Omega One Radio is back on the air, on 13.556.00 MHz LSB, with a power
output of 100 watts.

Todd N9OGL
OMEGA ONBE RADIO
13.556.00 MHz LSB

wrote:
On Fri, 3 Nov 2006 21:43:40 +0100 (CET),
) wrote:


On 3 Nov 2006 11:13:46 -0800, N9OGL wrote:
Omega One Radio is back on the air, on 14.556.00 MHz LSB, with a power
output of 1000 watts.

Todd N9OGL
OMEGA ONBE RADIO
14.556.0 MHz LSB

it is to late. I alredy mailed you a turd.
https://kb9rqz.blogspot.com
id theft reamins a crime creep
http://kb9rqz.blogspot.com/

--
Posted via a free Usenet account from http://www.teranews.com

marqueer......stfu and get over here and work my pecker

"N9OGL" wrote in
oups.com:

Omega One Radio is back on the air, on 13.556.00 MHz LSB, with a power
output of 100 watts.

Todd N9OGL
OMEGA ONBE RADIO
13.556.00 MHz LSB


I thought that might be your ****ty music.

Welcome back.

SC

) wrote in
:


On 3 Nov 2006 11:13:46 -0800, N9OGL wrote:
Omega One Radio is back on the air, on 14.556.00 MHz LSB, with a power
output of 1000 watts.

Todd N9OGL
OMEGA ONBE RADIO
14.556.0 MHz LSB

it is to late. I alredy mailed you a turd.
https://kb9rqz.blogspot.com



ROFL.

N9OGL wrote:
Omega One Radio is back on the air, on 13.556.00 MHz LSB, with a power
output of 100 watts.

Todd N9OGL
OMEGA ONBE RADIO
13.556.00 MHz LSB

Hey Toiddie...I forwarded this to Monitoring Times for you so they
could get the story about you straight!

You can thank me later.

Steve, K4YZ

K4YZ wrote:
N9OGL wrote:
Omega One Radio is back on the air, on 13.556.00 MHz LSB, with a power
output of 100 watts.

Todd N9OGL
OMEGA ONBE RADIO
13.556.00 MHz LSB

Hey Toiddie...I forwarded this to Monitoring Times for you so they
could get the story about you straight!

You can thank me later.

Steve, K4YZ

Steve, I suggest you read Part 15, Part 15 has nothing to do with power
(in Wattage) it has to do with the field strength (maininly the
electrical field of the electromaganetic wave) you can put out 100
watts and still have the field strength as prescribed under part 15 (on
13.556 MHz it 15,848 microvolts per meter at a distance of 30 meters
(90 Feet) CB radio's which run 4 - 5 watts is 10,000 microvolts per
meter at 30 meters.....but you wouldn't know anything about that now
would you??

Todd N9OGL
OMEGA ONE RADIO
13.556.00 MHz. LSB

wrote:
On 6 Nov 2006 16:31:39 -0800, "N9OGL" wrote:


K4YZ wrote:
N9OGL wrote:
Omega One Radio is back on the air, on 13.556.00 MHz LSB, with a power
output of 100 watts.

Todd N9OGL
OMEGA ONBE RADIO
13.556.00 MHz LSB

Hey Toiddie...I forwarded this to Monitoring Times for you so they
could get the story about you straight!

You can thank me later.

Steve, K4YZ

Steve, I suggest you read Part 15, Part 15 has nothing to do with power
(in Wattage) it has to do with the field strength (maininly the
electrical field of the electromaganetic wave) you can put out 100
watts and still have the field strength as prescribed under part 15 (on
13.556 MHz it 15,848 microvolts per meter at a distance of 30 meters
(90 Feet) CB radio's which run 4 - 5 watts is 10,000 microvolts per
meter at 30 meters.....but you wouldn't know anything about that now
would you??
steve can't read unless it is morse code and even then not if it
disturbs his preconceived notions

Todd N9OGL
OMEGA ONE RADIO
13.556.00 MHz. LSB
http://kb9rqz.blogspot.com/

--
Posted via a free Usenet account from http://www.teranews.com

That's the problem with ham operators, they are use to working with
wattage, under part 15 it's a little different. I know I guy who builts
part 15 device and has done for 15 to 20 years now and he tell you the
same thing I told steve, but again hey stebie is a ham and only mess
with wattage.

Todd N9OGL
OMEGA ONE RADIO
13.556.00 MHz. LSB

On 6 Nov 2006 16:31:39 -0800, N9OGL wrote:
:
: Steve, I suggest you read Part 15, Part 15 has nothing to do with power
: (in Wattage) it has to do with the field strength (maininly the
: electrical field of the electromaganetic wave) you can put out 100
: watts and still have the field strength as prescribed under part 15 (on
: 13.556 MHz it 15,848 microvolts per meter at a distance of 30 meters
: (90 Feet) CB radio's which run 4 - 5 watts is 10,000 microvolts per
: meter at 30 meters.....but you wouldn't know anything about that now

Odd. If you take the formula for an isotropic radiator emitting P
watts and solve it for the electric field, e, you come up with
e = sqr(30*P)/r at a distance of "r" meters (see my earlier posts).

