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#51
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Walter Maxwell wrote:
In transmitters with tubes and a pi-network output coupling circuit there is no 'fold back' circuitry to protect the amp, because none is needed, due to the total re-reflection of the reflected power. It is only in solid-state transmitters that have no circuitry to achieve destructive and constructive interference that requires fold back to protect the output transistors. One can illustrate the destructive and constructive interference with a solid-state transmitter and no tuner. Consider the following example using S-parameter terms. 100W--50 ohm line--+--1/2WL 300 ohm line--50 ohms a1-- --a2 --b1 b2-- Since there is zero reflected power on the 50 ohm line, we know that "total destructive interference" (as described by Hecht in "Optics", 4th edition, page 388) exists toward the source at point '+'. s11 = (300-50)/(300+50) = 0.7143 = -s12 b1 = (s11)(a1) + (s12)(a2) = 0 Note that given a1, s11, and s12, we can calculate the magnitude and phase of a2 needed to make b1=0. That is the Z0-match condition. The conservation of energy principle says that, (in a transmission line with only two directions) "total constructive interference" must exist in the opposite direction to the "total destructive interference" and that they must be of equal magnitudes. That tells us what *must* happen to the energy associated with the a2 reflected wave. All of the energy incident upon point '+' from both directions, |a1|^2 + |a2|^2, is directed toward the load by the interference patterns at the Z0-match point '+'. We hams commonly refer to that condition as being 100% re-reflected. -- 73, Cecil http://www.w5dxp.com |
#52
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Cecil Moore wrote:
All of the energy incident upon point '+' from both directions, |a1|^2 + |a2|^2, is directed toward the load by the interference patterns at the Z0-match point '+'. We hams commonly refer to that condition as being 100% re-reflected. The above is true in the special case of a Z0-match. In general, |a1|^2 + |a2|^2 = |b1|^2 + |b2|^2 and since |b1|^2 = 0, the above expression is correct. *Quoting from HP Ap Note 95-1*: |a1|^2 = Power incident on the input of the network (i.e. Forward power on the 50 ohm line) |a2|^2 = Power reflected from the load (i.e. Reflected power on the 300 ohm line) |b1|^2 = Power reflected from the input port of the network (i.e. Reflected power on the 50 ohm line) |b2|^2 = Power incident on the load (i.e. Forward power on the 300 ohm line) end quote from HP Ap Note 95-1 -- 73, Cecil http://www.w5dxp.com |
#53
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Cecil Moore wrote in
: .... s11 = (300-50)/(300+50) = 0.7143 = -s12 b1 = (s11)(a1) + (s12)(a2) = 0 Cecil, I see you are back to using S parameters to disguise the fact you are using about Vf and Vr in trying to support your "power wave" explanation of what happens on the transmission line. S parameters are ratios of Vf and Vr. Owen |
#54
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Cecil Moore wrote in
et: Owen Duffy wrote: Cecil Moore wrote in EM wave energy necessarily travels at the speed of light. There is exactly the amount of EM wave energy contained in a transmission line to support the forward power and reflected power. You are not suggesting that the energy contained in a transmission line in the steady state in the general case is constant, are you? Obviously, a leading question. :-) I'm not talking about instantaneous values here. All my statements apply only to values averaged over an integer number of RF cycles in one second. This gets confusing. You are talking about "the amount of EM wave energy contained in a transmission line" and now you qualify it with "values averaged over an integer number of RF cycles in one second". Average energy over time is POWER... are you talking about power and foxing us by calling it energy. I am confused. Owen |
#55
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Cecil Moore wrote:
It was Gene who first pointed out the difference between a traveling wave and a standing wave. Now he says there is no difference. Cecil, Utter nonsense. I have never said any such thing. What I *did* say, and it is still true today, is that there is no difference between a standing wave and its *constituent* traveling wave components. It is purely a matter of mathematical convenience. There is no underlying hidden physics available from trying to look at only one of the traveling wave components. If you sort out an individual component then the standing wave is no longer there. ad hominem Your debating style is a bit rough, but it is clear from this thread that others have observed your tricks. /ad hominem 73, Gene W4SZ |
#56
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Owen Duffy wrote:
