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#31
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![]() "K7ITM" wrote in message ... On Oct 22, 9:52 pm, "John KD5YI" wrote: "Richard Harrison" wrote in message ... Mike, N3LI wrote: "Why would the velocity be less at increased (antenna element) width?" Let B = the phase velocity on the antenna element, in radians per unit length. 2pi/B = wavelength on the element. Therefore, 2pi/B=velocity of phase propagation. Due to the behavior of of open-circuited transmission lines and open-circuited antennas: B=2pif times sq.rt. of LC radians / unit length. 2 pi f / B = velocity of propagation. It is intuitive that a fat antenna element has more L & C than a thin element and thus a lower velocity of propagation. Best regards, Richard Harrisob, KB5WZI Hmmmm... my straight wire inductance equation from the ARRL handbook indicates smaller wire diameters have larger inductance. ??? 73, John Not surprisingly, that's what E&M texts say too--or leave as an exercise. With a larger diameter, there's less net magnetic field for a given current, so less energy stored, so less inductance. Cheers, Tom So, then, it isn't intuitive (to me, at least) that a fat antenna has more inductance. Intuitive to me is that the reverse may be true. Cheers to you, too, Tom. John |
#32
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John Wood, N4GGO wrote:
"---or intended such as Andrew`s "Radiax" brand of leaky transmission line for installation in tunnels and elevator shafts as a convenient means to extend the reach of over-the-air broadcasts." Similar results are obtained more cheaply by replacing the Radiax with 300-ohm twin-lead. Best regards, Richard Harrison, KB5WZI |
#33
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Mike, N3LI wrote:
"I thought that the inductance tends donward as the diameter of the wire increases. I can understand your calculation after the wavelength part, but don`t quite get the increased inductance part." Good observation. Wire inductance decreases with the circumference increase as this effectively places more parallel inductors in place along the surface of the wire. Wire capacitance increases proportionally with the square of the circunference of the wire as it is proportional to the wire`s surface area. The fatter wire grows capacitance faster than it changes inductance. Reactance along a wire antenna element varies quickly near resonant and antiresonant points so is not uniformly distributed. This complicates calculations and requires average values for some. Bailey says of surge impedance: "Nevertheless, this variation in theoretical surge impedance shall not deter us from setting uup practical "average" values of surge impedance. Best regards, Richard Harrison, KB5WZI |
#34
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![]() "Richard Harrison" wrote in message ... Mike, N3LI wrote: "Why would the velocity be less at increased (antenna element) width?" Let B = the phase velocity on the antenna element, in radians per unit length. 2pi/B = wavelength on the element. Therefore, 2pi/B=velocity of phase propagation. Due to the behavior of of open-circuited transmission lines and open-circuited antennas: B=2pif times sq.rt. of LC radians / unit length. 2 pi f / B = velocity of propagation. It is intuitive that a fat antenna element has more L & C than a thin element and thus a lower velocity of propagation. Best regards, Richard Harrisob, KB5WZI If B is the 'phase velocity' then surely it's also the 'velocity of phase propagation' so that's not 2pi/B? The velocity of propagation of an electromagnetic wave, be it the phase or group velocity, is most-strongly dependent on the permittivity and permeability of the medium in which the wave is propagating. Another clue to resolution of this issue is that the terminal impedance of an open circuit stub has a slope with respect to frequency that depends on the characteristic impedance of the stub. For the case of a cylindrical dipole, the characteristic impedance is not constant but increases progressively along the lengths of the limbs, but the slope of the terminal impedance can be related to an 'average characteristic impedance' and the value of this parameter depends on the average distributed inductance and capacitance, as has been said here before. Z = sqrt(L/C) in general terms. The self-inductance of a conducting cylinder has been shown fairly rigorously by some (e.g. Rosa, and used by Terman) to be inversely proportional to its radial 'thickness' but this appears to be a contentious issue and can lead the unwary user into a paradox! Chris |
#35
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#36
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On Oct 23, 10:35*am, (Richard Harrison)
wrote: Mike, N3LI wrote: "I thought that the inductance tends donward as the diameter of the wire increases. I can understand your calculation after the wavelength part, but don`t quite get the increased inductance part." Good observation. Wire inductance decreases with the circumference increase as this effectively places more parallel inductors in place along the surface of the wire. Wire capacitance increases proportionally with the square of the circunference of the wire as it is proportional to the wire`s surface area. The fatter wire grows capacitance faster than it changes inductance. Reactance along a wire antenna element varies quickly near resonant and antiresonant points so is not uniformly distributed. This complicates calculations and requires average values for some. Bailey says of surge impedance: "Nevertheless, this variation in theoretical surge impedance shall not deter us from setting uup practical "average" values of surge impedance. * Best regards, Richard Harrison, KB5WZI I know we're talking about linear antennas here, but even in that case, it's surely not true that capacitance increases as the square of the wire diameter (or radius or circumference); nor inductance proportional to 1/diameter. Consider that if both those were true, doubling the wire diameter would quadruple the capacitance and halve the inductance, and the propagation velocity along that wire would be 1/sqrt(4*0.5) or about .707 times as great as with the thinner wire. Clearly things change much more gradually than that. In the controlled environment of a coaxial capacitor, the capacitance per unit length is proportional to 1/log(b/a), where a is the inner conductor diameter and b is the inside diameter of the outer conductor. If you change b/a from 10000 to 5000 (huge outer diameter, like a thin wire well away from ground), the capacitance increases by about 8 percent. Going from b/a = 100000 to 50000, the capacitance increases by a little over 6 percent. Similarly, inductance in coax is proportional to log(b/a), so in coax as you change the inner conductor diameter, the capacitance change offsets the inductance change exactly and the propagation velocity is unchanged. The environment of an antenna wire is different than that, but not so different that doubling the wire diameter has a drastic 30% effect on the resonant frequency. Cheers, Tom |
