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#1
October 17th 04, 07:30 PM
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CB gear for sale
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#2
October 17th 04, 08:41 PM
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"Bada Bing" wrote
How much drive does it require? It will easily fit in your ass if you get mopedope to give it a push. |
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#3
October 18th 04, 12:27 AM
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Bada Bing wrote:
"N8WWM" wrote in message news:1097882528.56/Y//wsOcl7ntLQduxcVQ@teranews... 32 pill mobile amp. Swings 7000 watts. $2000 firm. Be LOUD and PROUD! How much drive does it require? And, HOW BIG of a 440 Volt 3 Phase Sub-Station is required? The corona off the gutters ought to remove the need for a yard light, tho !  -- |
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#4
October 18th 04, 01:07 AM
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A typical efficiency is about 50%, possibly less at these current levels, so
figure14000W input, or 1000A at 14V? I'm going to bet that there's some significant I^2R loss in that system. Of course on the new car systems with the higher voltages, things will get a lot easier. -- KC6ETE Dave's Engineering Page, www.dvanhorn.org Microcontroller Consultant, specializing in Atmel AVR -- |
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#5
October 18th 04, 02:18 AM
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"NN7KexNOSPAMk7zfg" wrote:
Bada Bing wrote: "N8WWM" wrote in message news:1097882528.56/Y//wsOcl7ntLQduxcVQ@teranews... 32 pill mobile amp. Swings 7000 watts. $2000 firm. Be LOUD and PROUD! How much drive does it require? And, HOW BIG of a 440 Volt 3 Phase Sub-Station is required? The corona off the gutters ought to remove the need for a yard light, tho ! I'm pretty sure that's a mobile amp Doug is selling. Must take quite a bank of alternators. |
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#6
October 18th 04, 03:30 AM
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Steveo wrote:
"NN7KexNOSPAMk7zfg" wrote: Bada Bing wrote: "N8WWM" wrote in message news:1097882528.56/Y//wsOcl7ntLQduxcVQ@teranews... 32 pill mobile amp. Swings 7000 watts. $2000 firm. Be LOUD and PROUD! How much drive does it require? And, HOW BIG of a 440 Volt 3 Phase Sub-Station is required? The corona off the gutters ought to remove the need for a yard light, tho ! I'm pretty sure that's a mobile amp Doug is selling. Must take quite a bank of alternators. More like a WELDER, GENERATOR or, one hell of an extension cord! and, the antenna would need to be about 5 inches in diameter to keep from melting! |
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#7
October 18th 04, 03:53 AM
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7kW at 50 ohms isn't THAT much current.
What's the feedline connector? -- KC6ETE Dave's Engineering Page, www.dvanhorn.org Microcontroller Consultant, specializing in Atmel AVR |
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#8
October 18th 04, 03:54 AM
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"Dave VanHorn" wrote in message ... 7kW at 50 ohms isn't THAT much current. What's the feedline connector? BNC should work nicely. |
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#9
October 18th 04, 02:11 PM
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I forget the math?
P=IxE and E=IxR so P=IxIxR? 7KW=IxIx50 7000/50=IxI 140=IxI 140=me twice Damn now I've got a headache! Dave VanHorn wrote: 7kW at 50 ohms isn't THAT much current. What's the feedline connector? |
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#10
October 18th 04, 05:39 PM
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I forget the math?
P=IxE and E=IxR so P=IxIxR? 7KW=IxIx50 7000/50=IxI 140=IxI 140=me twice Damn now I've got a headache! P=I^2R so assuming a properly matched load, P/50=I^2 and I is about 12A. -- KC6ETE Dave's Engineering Page, www.dvanhorn.org Microcontroller Consultant, specializing in Atmel AVR |
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