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#11
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![]() "Roy Lewallen" wrote in message ... Z0 = 68 - j39 ohms. Zl = 10 + j50 ohms. Zl is certainly physically possible. I believe Z0 is also. According to A/C/F the angle of Zo is constrained to +/- 45 degrees. |
#12
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Cecil Moore wrote:
Using deductive reasoning, since the real part of the voltage reflection coefficient cannot be greater than 1.0, ... So much for my deductive reasoning - A kind soul has furnished proof by email that the real part of the voltage reflection can be greater than 1.0. Z_0 = 50 - 25j (which is well within the - 45 to 45 degree angle bounds) Z_L = 50 + 250j (chosen to make the arithmetic easy; there are lots more) Then Z_L - Z_0 = 275j and Z_L + Z_0 = 100 + 225j so that gamma = 11j/(4 + 9j) = 11j(4 - 9j)/(16 + 81) = (99 + 44j)/97. -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
#13
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Well, Cecil, I think we're zeroing in on the flaw in your perception of
how the powers add. I hope you won't just keep saying it's impossible, and will instead sharpen your pencil to show, as I have, the forward, reverse, and total voltages, currents, and powers at both ends of the line. And how everything can work together consistently to fit into your view of power addition and subtraction. A number of people have been trying for a long time to convince you there's a flaw in your logic, but so far you haven't been able to see it. Hopefully, in the process of deriving the values for this circuit, you'll see where your logic has gone astray. Or, perhaps, you'll come up with a completely consistent set of voltages, currents, and powers that do fit within your view. And we'll all learn from it as we see where the difference arises between your analysis and mine. Until you come up with your analysis, though, I won't pay much attention to your complaints that it's wrong unless you're able to show where in the analysis the error lies. I've posted the derivation of the total power formula on this thread. In going through it, I found an error in the formula posted with my numerical example. I've posted a correction for that on the same thread as the example. In the correction posting, I also show how the formula produces the same result as I got by directly calculating the total power from the load voltage and current. A closing quotation, from Johnson's _Transmission Lines and Networks_: "[For a low loss line] P = |E+|^2 / Z0 - |E-|^2 / Z0. We can regard the first term in this expression as the power associated with the forward-traveling wave, and the second term as the reflected power. This simple separation of power into two components, each associated with one of the traveling waves, can be done only when the characteristic impedance is a pure resistance. Otherwise, the interaction of the two waves gives rise to a third component of power. Thus, the concept applies to low-loss lines and to distortionless lines, but not to lossy lines in general." Something for you to think about. Or maybe you subscribe to Reg's view that these texts are written by marketeers and salesmen. After all, as Chairman of Princeton's EE department, I suppose Johnson's job was primarily PR. I'm quite sure that if you look carefully at any text where the author subtracts "reverse power" from "forward power" to get total power, that somewhere prior to that the assumption is made that loss is zero and/or the line's characteristic impedance is purely real. Roy Lewallen, W7EL Cecil Moore wrote: Roy Lewallen wrote: No, the average Poynting vector points toward the load. That automatically says Pz- is not larger than Pz+. There are only two component Poynting vectors, 'Pz+' forward and 'Pz-' reflected. If so, surely you came up with the same result, including the third power term. If you haven't done the derivation, or if you'd like to compare your derivation of total average power with mine, I'll be glad to post it. Assuming coherent waves, all wave components flowing toward the load superpose into the forward wave and all wave components flowing away from the load superpose into the reflected wave. Since there are only two directions, there cannot exist a third wave. If your average Poynting vector points toward the load, Pz- cannot possibly be larger than Pz+. But feel free to post the derivation. |
#14
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I believe that, and the value I used is within that range.