For a power of 5 watts at a distance of 30 meters, that becomes

e = sqr(30*5)/30 = 0.408 volts/meter = 408,000 microvolts/meter.

That number is 400 times larger than the value you quoted. Where in the
heck are you obtaining figures like 10,000 microvolts/meter? Have you
been consulting Woger again?

On Tue, 07 Nov 2006 21:48:10 -0500, wrote:
: On Tue, 7 Nov 2006 23:47:02 +0000 (UTC), Stagger Lee
: wrote:
:
: On 6 Nov 2006 16:31:39 -0800, N9OGL wrote:
: :
: : Steve, I suggest you read Part 15, Part 15 has nothing to do with power
: : (in Wattage) it has to do with the field strength (maininly the
: : electrical field of the electromaganetic wave) you can put out 100
: : watts and still have the field strength as prescribed under part 15 (on
: : 13.556 MHz it 15,848 microvolts per meter at a distance of 30 meters
: : (90 Feet) CB radio's which run 4 - 5 watts is 10,000 microvolts per
: : meter at 30 meters.....but you wouldn't know anything about that now
:
: Odd. If you take the formula for an isotropic radiator emitting P
: watts and solve it for the electric field, e, you come up with
: e = sqr(30*P)/r at a distance of "r" meters (see my earlier posts).
:
: what is odd is that you keep leaving the apporoate contants that
: adjust for the presence of AIR (amoug other thing

Air and vacuum have nearly identical permittivity and permeability -
the properties which control the impedance of air and of free space
and which in turn relate electric field strength to the spatial power
density. It sounds to me as though you are simply blowing smoke and
have no real understanding of what you just attempted to write.

Todd is operating illegally. No amount of bloviating can make that
fact go away. Deal with it.

On Tue, 07 Nov 2006 23:08:19 -0500, wrote:
: On Wed, 8 Nov 2006 03:28:13 +0000 (UTC), Stagger Lee
: wrote:
:
: On Tue, 07 Nov 2006 21:48:10 -0500, wrote:
: : On Tue, 7 Nov 2006 23:47:02 +0000 (UTC), Stagger Lee
: : wrote:
: :
: : On 6 Nov 2006 16:31:39 -0800, N9OGL wrote:
: : :
: : : Steve, I suggest you read Part 15, Part 15 has nothing to do with power
: : : (in Wattage) it has to do with the field strength (maininly the
: : : electrical field of the electromaganetic wave) you can put out 100
: : : watts and still have the field strength as prescribed under part 15 (on
: : : 13.556 MHz it 15,848 microvolts per meter at a distance of 30 meters
: : : (90 Feet) CB radio's which run 4 - 5 watts is 10,000 microvolts per
: : : meter at 30 meters.....but you wouldn't know anything about that now
: :
: : Odd. If you take the formula for an isotropic radiator emitting P
: : watts and solve it for the electric field, e, you come up with
: : e = sqr(30*P)/r at a distance of "r" meters (see my earlier posts).
: :
: : what is odd is that you keep leaving the apporoate contants that
: : adjust for the presence of AIR (amoug other thing
:
: Air and vacuum have nearly identical permittivity and permeability -
: the properties which control the impedance of air and of free space
: and which in turn relate electric field strength to the spatial power
: density. It sounds to me as though you are simply blowing smoke and
: have no real understanding of what you just attempted to write.
:
: you are the one without any idea idea of what you are writting
:
: you simply have NO understanding of Gausses law which deteremines
: electircal feild strength

Wrong. In the case of an electromagnetic field, Gauss' law is only
one of four equations (Maxwell's equations) that are needed to
determine the electric field strength. Since a changing magnetic
field can produce an electric field too (Faraday's law), Gauss' law is
not enough. The only time it is sufficient is in the electrostatic
case.

Fortunately, the case under discussion doesn't require the solution of
a set of partial differential equations (Maxwell's equations), because
the solution has been incorporated into the idea of the impedance of
free space. That includes the permittivity of the medium (as used by
Gauss' law) plus the permeability of the medium, and it allows one to
express the power density in space with an Ohm's law type of equation
that involves only the electric field and the impedance.

That simple equation says that 5 watts of radiated power will produce
an electric field strength which is 40 times larger than that claimed
by N9OGL. That's why I asked him if he'd been consulting with Woger
again.

Perhaps he's been consulting with you instead. You just got an "F"
in electromagnetics.


====================
God said, "div D = rho, div B = 0, curl E = -@B/@t, curl H = J + @D/@t,"
and then there was light.