Home |
Search |
Today's Posts |
#1
![]() |
|||
|
|||
![]()
All,
This question is: How can the ground system for a vertical be improved? The RF ground calculates to about 52 Ohms. It consists of 16 radials varying in length from 24 to 45 feet. Four are buried and 12 are on ground. The location is the Pacific Northwest part way up a hillside. The surface is grass, the subsurface is clay. The value varies a little with rain, it has measured as low as 46 to 48 Ohms. Just as additional information, the antenna is a loaded vertical, overall about 4 meters. The coil is about 35% from the base. The antenna is raised about 1 meter. I am aware the configuration is not optimum and a top hat would help, those changes will be made independently. Several articles indicate this radial system should yield well under 20 Ohms, some estimates are under 8 Ohms. At this point my first target is under 20 Ohms. Little that I do seems to affect it. My question is: What am I missing? The problem is the value does not appear to change very much. I started with 4 radials and have been adding them periodically. Those changes do not seem to have a measurable effect. (However I must admit that earlier numbers not as good as the current measurement. I believe the current measurements are better then 10%.) Thanks - Dan |
#2
![]() |
|||
|
|||
![]()
dansawyeror wrote in
: Dan, You refer to calculation of ground resistance and later to measurements. It would help if you explained what you measured, the frequency of measurement, and how you measured it, then how you calculated your results. Perhaps the regimen of that might help you to an answer. Owen All, This question is: How can the ground system for a vertical be improved? The RF ground calculates to about 52 Ohms. It consists of 16 radials varying in length from 24 to 45 feet. Four are buried and 12 are on ground. The location is the Pacific Northwest part way up a hillside. The surface is grass, the subsurface is clay. The value varies a little with rain, it has measured as low as 46 to 48 Ohms. Just as additional information, the antenna is a loaded vertical, overall about 4 meters. The coil is about 35% from the base. The antenna is raised about 1 meter. I am aware the configuration is not optimum and a top hat would help, those changes will be made independently. Several articles indicate this radial system should yield well under 20 Ohms, some estimates are under 8 Ohms. At this point my first target is under 20 Ohms. Little that I do seems to affect it. My question is: What am I missing? The problem is the value does not appear to change very much. I started with 4 radials and have been adding them periodically. Those changes do not seem to have a measurable effect. (However I must admit that earlier numbers not as good as the current measurement. I believe the current measurements are better then 10%.) Thanks - Dan |
#3
![]() |
|||
|
|||
![]()
Owen,
I did not want to concentrate on that; however it is a fair question. The frequency is 3970 kc and the methodology is based on use of an hp network analyzer. The analyzer has both polar and Cartesian displays. The outputs were cross checked.f The feed line was calibrated using a 25 Ohm termination to 180 degrees. The return measured about -9.4db (close to what is predicted with line loss). This was checked against an open circuit confirmed the calibration by a reading 1 degree and 1db. (very close to what is predicted) For the actual measurement the return loss was measured at just over -26db at 0 degrees. (no feed-point network) Three models were used to calculate the input resistance of the antenna. They all predicted an antenna resistance of about 3 to 4 Ohms. (the suggested input network is 120 pf) To focus on the question is: Why is the ground resistance so high? It is not important at this stage to determine its precise value. The point is it is high enough to cause a return of 0 degrees. This puts the 'system' at over 50 degrees. Even if the antenna were 6 to 8 Ohms the ground loss would be at least 42 to 44 Ohms. - Dan Owen Duffy wrote: dansawyeror wrote in : Dan, You refer to calculation of ground resistance and later to measurements. It would help if you explained what you measured, the frequency of measurement, and how you measured it, then how you calculated your results. Perhaps the regimen of that might help you to an answer. Owen All, This question is: How can the ground system for a vertical be improved? The RF ground calculates to about 52 Ohms. It consists of 16 radials varying in length from 24 to 45 feet. Four are buried and 12 are on ground. The location is the Pacific Northwest part way up a hillside. The surface is grass, the subsurface is clay. The value varies a little with rain, it has measured as low as 46 to 48 Ohms. Just as additional information, the antenna is a loaded vertical, overall about 4 meters. The coil is about 35% from the base. The antenna is raised about 1 meter. I am aware the configuration is not optimum and a top hat would help, those changes will be made independently. Several articles indicate this radial system should yield well under 20 Ohms, some estimates are under 8 Ohms. At this point my first target is under 20 Ohms. Little that I do seems to affect it. My question is: What am I missing? The problem is the value does not appear to change very much. I started with 4 radials and have been adding them periodically. Those changes do not seem to have a measurable effect. (However I must admit that earlier numbers not as good as the current measurement. I believe the current measurements are better then 10%.) Thanks - Dan |
#4
![]() |
|||
|
|||
![]()
dansawyeror wrote in
