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#11
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Uwe wrote in message ...
So a 50 resistor serves as my dummy load and a meter connected to the dummy load indicates around 10 volts RMS. If I did my homework that would indicate around 2 watt output. E squared over R, yes, two watts is about right. All this at B+ of 200v and an anode current of about 35mA (I am running the transmitter off an adjustable bench tube power supply at this point). Seven watts input, two watts output is a bit low. How are you adjusting the controls? Does all this compare with the numbers you get with your transmitter?? I will need to build a power supply for the final version and would be interested to know what you use for B+. In order to get 5 Watts I would have to crank up the B+ quite a bit. IIRC that design called for 300 or 350 volts B+, which would work out to 15 watts or so input. The output network is not optimized for 200 volts B+, and in addition the efficieny is better with more plate voltage. Actually I don't care at this point since I am still practicing for my code exam, so I can't even use the transmitter right now. What study methods are you using? How do you monitor your transmitting tone with a device like this. Several ways: 1) Connect an audio oscillator to the key so that both it and the transmitter are keyed at the same time. This can be a bit tricky because the two circuits must not interact. 2) Listen to the transmitted signal on your receiver when transmitting. This requires that you have a way of reducing the receiver gain while transmitting, but not completely silencing the receiver. What sort of receiver do you have to go with the transmitter? 73 de Jim, N2EY |
#12
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So a 50 resistor serves as my dummy load and a meter connected to
the dummy load indicates around 10 volts RMS. If I did my homework that would indicate around 2 watt output. Uwe, The 10 Vrms that your meter indicates may not be accurate at 3.5 or 7 MHZ. It is probably OK at 60 hz. What you can derive from the 10 Vrms is that the AC-1 is producing power, just not sure how much. One thing you might try is a method to remove the frequency dependency of your measurements. Use a 10:1 voltage divider (10k and a 1.11k). Run this thru a Germanium or Schottky detector diode and a .01 filter capacitor. You now have a DC voltage that is proportional to power, and relatively frequency independent. To calculate the RMS voltage across the 50 ohm load: Read the DC volts out of the detector-Vdc. Then Vrms=(Vdc*.707)*10. Example: You read 2Vdc out of the detector. Vrms=14.14 volts. Power into the 50 ohm load is then: 14.14^2/50=4 Watts. The diode drop in the dector will introduce some error at QRP levels, hopefully not too much for what you are trying to do. 73 Gary N4AST |
#13
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So a 50 resistor serves as my dummy load and a meter connected to
the dummy load indicates around 10 volts RMS. If I did my homework that would indicate around 2 watt output. Uwe, The 10 Vrms that your meter indicates may not be accurate at 3.5 or 7 MHZ. It is probably OK at 60 hz. What you can derive from the 10 Vrms is that the AC-1 is producing power, just not sure how much. One thing you might try is a method to remove the frequency dependency of your measurements. Use a 10:1 voltage divider (10k and a 1.11k). Run this thru a Germanium or Schottky detector diode and a .01 filter capacitor. You now have a DC voltage that is proportional to power, and relatively frequency independent. To calculate the RMS voltage across the 50 ohm load: Read the DC volts out of the detector-Vdc. Then Vrms=(Vdc*.707)*10. Example: You read 2Vdc out of the detector. Vrms=14.14 volts. Power into the 50 ohm load is then: 14.14^2/50=4 Watts. The diode drop in the dector will introduce some error at QRP levels, hopefully not too much for what you are trying to do. 73 Gary N4AST |
#15
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Doug, that is much more power than I had hoped to get.
I am unsure about the max. values for the 6v6, therefore I stayed low. When I increase the plate voltage to 325V my 2. grid runs about 280V and the plate current increases to about 65 mA. I don't really dare to do that without knowing the max values on that tube. I guess I could lower the 2. grid voltage by increasing the value of the resistor connectd to it. I don't know if that would lower my plate current to what you get. And yes I have a few 807's lying around, so eventually I could build something more powerful, but at this point I need to work on my code, otherwise all of this is a mute point. You are right about monitoring the CW, it spills over to my receiver and I can monitor it there, even if I run the transmitter with a dummy load. So eventually I guess I could just use an arrangement that on transmitt I would automatically shorten out my receivers antenna. Hate to use a computer chip (for example) to do it though, I will have to look for a lower tech way to accomplish this switching. regards Uwe in article , Troglodite at wrote on 3/12/04 08:36: I run my 6V6's at about 325 volts on the plate, 250 on the screen. The plate is loaded to about 40ma, which is about 13 watts input. You can push it beyond this, but there's really no point since you have to quadruple your power to gain one S unit on the receiving end. You'll get about 8 watts out which is fine. If you want something heftier, you can go to a 6L6, 807 or 6146 tube. There is a compromise with single tube transmitters though, as the power goes up they tend to chirp, that is, the frequency slides a bit as they are keyed. It's not objectionable on the 6V6 transmitters, which is why I favor this power level. I started out in 1954 with a surplus ARC-5 receiver and a simple 6V6 transmitter. With it I gained code proficiency and managed to work 28 states before my Novice licence expired. (They were only good for a year back then.) For monitoring, you can just use your receiver with the antenna disconnected, or you can construct any number of monitor devices which you will find in the ARRL handbook. You can get more sophisticated but you don't have to. There is a special satisfaction in communicating with very simple equipment. Doug Moore KB9TMY |
#16
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In article , Uwe
