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#1
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I typically do not like to "Xerox" material to support my arguments, but
I will make an exception in this case. Very recently RRAA's very own "John Smith" included the following comment in a message. "I think Cecil has done an excellent job, if you have followed him (and, I cannot claim I have COMPLETELY done so), however, he has shown there ARE holes in what we 'believe.' And, some things don't quite 'mate-up' and what we have taken for granted looks differently when under the 'microscope.' 'Standing Waves' is but the shining example." Considering the source of that comment, I am not surprised. But for any others who might have been hoodwinked by the nonsense, I will try to add a bit of color. As some may recall BG, there has been a bit of an ongoing discussion about the nature of energy flow, or lack thereof, in standing waves. In order to support his point about using phasors interchangeably with field vectors, Cecil copied and posted a figure on his website under the page name of "EHWave.jpg". This figure was referenced as an extract from a book by Haznadar and Stih entitled "Electronic Fields, Waves, and Numerical Methods." The figure itself completely misses the point, since it is simply a representation of an ordinary circularly polarized wave. The topic of polarization is not particularly relevant here. It merely complicates the arithmetic, and it adds nothing to the science of Poynting vectors or standing waves. It is, however, interesting to note that the figure caption in the original source is given quite clearly. On page 241, the page containing Cecil's copied jpeg, it says, "Figure 8.3.2 Propagation of a circularly polarized pure direct (in the +z direction) travelling wave with phase velocity vf = c." Whether Cecil did not see this caption, did not understand it, or was again trying to pull a fast one remains unknown. It matters not in any case. I must give great credit to Cecil's hidden research team for finding this reference. It seems quite obscure. However, Cecil's groupies appear to have neglected to turn a few pages to arrive at page 244. On this page there is a discussion of the Poynting vector for standing waves. An exact quote, or at least as close as possible in ASCII, is, *********** "In a real domain, the instantaneous value of Poynting's vector for a pure standing wave is, according to (8.3.26a,b), NRe = (ax ExRe x ay HyRe) = -az 1/4 (Eo^2)/Z' sin^2 (2 pi z/lambda) sin (2wt) (8.3.28b) Using this expression, we see that the time-averaged value of Poynting's vector in a real domain is equal to zero since the time-averaged value of the function sin (2wt) is always equal to zero." *********** The equation is slightly cleaner when the "Re" subscripts are removed. N = (ax Ex X ay Hy) = -az 1/4 (Eo^2)/Z' sin^2 (2 pi z/lambda) sin (2wt) (8.3.28b) What is immediately observed is that the Poynting vector for an ordinary standing wave is zero only for specific locations or for specific times. At other locations and times the Poynting vector is non-zero. Only the time or space *average* is zero. This is of course exactly what I and some others have been saying. This is exactly what the traditional science says. The colloquial expression is that the energy sloshes back and forth. This equation is easily derived from the standard representation of a standing wave, but it is *so* much more authoritative when Xeroxed from Cecil's own reference book. The iconoclasts never give up. The 200 mpg carburetor lives on. 73, Gene W4SZ |
#2
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Gene Fuller wrote:
"Figure 8.3.2 Propagation of a circularly polarized pure direct (in the +z direction) travelling wave with phase velocity vf = c." Whether Cecil did not see this caption, did not understand it, or was again trying to pull a fast one remains unknown. It matters not in any case. If I was trying to pull a fast one, I wouldn't have posted the reference along with the graphic. The phasors associated with a traveling wave rotate in opposite directions for forward and reflected traveling waves, i.e. in their exponential notations, they are indeed polarized. If the forward and reflected waves didn't rotate in opposite directions, the standing waves wouldn't stand. That graph is a reasonable graph of a uniform plane wave in exponential notation. My graph of the superposition of forward wave phasors and reflected wave phasors still stands at: http://www.w5dxp.com/EHSuper.JPG The Re part of those phasors (the fields) are 180 degrees out of phase. Quoting "Optics" by Hecht, concerning a traveling wave: "... a phasor rotating counterclockwise at a rate omega is equivalent to a wave traveling to the left (decreasing x), and similarly, one rotating clockwise corresponds to a wave traveling to the right (increasing x)." The graphic I posted is a reasonable representation of a traveling wave illustrated in exponential form. The fields of a