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August 20th 03, 11:04 AM
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"Dr. Slick" wrote:
wrote in message ... Actually, you've done 2*pi*radius*force work. Moving one circumference times the force. Actually, thats 2*pi*radius*force*moment arm. Right. In my example, I intended the 'radius' to be the radius at which the force was applied so the 'moment arm' was already accounted for. When the radius is the radius at which the force is applied, 2*pi*radius is the distance through which the force has acted after one revolution so the expression is the same as the common force*distance used for linear work. More generally, it does not matter what the shape of the path is; the work is always the force times the distance along the path. ....Keith |
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