writes: When I increase the plate voltage to 325V my 2. grid runs about 280V and the plate current increases to about 65 mA. I don't really dare to do that without knowing the max values on that tube. I guess I could lower the 2. grid voltage by increasing the value of the resistor connectd to it. I don't know if that would lower my plate current to what you get. Uwe, How are you tuning up the transmitter? Are you adjusting the plate capacitor for minimum current? 73 de Jim, N2EY |
#17
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In article , Uwe
writes: When I increase the plate voltage to 325V my 2. grid runs about 280V and the plate current increases to about 65 mA. I don't really dare to do that without knowing the max values on that tube. I guess I could lower the 2. grid voltage by increasing the value of the resistor connectd to it. I don't know if that would lower my plate current to what you get. Uwe, How are you tuning up the transmitter? Are you adjusting the plate capacitor for minimum current? 73 de Jim, N2EY |
#18
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in article , N2EY at
PAMNO wrote on 3/13/04 15:42: In article , Uwe writes: When I increase the plate voltage to 325V my 2. grid runs about 280V and the plate current increases to about 65 mA. I don't really dare to do that without knowing the max values on that tube. I guess I could lower the 2. grid voltage by increasing the value of the resistor connectd to it. I don't know if that would lower my plate current to what you get. Uwe, How are you tuning up the transmitter? Are you adjusting the plate capacitor for minimum current? 73 de Jim, N2EY Jim, Sofar I have connected a scope to the antenna and tuned for max waveform eg. highest voltage. That is also the setting where my dummy load with bulbs is brightest. The original instructions for the AC1 explain how to tune but use expressions like 'turn the capacitor clockwise' which is useless to me when I am not using their exact part. They have an alternative way to tune by inserting a mA meter into the key lead but I do not get the little dips in current they are describing. For me it is more of a linear increase in current from the highest capacity setting (lowest current) to the setting where the cap is all open and the current is highest. The way things are the max output occurs more or less at the lowest anode current of my power supply (about 35mA at 200V B+). Why do I tune for minimum current?? 73 Uwe KB1JOW |
#19
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in article , N2EY at
PAMNO wrote on 3/13/04 15:42: In article , Uwe writes: When I increase the plate voltage to 325V my 2. grid runs about 280V and the plate current increases to about 65 mA. I don't really dare to do that without knowing the max values on that tube. I guess I could lower the 2. grid voltage by increasing the value of the resistor connectd to it. I don't know if that would lower my plate current to what you get. Uwe, How are you tuning up the transmitter? Are you adjusting the plate capacitor for minimum current? 73 de Jim, N2EY Jim, Sofar I have connected a scope to the antenna and tuned for max waveform eg. highest voltage. That is also the setting where my dummy load with bulbs is brightest. The original instructions for the AC1 explain how to tune but use expressions like 'turn the capacitor clockwise' which is useless to me when I am not using their exact part. They have an alternative way to tune by inserting a mA meter into the key lead but I do not get the little dips in current they are describing. For me it is more of a linear increase in current from the highest capacity setting (lowest current) to the setting where the cap is all open and the current is highest. The way things are the max output occurs more or less at the lowest anode current of my power supply (about 35mA at 200V B+). Why do I tune for minimum current?? 73 Uwe KB1JOW |
#20
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![]() "Uwe" wrote in message ... They have an alternative way to tune by inserting a mA meter into the key lead but I do not get the little dips in current they are describing. For me it is more of a linear increase in current from the highest capacity setting (lowest current) to the setting where the cap is all open and the current is highest. It seems as though your Plate Tuning capacitor has too little capacitance to resonate at the frequency you are using. The way things are the max output occurs more or less at the lowest anode current of my power supply (about 35mA at 200V B+). Why do I tune for minimum current?? The combination of the Plate Tuning capacitor and the inductor in the output circuit comprise a parallel-resonant tuned circuit, which has its highest impedance at resonance. Therefore, when the two are resonant, current is at its lowest point. Tuning for maximum voltage on the antenna is not guaranteed to get the plate circuit on frequency, at least not the frequency you want. On many of those older tube transmitters, there was enough range in the plate tuning capacitor that the circuit could be tuned to the second harmonic of the desired frequency. Ie, if your desired frequency was 3500 kHz, the circuit could also be tuned to 7000 kHz. Measuring antenna voltage (which many cheap rigs did, by using a "Relative Output" meter, just an rf voltmeter connected across the antenna terminal) could lead you to adjust for the wrong resonance frequency. (In the 1960s the 80-meter Novice subband was 3.7-3.75 MHz, putting the second harmonic outside of any amateur band and generating a lot of QSL cards from the FCC for unsuspecting owners of transmitters like the Knight T-60, which had only a relative output meter.) If you can find someone who has a "dip meter," you can determine whether your plate circuit can be tuned to resonance, and, if not, how far off it is. A dip meter is an oscillator with an exposed coil, and an analog meter that dips when the oscillator is positioned near a resonant circuit. You adjust the dip meter knob until its meter dips and read the frequency off the dial. The dial calibration is not great, but if you have a general-coverage receiver you can listen for the oscillator signal. I would also investigate the coupling capacitor from the tube plate to the ungrounded terminal of the plate tuning capacitor. It may have dried out and shorted. Carefully measure for dc voltage from the ungrounded terminal of the plate tuning capacitor to the chassis. There shouldn't be any. If there is, replace the capacitor. As a rule of thumb, its voltage rating should be 4x the plate voltage, capacitance about 1000-1500 pF. "PM" |
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