circularly polarized waves are virtually identical to the phasors of a uniform plane traveling wave. You can observe the rotation of a traveling wave by downloading http://www.w5dxp.com/rhombicT.EZ and turning on the current phase option. What is immediately observed is that the Poynting vector for an ordinary standing wave is zero only for specific locations or for specific times. At other locations and times the Poynting vector is non-zero. Only the time or space *average* is zero. Which is exactly what I have been saying. The instantaneous Poynting vector is of limited usefulness. The time-averaged Poynting vector is the one that is useful and the one I have been talking about, as I stated a couple of times previously. Every time I have used the words, "Poynting vector", I have been referring to the average Poynting vector. As you know, I have been using the word "net" as in, "there is no net energy flow in a standing wave". We both agree that in a traveling wave the voltage and current are in phase for forward waves and 180 degrees out of phase for reflected waves. The E-field and H-field are 90 degrees apart in both traveling wave cases. A traveling wave is an example of a uniform plane wave. The technical fact that the voltage and current in a pure standing wave are 90 degrees out of phase proves that the standing wave is NOT a uniform plane wave. In fact, in an earlier posting, a standing wave failed all 7 properties of a uniform plane wave. V*I*cos(A) = average Poynting vector = 0 for a standing wave. -- 73, Cecil http://www.w5dxp.com |
#3
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On Mon, 21 Jan 2008 15:11:09 GMT, Gene Fuller
wrote: it is *so* much more authoritative when Xeroxed from Cecil's own reference book. Indeed, Gene, Simply drilling into Cecil's corrupted Xerography always finds the decay of his logic. 73's Richard Clark, KB7QHC |
#4
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Richard Clark wrote:
Simply drilling into Cecil's corrupted Xerography always finds the decay of his logic. Richard, I admit that I am not perfect nor omniscient. Will you admit that about yourself? -- 73, Cecil http://www.w5dxp.com |
#5
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Gene Fuller wrote:
... The iconoclasts never give up. The 200 mpg carburetor lives on. 73, Gene W4SZ Actually, you are quite correct ... As a boy, I had a moped, it did get mighty close to 200mpg. Depending on how you "drove" it (peddled it?), it could be pushed to better performance than that! Absolute proof the 200 mpg carburetor does exist! ROFLOL Regards, JS |
#6
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On Mon, 21 Jan 2008 18:12:00 -0600, Cecil Moore
wrote: Richard Clark wrote: Simply drilling into Cecil's corrupted Xerography always finds the decay of his logic. Richard, I admit that I am not perfect nor omniscient. Will you admit that about yourself? Hmm, I've been called a gay-wad, liar, a sailor, stupid, a cheat, a vile lover of Shakespeare by any number of correspondents here (including you) - your fawning need for sentimental admissions that celebrities love to gush would be a pale shade of mauve in comparison. Feel free to spit on me again at your convenience. ;-) Wearing my Nor'wester in this wet climate since 1995, 73's Richard Clark, KB7QHC |
#7
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Richard Clark wrote:
Hmm, I've been called a gay-wad, liar, a sailor, stupid, a cheat, a vile lover of Shakespeare by any number of correspondents here (including you) Sorry, that's a false statement. I have never called you a gay-wad, a sailor, or a vile lover of Shakespeare. :-) - your fawning need for sentimental admissions that celebrities love to gush would be a pale shade of mauve in comparison. So the answer to my question is "no", you are unwilling to admit that you are not perfect nor omniscient. :-) -- 73, Cecil http://www.w5dxp.com |
#8
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Gene Fuller wrote:
In order to support his point about using phasors interchangeably with field vectors, Cecil copied and posted a figure on his website under the page name of "EHWave.jpg". For the record, I have not used field vectors at all during this discussion. Everything I have ever posted have used phasors. From the IEEE Dictionary, "E and H are the electric and magnetic field vectors in phasor notation". That is what I have been doing all along. From "Optics" by Hecht: "Therefore, its instantaneous value [for the Poynting vector] would be an impractical quantity to measure directly. This suggests that we employ an averaging procedure." Virtually every time I have used the term, "Poynting vector", I have been talking about the average value, not the instantaneous value. EHWave.JPG is a good representation of an EM traveling wave in phasor notation. If we project the fields onto the real axis, we obtain the conventional representation. -- 73, Cecil http://www.w5dxp.com |
#9
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Cecil Moore wrote:
Gene Fuller wrote: In order to support his point about using phasors interchangeably with field vectors, Cecil copied and posted a figure on his website under the page name of "EHWave.jpg". For the record, I have not used field vectors at all during this discussion. Everything I have ever posted have used phasors. From the IEEE Dictionary, "E and H are the electric and magnetic field vectors in phasor notation". That is what I have been doing all along. The "notation" is not the most important part. "Phasor notation" is simply a means expressing the phase in terms of complex numbers. The vector *direction* is all-important. That is the essential "vector" part of the Poynting analysis. The vector *direction* is not addressed at all by the phase or by phasor notation. Depending on the exact notation, the vector "magnitude" may be described by phasor notation. If one is going to correctly perform Poynting analysis, it is necessary to consider field vectors. There is no alternative. From "Optics" by Hecht: "Therefore, its instantaneous value [for the Poynting vector] would be an impractical quantity to measure directly. This suggests that we employ an averaging procedure." Virtually every time I have used the term, "Poynting vector", I have been talking about the average value, not the instantaneous value. Most of this discussion has been based upon a disagreement between your insistence that the instantaneous Poynting vector for a standing wave is always zero at all times and places, compared to my insistence that it is not zero at all times and places. I have no disagreement with Hecht. EHWave.JPG is a good representation of an EM traveling wave in phasor notation. If we project the fields onto the real axis, we obtain the conventional representation. The representation in EHWave.jpg is already shown in real axes. There is no projection needed. The whole point of that figure is to show a circularly polarized wave. The vector direction does indeed rotate around the propagation axis exactly as shown. The observed rotation angles around the propagation axis have nothing to do with phasors; they are real physical angles of the E-field and H-field. 73, Gene W4SZ |
#10
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Gene Fuller wrote:
Cecil Moore wrote: For the record, I have not used field vectors at all during this discussion. Everything I have ever posted have used phasors. From the IEEE Dictionary, "E and H are the electric and magnetic field vectors in phasor notation". That is what I have been doing all along. The "notation" is not the most important part. "Phasor notation" is simply a means expressing the phase in terms of complex numbers. The vector *direction* is all-important. That is the essential "vector" part of the Poynting analysis. The vector *direction* is not addressed at all by the phase or by phasor notation. Depending on the exact notation, the vector "magnitude" may be described by phasor notation. If one is going to correctly perform Poynting analysis, it is necessary to consider field vectors. There is no alternative. You apparently did not bother to read the IEEE Dictionary definition above. Please do it and while you are at it, would you please explain what the "complex conjugate" means when one is not dealing with phasors? Exactly what is the complex conjugate of a vector in free x,y,z space? For instance, what is the complex conjugate of a vector running from 0,0,0 to 1,2,3? From "Optics" by Hecht: "Therefore, its instantaneous value [for the Poynting vector] would be an impractical quantity to measure directly. This suggests that we employ an averaging procedure." Virtually every time I have used the term, "Poynting vector", I have been talking about the average value, not the instantaneous value. Most of this discussion has been based upon a disagreement between your insistence that the instantaneous Poynting vector for a standing wave is always zero at all times and places, compared to my insistence that it is not zero at all times and places. Either I misspoke or else you misunderstood. Phasor magnitudes are usually RMS values, i.e. average values. If I ever said anything about the instantaneous Poynting vector, it was a mistake. Every time I said "Poynting vector", I was referring to the average Poynting vector. I tend to agree with Hecht - the instantaneous Poynting vector is impractical to work with. I always deal with phasors and averages. When I realized that Keith was talking about instantaneous values, I backed out of the discussion. I do not agree or disagree with anyone about instantaneous values. I just think they are of very limited usefulness in this discussion. It is the average values that are important here. So I repeat: The average energy flow in a standing wave is zero so the average Poynting vector for a standing wave is zero. That was the only point I was trying to make. V*I*cos(A) are RMS phasors. -- 73, Cecil http://www.w5dxp.com |
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