#37
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In article , Richard Clark
wrote: On Thu, 23 Oct 2008 07:01:18 -0400, (J. B. Wood) wrote: In article , Richard Clark wrote: Lest there be any confusion: an antenna IS a transmission line. Hello, and I think one would have to include two antennas and the intervening medium(s) for the above statement to make sense. ... Over a range of frequencies the behavior of this 2-port can easily differ from that of a transmission line, though. It would appear your first sentence is contested by your last sentence in your reply. snip Hello, Richard, and all. And as I previously pointed out the 2-port model might not be the equivalent of a line in a broadband sense. Another way to put it would be that the 2-port could have the electrical characteristics (characteristic impedance, delay, loss) of a particular line at one frequency but of a different line at another frequency. Please excuse my snipping of the remainder of your comments but they sound more of philosophy than science and quite frankly I have no idea what you're talking about. You emphatically stated an antenna "IS" a transmission line without a few words on why this should be so. My take on a transmission line (or waveguide) is that it is a medium (ideally lossless) used to convey electromagnetic energy from one place to another. An antenna (or antenna array) is used to introduce or extract electromagnetic energy from a medium. Unlike the power available at the output of a low-loss transmission line, a receiving antenna operating at a far-field distance from a transmitter can only extract a macimum of 1/2 the power available from an incident electromagnetic wave. Now, if you meant that antennas and transmission lines share phenomena in common (e.g. standing waves) that would be a correct statement. And Maxwell's equations certainly apply to both. But I don't see an equivalency of a single antenna and a non-radiating (at least intended by design) transmission line and I don't recall any of my many electromagnetics texts making such a statement. Sincerely, What you are arguing is a failure of application, not a failure of the device. I've seen similar arguments that forced terms of transformer or transducer into the mix to show how they fail. I find the terms suitable in a casual discussion, but the new minted failures occur on the basis of forcing definitions when the casual applications worked just fine. One can, by a simple twist of the oscillator's frequency knob, find failure in all analogues of antennas, lumped circuits, and transmission lines. Those failures are not exotic perturbations in the 5th decimal place, but simple and utter refusals to conform to a general rule (such as my bald statement). For any attempt to refute my bald statement with "proven concepts" will reveal those challenging concepts built on a foundation of sand by a similar token of counter proof. 73's Richard Clark, KB7QHC John Wood (Code 5550) e-mail: Naval Research Laboratory 4555 Overlook Avenue, SW Washington, DC 20375-5337 |
#38
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K7ITM wrote:
On Oct 23, 10:35 am, (Richard Harrison) wrote: Mike, N3LI wrote: "I thought that the inductance tends donward as the diameter of the wire increases. I can understand your calculation after the wavelength part, but don`t quite get the increased inductance part." Good observation. Wire inductance decreases with the circumference increase as this effectively places more parallel inductors in place along the surface of the wire. Wire capacitance increases proportionally with the square of the circunference of the wire as it is proportional to the wire`s surface area. The fatter wire grows capacitance faster than it changes inductance. Reactance along a wire antenna element varies quickly near resonant and antiresonant points so is not uniformly distributed. This complicates calculations and requires average values for some. Bailey says of surge impedance: "Nevertheless, this variation in theoretical surge impedance shall not deter us from setting uup practical "average" values of surge impedance. Best regards, Richard Harrison, KB5WZI I know we're talking about linear antennas here, but even in that case, it's surely not true that capacitance increases as the square of the wire diameter (or radius or circumference); nor inductance proportional to 1/diameter. Consider that if both those were true, doubling the wire diameter would quadruple the capacitance and halve the inductance, and the propagation velocity along that wire would be 1/sqrt(4*0.5) or about .707 times as great as with the thinner wire. Clearly things change much more gradually than that. Trying to make a "readers Digest" version here.... If I'm following so far: The lowered frequency of resonance is due to changes in the velocity factor. The lowered vf is somewhat due to increased capacitance, and an increase in inductance - the latter part I'm still trying to grok. I think there is likely something more going on. I'm still left with the increased bandwidth phenomenon. None of the above would seem to account for this. I've been working with mobile antennas for the past several months, and I might be going astray, because I keep thinking about increased bandwidth as a partner of lowered efficiency. Not likely the case here. Thanks to everyone for the help, while I'm happy to accept the obvious real results, It is even better if I can understand what is going on. - 73 de Mike N3LI - |
#39
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J. B. Wood wrote:
Hello, and I think one would have to include two antennas and the intervening medium(s) for the above statement to make sense. In any ... John Wood (Code 5550) e-mail: Naval Research Laboratory 4555 Overlook Avenue, SW Washington, DC 20375-5337 Absolutely, such as two antennas stuck into a superconducting media, which extends in all directions to the point of seemingly infinite distances. A rather unique way of viewing the phenomenon, and rarely presented in such terms. Yet, quite valid, nonetheless. Regards, JS |
#40
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Tom, K7ITM wrote:
"The environment of an antenna wire is different from that, but not so different that doubling the diameter has a drastic 30% effect on the resonant frequency." Thanks to Tom for his observation. It makes sense to me. I was wrong. Best regards, Richard Harrison, KB5WZI |
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