I see you are back to using S parameters to disguise the fact you are using about Vf and Vr in trying to support your "power wave" explanation of what happens on the transmission line. Others use the term "power wave", Owen, but *I DO NOT* so please stop accusing me of something of which I am not guilty. I use the term "EM RF energy wave" for the traveling waves under discussion. When anyone can prove that RF energy waves don't exist or are not associated with EM energy or don't move at the speed of light, I will retire from the argument. Good luck on that one. S parameters are ratios of Vf and Vr. Exactly! No disguise intended - it's just additional support from the well respected field of S-parameter analysis for the distributed network wave reflection model. The only difference is that the S-parameter Vf and Vr values are normalized to Z0 so when they are squared they indeed do yield watts. Your tone seems to reject the S-Parameter analysis as a valid model of reality. Any model that has to resort to rejecting the S-Parameter analysis as well as the distributed network wave reflection model is certainly suspect. Did you ever see the movie, "One Bridge Too Far"? This "reflected wave energy doesn't exist" argument reminds me of that movie. -- 73, Cecil http://www.w5dxp.com |
#57
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Owen Duffy wrote:
This gets confusing. You are talking about "the amount of EM wave energy contained in a transmission line" and now you qualify it with "values averaged over an integer number of RF cycles in one second". Average energy over time is POWER... are you talking about power and foxing us by calling it energy. I am confused. I have been convinced by Jim, AC6XG, to abandon the word "power" because of the difference in definitions between the field of physics and the field of RF engineering. Jim would argue with you and say that average energy over time is NOT necessarily POWER and is only power if actual work is done which, of course, is not done by a reflected wave. So you need to go off and argue with Jim over the definition of "power". Instead of talking about power, Jim has convinced me to talk about watts or joules/sec which he says are not necessarily power. The confusion comes from the field of physics, not from me. While you are talking to Jim, get him to explain the definition of "transfer". -- 73, Cecil http://www.w5dxp.com |
#58
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Cecil Moore wrote in
: Your tone seems to reject the S-Parameter analysis as a valid model of reality. Any model that has to Not at all. S parameters are Vf and Vr based and when properly applied will produce exactly the same analysis outcome. It is the application of S parameters in the "power flow analysis" that is a reach, it might be convenient, but it does not legitmise the argument that forward and reflected "power waves" exist separately. A quote from HP (which you seem to respect): ===quote Notice that the square of the magnitude of these new variables has the dimension of power. |a1|^2 can then be thought of as the incident power on port one; |b1|^2 as power reflected from port one. These new waves can be called traveling power waves rather than traveling voltage waves. Throughout this seminar, we will simply refer to these waves as traveling waves. ===equote There is a difference between "can then be thought of as..." and "are...". Owen |
#59
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Gene Fuller wrote:
Utter nonsense. I have never said any such thing. Yes, you did, in the part that you deleted. Here it is again: Gene Fuller, W4SZ wrote: In a standing wave antenna problem, such as the one you describe, there is no remaining phase information. Any specific phase characteristics of the traveling waves died out when the startup transients died out. Phase is gone. Kaput. Vanished. Cannot be recovered. Never to be seen again. What I *did* say, and it is still true today, is that there is no difference between a standing wave and its *constituent* traveling wave components. The constituent traveling wave components possess changing phase. The standing wave doesn't possess changing phase. You are contradicting yourself. -- 73, Cecil http://www.w5dxp.com |
#60
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Gene, W4SZ wrote:
"No need to account for any mythical power in the reflected waves." My dictionary defines reflected power as: "The power flowing back to the generator from the load." Maximum power theorem is defined as: "The maximum power will be absorbed by one network from another joined to it at two terminals, when the impedance of the receiving network is varied, if the impedances (looking into the two networks at the junction) are conjugates of each other." Clearly a generator (transmitter) connected to a load through a lossless line sees Zo of the line as its load until the instant that reflected power returns to the generator from the load. Suppose the round-trip delay of the line makes the reflected voltage exactly in phase with the transmitter output. further suppose the reflection was total so that the reflected voltage exactly equals the transmitter output. In this special case, we might as well be connecting identical battery cells in parallel. No current is going to flow. The generator is seeing infinite impedance. What is the generator load that extracts maximum power from a transmitter? A conjugately matched load, of course. To determine the impedance of a transmitter, one only needs to find the load which extracts maximum power. The transmitter impedance is its conjugate. Best regards, Richard Harrison, KB5WZI |
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