Len,

Thanks for your advice regarding the calculator. I found that the
various questions are constructed to be answered correctly simply by
using vector graphical methods, long division, and approximation of
inputs for fast figuring.

The Eternal Squire

wrote:
Oops, one other thing I forgot to mention:

Q = XL / XR

The Eternal Squire

Two problems.

1. It's XL / R. There's no such thing as XR, in this context anyway.
2. Q = XL / R only when the R and L are in series. The Q of a parallel
R-L is R / XL.

You can remember those by using a little thought. The Q of an inductor
is highest if it has zero series resistance or if it has infinite shunt
resistance. Conversely, if you put a very large resistor in series with
an inductor, you won't be able to distinguish the circuit from just the
resistor. So the Q will be very low. In the parallel case, a low value
of resistor will make the inductor become insignificant, trashing the Q.

Good luck with your exam!

Roy Lewallen, W7EL

I GOT IT! I GOT IT! I GOT IT!

Thanks for all your help! I just wrote the exam with a 92% pass.

The Eternal Squire

wrote:
I GOT IT! I GOT IT! I GOT IT!

Thanks for all your help! I just wrote the exam with a 92% pass.

The Eternal Squire

Way cool! See you on HF, if this storm will ever go away.

Now go for your white belt -- if we're in the same organization.

--
Mike Andrews / Michael Fenwick Barony of Namron, Ansteorra
/ Amateur Extra radio operator W5EGO
Tired old music Laurel; web*******; SCAdian since AS XI

Har Har. I actually flunked out of a Okinawan karate class when I was
16, it was taught by ex-marines. I was still a white belt after a year
because I was overweight.

The Eternal Squire