On Fri, 14 Dec 2007 15:38:25 GMT, Cecil Moore
wrote:

As I said above, if you have a constant power source,
the energy in that stub would increase without bounds.
The forward power is certainly not limited to the source
power. The source is only having to supply the losses in
the stub. The stub could be storing magnitudes more energy
than your calculation.

The world's answer for energy shortage. Put in 100W and get 10 times
or more out. All courtesy of the modern miracle of superconduction
which is available TODAY!

But wait. That is not all. For the first 4 billion customers:

As pointed out above, your logic is flawed. I estimate
that with 100 watts being fed into the dipole and 100
watts being radiated from the dipole, the forward power
is about 500 watts and the reflected power is about
400 watts at the feedpoint of the 1/2WL dipole.

Our Soon-to-be-announced FORWARD WAVE DIPOLE will be arriving under
your Christmas tree in the future. Imagine applying only 100W to
enjoy the benefits of radiating 500W without the need for those
roasting hot linears that cost a fortune.

As a Bonus! Plug your rig into our patent pending energy stub that
requires less than 10W to power your rig, and here's a Christmas gift
you can take to the mountains in your backpack!

When was the last time your rig could radiate 500W for an hour from 10
AAA batteries? Better living through the bright promise of photons.
Look for our trademarked slogan:
"It's more than headlights in your eyes, dear."

73's
Richard Clark, KB7QHC

Richard Clark wrote:
The world's answer for energy shortage. Put in 100W and get 10 times
or more out.

Why is that surprising? Put in 100 watts into a
battery bank for 10 hours and get 1000 watts out
for an hour. How does that answer the energy
shortage? Do you think it is a violation of the
conservation of energy principle for the charging
cycle to be longer than the discharge cycle?

If you run your transceiver on a previously charged
battery, the steady-state power output of the battery
is an *infinite* number of times the steady-state
power input to the battery. Why do you think that's
strange?

The standing-wave energy is stored in the stub all
during steady-state. That stored energy is only
available to be output *after* steady-state. When the
power input to the standing-wave antenna is removed,
the power output from the standing wave is infinitely
greater than the input power for a few nanoseconds.

After the charging energy is removed from a capacitor,
the stored energy is still available. Why do you
think that is strange?
--
73, Cecil http://www.w5dxp.com