Home |
Search |
Today's Posts |
#171
![]() |
|||
|
|||
![]()
Tarmo Tammaru wrote:
there would be no other explanation for standing waves, May I suggest that you consider charge. Consider how static charge can store energy in the capacitance of the line. Consider how moving charge can store energy in the inductance of the line. Consider how the charge moves to change the energy distribution within the line. Do it for a pulse of charge; then for multiple pulses. Consider what happens when the pulses collide; consider pulses of the same polarity and different. Do it for a step of charge; then make the step so long it looks like DC. Do it for sinusoids. Do it for opens, shorts and terminated lines. Do it for matched, unmatched and disconnected sources (disconnect just after injecting the pulse, step or sinusoid). Do it for sources at both ends of the lines. And soon you will have an explanation which does not require waves travelling up and down the line to explain the observed voltages and currents of the standing 'wave'. ....Keith |
#172
![]() |
|||
|
|||
![]()
W5DXP wrote:
Ian White, G3SEK wrote: Yes! That principle of impedance substitution is so simple, so fundamental, some people never notice it's there at all. And you would apparently like to pull the wool over the eyes of everyone who notices that the definition of impedance has changed in the process. Shame on you for that attempt at obfuscation! You are using that principle of impedance substitution whenever you calibrate your antenna impedance bridge using known values of resistORS, capacitORS and inductORS. Of course *you* are aware of the difference in what's connected to the instrument - you have more information than it has. The only claim Bill and I have been making is that you cannot tell the difference from any *electrical* measurement made at a single frequency in the steady state... and those were exactly the conditions that burned up your transmitter, so the substitution principle is valid for this branch of the discussion. That whole principle relies on the fact that, at the same frequency and in the steady state, the "definition of impedance" in terms of its electrical properties does *not* change. That's the whole point. -- 73 from Ian G3SEK 'In Practice' columnist for RadCom (RSGB) Editor, 'The VHF/UHF DX Book' http://www.ifwtech.co.uk/g3sek |
#173
![]() |
|||
|
|||
![]()
wrote:
And soon you will have an explanation which does not require waves travelling up and down the line to explain the observed voltages and currents of the standing 'wave'. Yes, soon you will have some mathematical shortcuts. But do mathematical shortcuts really cause photons to flow sideways between an equivalent capacitance and an equivalent inductance? Can you describe a bench experiment where photons are transferred from a capacitor to an inductor and back? -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 80,000 Newsgroups - 16 Different Servers! =----- |
#174
![]() |
|||
|
|||
![]()
Roy Lewallen wrote:
W5DXP wrote: In a nutshell, what laws of physics get repealed just as steady-state is achieved? Sorry, that's not worthy of a reply. OK, I'll answer it. No laws of physics get repealed just as steady-state is achieved. All the steady-state model does is to allow some mathematical shortcuts. (But it does not allow photons to oscillate locally between equivalent lumped circuit constants.) Some people apparently believe that those steady-state mathematical shortcuts turn around and effect reality. Causing something happen in reality by just thinking about a mental model is the domain of religion, not science. The steady-state model does NOT effect reality. Conditions on a transmission line are exactly the same whether the steady-state model is used or not. Nothing magic, like disappearing standing waves, happens at the instant steady-state is achieved. Too many engineers believe in the primacy of consciousness rather than in the primacy of existence. -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 80,000 Newsgroups - 16 Different Servers! =----- |
#175
![]() |
|||
|
|||
![]()
Ian White, G3SEK wrote:
You are using that principle of impedance substitution whenever you calibrate your antenna impedance bridge using known values of resistORS, capacitORS and inductORS. Yes, but I comprehend what I am doing. For you to imply the "electrical properties don't change" between a 50 ohm dummy load and a 50 ohm dipole antenna is simply ridiculous. That whole principle relies on the fact that, at the same frequency and in the steady state, the "definition of impedance" in terms of its electrical properties does *not* change. That's the whole point. The electrical properties *can* change and that's the whole point. The electrical properties of a 50+j0 dummy load and a 50+j0 antenna are almost completely different. A transmission line can transfer photons. Can a lumped constant L-C model transfer photons? -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 80,000 Newsgroups - 16 Different Servers! =----- |
#176
![]() |
|||
|
|||
![]()
Ian, G3SEK wrote:
"A related topic would be the effect of tank circuit Q on bandwidth of HF amplifiers;" Class A amplifiers are little used as HF finals, so in practical amplifiers current is only part-time. Impedance of a parallel resonant circuit is high. Circuit impedance rises with inductance. Q rises with capacitance. A Class C plate tank introduces a load on tube or transistor. It should waste only a small percentage of the power generated. It should have enough Q to linearize the output of the amplifier. Terman says it is easy to show that the Class C tank circuit efficiency is: 1 - Qloaded/Qunloaded. Loaded Q is the ratio of the circulating volt-amperes to the transmitted watts. If Q is too high, bandwidth is too narrow. If Q is too low, harmonics are high. As Q is ordinarily high, the tank circuit impedance is higher than the load on the amplifier. Impedance on the Class C amplifier has little effect on the tube or transistor loading. Output impedance presented by the transmitter to the load is determined in many cases by the percentage of the time the amplifier is switched-off. Best regards, Richard Harrison, KB5WZI |
#177
![]() |
|||
|
|||
![]()
Cecil,
Try this out. For a line driven by a sin wave, there is a lumped parameter equivalent circuit with impedance R + JX for any line length and any termination. For a line exited by a pulse, this equivalent circuit is an infinite series with nuls at n/PW; there is no length of line where the line is resonant. Tam/WB2TT "W5DXP" wrote in message ... Do steady-state signals obey one set of laws of physics and pulses obey a different set of laws of physics? |
#178
![]() |
|||
|
|||
![]()
W5DXP wrote:
Ian White, G3SEK wrote: You are using that principle of impedance substitution whenever you calibrate your antenna impedance bridge using known values of resistORS, capacitORS and inductORS. Yes, but I comprehend what I am doing. For you to imply the "electrical properties don't change" between a 50 ohm dummy load and a 50 ohm dipole antenna is simply ridiculous. I didn't either say that or imply it. What's truly "ridiculous" is for you to *infer* that I did. I think I've already made my points well enough for other readers to judge, so I really am done this time. No doubt you'll have the last word, Cecil. Use it well. -- 73 from Ian G3SEK 'In Practice' columnist for RadCom (RSGB) Editor, 'The VHF/UHF DX Book' http://www.ifwtech.co.uk/g3sek |
#179
![]() |
|||
|
|||
![]()
Was Descartes an engineer??
DD, W1MCE W5DXP wrote: Roy Lewallen wrote: [SNIP] Too many engineers believe in the primacy of consciousness rather than in the primacy of existence. |
#180
![]() |
|||
|
|||
![]()
I left out the word "tank" in the sentence: Tank impedance on the Class
C amplifier has little effect on tube or transistor loading." Sorry. Sometimes I delete too much when I shuffle things on the screen, I should write it first. Best regards, Richard Harrison, KB5WZI |
Reply |
Thread Tools | Search this Thread |
Display Modes | |
|
|
![]() |
||||
Thread | Forum | |||
Conservation of Energy | Antenna |