Here's a request for anyone capable of performing the
necessary math to verify (or disprove) my figures below:

Shortened Stub Example:

rho = |0.7143|
--43.4 deg 600 ohm line--+--10 deg 100 ohm line--open
Vfor1--|--Vfor2 Vi--|
Vref1--|--Vref2 Vr--|

Assume the RMS voltage, Vi, incident upon the open end
of the stub is: Vi = 100 volts at 0 degrees.

At point '+' 10 degrees back from the open,
Vfor2 = 100 volts at -10 degrees
Vref2 = 100 volts at +10 degrees

Vfor1 = 143.33 volts at -46.6 degrees
Vref1 = 143.33 volts at +46.6 degrees

The phase shift between Vfor1 and Vfor2 is 36.6 degrees.

The phase shift between Vref2 and Vref1 is 36.6 degrees.

Vfor1 + Vref1 = Vfor2 + Vref2 at point '+'
--
73, Cecil http://www.w5dxp.com