth paragraph, you say that "real power is in the real part of the impedance", and in the last, that it's "found by integrating the Poynting vector slightly outside the surface of the antenna". The impedance is E/H, the Poynting vector E X H. Clearly these aren't equivalent. The radiated power is, as you say, the integral of the Poynting vector over a surface. (And the average, or "real", radiated power is the average of this.) Correction "real part of Poynting vector" noted. The problem remains: How is the *real* part of the antenna input impedance, regardless of how it is fed and regardless of what kind of antenna it is, get "transformed" to the *real* 377 ohms of free space? I believe (intuitively) that the reactive E and H near-fields collaborate to create an impedance transformation function, in much the same way as a lumped-element reactive L and C network. In other words, energy shuffling between inductive and capacitive fields do the job and the E and H fields modify to the real values of free space. The details of this are murky, But I believe the basic idea is correct. Bill W0IYH For example, consider an EZNEC solution to an antenna, say a 50 ohm dipole. The far-field 377 ohm solution provided by the program is precisely the field that I am thinking about. How does EZNEC, with its finite-element, method-of-moments algorithm, transform a 50 ohm dipole input resistance to 377 ohms in free space? I don't want the equations, I want a word description (preferably simple) of how EZNEC performs this magic. The far-field E and H fields are different from the near-field E and H fields. What is going on? Bill W0IYH |
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50 Ohms "Real Resistive" impedance a Misnomer? | Antenna |