Roy Lewallen, W7EL Tarmo Tammaru wrote: "Roy Lewallen" wrote in message ... Z0 = 68 - j39 ohms. Zl = 10 + j50 ohms. Zl is certainly physically possible. I believe Z0 is also. According to A/C/F the angle of Zo is constrained to +/- 45 degrees. |
#15
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Roy Lewallen wrote:
Well, Cecil, I think we're zeroing in on the flaw in your perception of how the powers add. I don't see how this thread is relevant to the treatment of powers in lossless lines. Perhaps you have misunderstood what I said. A number of people have been trying for a long time to convince you there's a flaw in your logic, but so far you haven't been able to see it. If there's a flaw for lossless lines with purely resistive characteristic impedances, please present it. So far, nobody has. Here's what I said in my magazine article on my web page" "For the purpose of an energy analysis involving *LOSSLESS* transmission lines, we do not need to know anything about the source or the load or the length of the transmission lines." I'm quite sure that if you look carefully at any text where the author subtracts "reverse power" from "forward power" to get total power, that somewhere prior to that the assumption is made that loss is zero and/or the line's characteristic impedance is purely real. Of course, that's why my previous assertions have been only about lossless lines. Do you happen to have a lossless example that proves my concepts about lossless lines are wrong? I have no concepts about lossy lines except that they obey the conservation of energy principle. -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
#16
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Roy Lewallen wrote:
P1 = fP - rP + (|fE1|^2 / |Z0|) * rho * exp(-2 * ax) * 2 * sin(delta) * sin(2 * bx - 2 * psi). Seems to me, all the terms with a '+' sign would be forward power, by definition, and all the terms with a '-' sign would be reflected power, by definition. I don't see any violation of the conservation of energy principle. The power equation balances. -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
#17
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I apologize. I thought your view of power waves was alleged to hold true
even with loss. If it's restricted to lossless lines (which have purely real Z0), then the total average power does equal "forward power" minus "reverse power". So please don't bother yourself with trying to explain the component of power that's neither the "forward power" nor "reverse power". Roy Lewallen, W7EL Cecil Moore wrote: Roy Lewallen wrote: Well, Cecil, I think we're zeroing in on the flaw in your perception of how the powers add. I don't see how this thread is relevant to the treatment of powers in lossless lines. Perhaps you have misunderstood what I said. A number of people have been trying for a long time to convince you there's a flaw in your logic, but so far you haven't been able to see it. If there's a flaw for lossless lines with purely resistive characteristic impedances, please present it. So far, nobody has. Here's what I said in my magazine article on my web page" "For the purpose of an energy analysis involving *LOSSLESS* transmission lines, we do not need to know anything about the source or the load or the length of the transmission lines." I'm quite sure that if you look carefully at any text where the author subtracts "reverse power" from "forward power" to get total power, that somewhere prior to that the assumption is made that loss is zero and/or the line's characteristic impedance is purely real. Of course, that's why my previous assertions have been only about lossless lines. Do you happen to have a lossless example that proves my concepts about lossless lines are wrong? I have no concepts about lossy lines except that they obey the conservation of energy principle. |
#18
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Roy:
[snip] There are a lot of opportunities for typos in a derivation like this, especially when restricted to plain ASCII characters. I'd appreciate very much if anyone finding an error, either in concept, fact, assumption, or just typo, to call it to my attention so it can be corrected. Roy Lewallen, W7EL [snip] Wow! You said it Roy. BTW... thanks for all of your nice work. But for my taste it's far too detailed and seems filled with gratuitously long symbols for ASCII text consumers. My eyes glazed over and I nearly fell asleep and had to stop following after a couple of screens of what seemed to turn into gibberish before my eyes. Not your fault mind you, it's mine. On the other hand, ASCII NewsGroup postings are hardly the media for sharing such detailed algebraic/numeric developments! I just don't get the point of all of your wonderful efforts! Thoughts, comments, -- Peter |
#19
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"Peter O. Brackett" wrote:
On another whole level it simply DOES NOT MATER which defiinition of the reflection coefficient one uses to make design calculations though, as long as the definition is used consistently throughout any calculations. One can convert any results based on the non-conjugate version of rho to results based on the conjugate version of rho and vice versa. In other words, neither version is "RIGHT" or "WRONG" as long as the results from using that particular definition are interperted correctly in terms of the original definition. While true, this is not what is occuring in the 'revised rho' debate. Their claim is simply that 'classical rho' has been mis-calculated all these years and we should start using the 'proper' calculation. There is no acknowledgement that 'revised rho' will have different properties than 'classical rho' and that, therefore, they are introdcing a new entity. Their claim of incorrectness derives from the fact that 'classical rho' can have a magnitude greater than 1 and a belief that this means reflected power is greater than incident. This belief is inconsistent with generally accepted knowledge, so rather than modifying the belief, the derivation of 'classical rho' is rejected. Their second difficulty derives from not being able to separate the behaviour at a particular interface from the system behaviour. They do not recognize that a reflection at a particular interface (which would reduce energy transfer at that interface), can improve overall system energy transfer by improving the energy transfer at another interface. This being what a transmission line transformer does, for example. Once they overcome these two hurdles, they will have no problems with the classical definition of rho. So... who gives a damm about the defintion of rho as long as you are consistent in it's use. It simply doesn't matter! [Unless you choose M to be singular. ;-) ] There is no problem if this is what the 'revised rho' crowd really is attempting to do, but they should clearly state this and have the courtesy to pick a new name (despite Humpty-Dumpty's assertions) to facilitate clear communication. Really though, you are thinking several levels above them when you hypothesize the existence of other, self-consistent, definitions of rho. They are still at the 'classical rho computation is just plain wrong' level. ....Keith |
#20
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Roy Lewallen wrote:
Well, shucks, that makes it easy. Just being logical. There are only two directions in a transmission line, forward and reverse. If all the waves are coherent, all forward waves superpose to one wave and all reverse waves superpose to one other wave. Your net forward power is greater than your net reflected power by the net amount of power accepted by the load. This happens locally at the load no matter what is happening elsewhere in the transmission line. Cecil Moore wrote: Seems to me, all the terms with a '+' sign would be forward power, by definition, and all the terms with a '-' sign would be reflected power, by definition. I don't see any violation of the conservation of energy principle. The power equation balances. -- 73, Cecil http://www.qsl.net/w5dxp "One thing I have learned in a long life: that all our science, measured against reality, is primitive and childlike ..." Albert Einstein -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
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