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#91
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Roy Lewallen wrote:
I've always regarded a "standing wave" as being a description of the envelope caused by the interference between forward and reverse traveling waves. If you have "Fields and Waves ..." by Ramo and Whinnery, take a look at the equation for standing wave voltage and current on page 285 of the 2nd edition. Ex = E*e^j(wt-Bz) + E'*e^j(wt+Bz) Roy, that is NOT the equation for an envelope. -- 73, Cecil http://www.w5dxp.com |
#92
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Cecil Moore wrote:
Roy Lewallen wrote: I've always regarded a "standing wave" as being a description of the envelope caused by the interference between forward and reverse traveling waves. If you have "Fields and Waves ..." by Ramo and Whinnery, take a look at the equation for standing wave voltage and current on page 285 of the 2nd edition. Ex = E*e^j(wt-Bz) + E'*e^j(wt+Bz) Roy, that is NOT the equation for an envelope. It's too bad you don't have the foggiest notion as to just what it is the equation of. Much of the thousands of posts could have been avoided if that were the case. 73, Tom Donaly, KA6RUH |
#93
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Owen Duffy wrote:
Walter Maxwell wrote: It appears to me that even with all the successive posts on the subject of power in the standing wave, you all seem to be missing the ingredient that proves why there is no useable power in the standing wave. It is because the current and voltage in the standing wave are 90° out of phase. Multiplying E x I under this condition results in zero power. I am trying to make sense of this and the first issue is what you mean by the term "standing wave". Walt is right. Let's look at an arbitrary example of forward and reflected voltage and current instantaneous phasors at one point on a particular line. Vfor = 100v at 45 degrees, Ifor = 2 amps at 45 degrees The forward voltage and forward current are in phase. Vref = 100v at -45 degrees, Iref = 2 amps at 135 degrees The reflected voltage and reflected current are 180 degrees out of phase. Now calculate the total voltage and total current. Total voltage = 2*100cos(45) = 141.4v at 0 deg Total current = 2*2sin(45) = 2.83a at 90 deg For a pure standing wave, the instantaneous voltage is *always* 90 degrees out of phase with the instantaneous current. There are no V*I*cos(A) watts in a pure standing wave. There are only V*I*sin(A) VARS. However, the VARS in the standing wave require energy which can be converted to watts by I^2*R losses. -- 73, Cecil http://www.w5dxp.com |
#94
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Tom Donaly wrote:
Cecil Moore wrote: Roy Lewallen wrote: I've always regarded a "standing wave" as being a description of the envelope caused by the interference between forward and reverse traveling waves. If you have "Fields and Waves ..." by Ramo and Whinnery, take a look at the equation for standing wave voltage and current on page 285 of the 2nd edition. Ex = E*e^j(wt-Bz) + E'*e^j(wt+Bz) Roy, that is NOT the equation for an envelope. It's too bad you don't have the foggiest notion as to just what it is the equation of. Much of the thousands of posts could have been avoided if that were the case. The technical content of your posting is noted. Here is what it is the equation of: http://www.chemmybear.com/standing.html -- 73, Cecil http://www.w5dxp.com |
#95
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I'm surprised that standing waves seem so hard for people to understand.
They're simply a spatial pattern formed by the interference between forward and reflected waves or, if you prefer, from the solution to a general transmission line problem with boundary values applied. I'd hope that even a brief look at a text would make it clear what standing waves are, and what they are not. Roy Lewallen, W7EL |
#96
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Cecil Moore wrote:
... I guess the authors of the textbooks never thought anyone would be so ignorant as to believe that EM waves can stand still. :-) EM waves are photonic in nature must travel at the speed of light in the medium. A standing wave stands still and oscillates in place. Therefore, A standing wave is not an EM wave - It is something else, by definition. Guess if you told me we were all communicating on "entangled antennas" (and, yes, a 1:1 relationship to entangled particles)--I'd have to, at least, give it a thought! ROFLOL! Merry Xmas OM, and warm regards, JS ;-) |
#97
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Dave Heil wrote:
... Inside the microwave oven, the microwaves bounce off the metal internal walls and set up complex 'standing wave' patterns. As with any wave, microwaves have peaks and troughs and the intensity of the microwaves is greatest in the peaks and troughs and lowest at points in between. ... Actually, a bit more than that, even ... Water molecules are slightly magnetic, they are spinning like hell on those "humps of the standing wave"--friction cooking, you will excuse my "artistic authors' license" ... or not, in ALL of this ... ;-) However, the standing wave is much more appreciated, by me--at this point, thanks to Cecil. And, my attention is always drawn towards "little oddities" which can serve as diversion. And, the standing wave IS cooking the turkey--in my humble opinion ... you could say, "I believe in standing waves." But then, tomorrow night, I'll be up very late with cookies and milk. Yanno, I've never seen 'em--yet? ;-) Regards, JS |
#98
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John Smith wrote:
Dave Heil wrote: [...] forgot ... Merry Xmas Heil, JS |
#99
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Roy Lewallen, W7EL wrote:
"As any text can tell you, the value of Z (ratio of V to I) varies along a line which has a reflected waves (i.e., has a standing wave)." Not exactly, maybe the apparent Z. Uniform line is assumed and it has a Zo determined only by line structure. Zo is identical for a signal traveling in either direction. However, a directional coupler must be used to measure voltage and current traveling in one direction while ignoring voltage and current traveling in the opposite direction. A Bird wattmeter uses a directional coupler. Voltage to current ratio on a line with reflections and standing waves is of little practical value except for determinimg whether the capacity of the line is exceeded or nearly so. I would argue that a microwave oven uses the real power delivered to its contents and not the standing wave as an article attached to another poster`s comments stated. Best regards, Richard Harrison, KB5WZI |
#100
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Richard Harrison wrote:
... I would argue that a microwave oven uses the real power delivered to its contents and not the standing wave as an article attached to another poster`s comments stated. Best regards, Richard Harrison, KB5WZI Nice thing about microwave ovens? They can be filled with a material and the standing waves seen visually, no math needed ... rather handy, really! Regards, Merry Xmas, and to all a goodnight, JS |
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