: .... I think a summary is that at 3970KHz, the feedpoint Z looks like about 45 +j0 and you reckon the radiation resistance should be around 4+j0, suggesting the earth system contributes around 40 ohms of resistance. Observations at a single frequency provide a limited view of what might be happening. Elevated radials should exhibit a clear resonance, and will offer the lowest impedance at resonance. Buried radials will not exhibit such a clear resonance in lossy soil, and using your wire to form more short radials might give better performance than few longer radials. Radials lying on the ground are likely to be somewhere in between. You may observe resonance, and in that case the ground system impedance will be optimised by "tuning" those radials (which will probably be a good bit shorter than formula length for free space radials). Owen |
#5
![]() |
|||
|
|||
![]()
On Sun, 08 Apr 2007 20:20:36 -0700, dansawyeror
wrote: To focus on the question is: Why is the ground resistance so high? Hi Dan, Focus on Why? Why? This is something that you have absolutely no control over without a huge investment in new dirt several 10s of meter deep out to at least as far as the antenna is tall. You want less resistance? then dig a hole and fill it with quartz sand. Build a dune to drive the loss down further. A suitable substitute is to lay out a ground field (radial wires). The more the better. Here is the Why? you should be asking (Why more wires?). The path through the earth is shortened between adjacent ground wires. Less path, less loss. The earth current travels not IN toward the center as the radials do. The earth current travels ACROSS or circumferentially towards the radial wires. This is due to the phase lag between the induced earth current and the radial current. The greater the distance between radials, the more path loss from the average distance between the radials, to the radials. As this is very difficult to treat in words alone, it is undoubtedly confusing in the description above. 73's Richard Clark, KB7QHC |
#6
![]() |
|||
|
|||
![]()
Richard Clark wrote:
The path through the earth is shortened between adjacent ground wires. Less path, less loss. The earth current travels not IN toward the center as the radials do. The earth current travels ACROSS or circumferentially towards the radial wires. This is due to the phase lag between the induced earth current and the radial current. The greater the distance between radials, the more path loss from the average distance between the radials, to the radials. As this is very difficult to treat in words alone, it is undoubtedly confusing in the description above. Indeed it is. Can you point me to a reference where I can get a more detailed explanation of this circumferential current and its cause? Roy Lewallen, W7EL |
#7
![]() |
|||
|
|||
![]()
To focus on the question is: Why is the ground resistance so high? It
is not important at this stage to determine its precise value. The point is it is high enough to cause a return of 0 degrees. This puts the 'system' at over 50 degrees. Even if the antenna were 6 to 8 Ohms the ground loss would be at least 42 to 44 Ohms. Simple answer- add more radials. Especially if the impedance is varying noticeably depending on ground moisture, you need more radials. Another possibility is that if there is some other conductor in the near field (tower, house, other wires, etc), the impedance might not be what you expect. Tor N4OGW |
#8
![]() |
|||
|
|||
![]() Well, I can't explain why lagging or leading current and voltage would change the physical direction of propagation of the EM wave front through the ground... But I do know that Dan does not have enough radials.. He needs at least another 16 and better yet would be in the range of 50 total... denny / k8do |
#9
![]() |
|||
|
|||
![]()
On Sun, 08 Apr 2007 20:20:36 -0700, dansawyeror wrote:
Owen, I did not want to concentrate on that; however it is a fair question. The frequency is 3970 kc and the methodology is based on use of an hp network analyzer. The analyzer has both polar and Cartesian displays. The outputs were cross checked.f [snip] To focus on the question is: Why is the ground resistance so high? It is not important at this stage to determine its precise value. The point is it is high enough to cause a return of 0 degrees. This puts the 'system' at over 50 degrees. Even if the antenna were 6 to 8 Ohms the ground loss would be at least 42 to 44 Ohms. How is the antenna loaded and what is the Q of the loading coil? Coil losses are almost certainly 5 ohms and could easily be as high as 35 ohms. bart |
#10
![]() |
|||
|
|||
![]()
Richard,
What coupling does this imply? Is it direct as is contact or is it a field coupling as capacitive or inductive? The question is: what would insulation or corrosion due to buried radials? - Dan Richard Clark wrote: On Sun, 08 Apr 2007 20:20:36 -0700, dansawyeror wrote: To focus on the question is: Why is the ground resistance so high? Hi Dan, Focus on Why? Why? This is something that you have absolutely no control over without a huge investment in new dirt several 10s of meter deep out to at least as far as the antenna is tall. You want less resistance? then dig a hole and fill it with quartz sand. Build a dune to drive the loss down further. A suitable substitute is to lay out a ground field (radial wires). The more the better. Here is the Why? you should be asking (Why more wires?). The path through the earth is shortened between adjacent ground wires. Less path, less loss. The earth current travels not IN toward the center as the radials do. The earth current travels ACROSS or circumferentially towards the radial wires. This is due to the phase lag between the induced earth current and the radial current. The greater the distance between radials, the more path loss from the average distance between the radials, to the radials. As this is very difficult to treat in words alone, it is undoubtedly confusing in the description above. 73's Richard Clark, KB7QHC |
Reply |
Thread Tools | Search this Thread |
Display Modes | |
|
|
![]() |
||||
Thread | Forum | |||
Choke Resistance | Boatanchors | |||
CALCULATION OF EARTH RESISTANCE IN MULTI-LAYER EARTH STRUCTURE | Antenna | |||
CALCULATION OF EARTH RESISTANCE IN MULTI-LAYER EARTH STRUCTURE | Equipment | |||
Internal Resistance (?) | Antenna | |||
Resistance Checking | Boatanchors |