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#1
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What is the available power, Pa in picowatts, that can be extracted from a free
space field of Ea microvolts per meter? A reference I have says it is: Pa = Ea squared multiplied by Ae (the antenna effective area) all divided by 2Zo, where Zo = 377 ohms, the impedance of free space. My question is why 2Zo rather than just Zo. Is it because only half of the power in the field can be extracted and delivered to a load? Ron, W4TQT |
#2
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The fact that you can extract only half the power from a wave with a
perfectly efficient antenna is already built into Ae. That is, Ae = P/S, where P is the power delivered to a conjugate load and S is the power density of the wave. I suspect that in your reference, Ea is the *peak*, not RMS, field strength, and that's why the factor of two. Incidentally, while you can extract only half the power from a wave with a perfectly efficient antenna, it is possible to extract *all* the power from a wave. An anechoic chamber extracts essentially all the power from waves generated within it. Roy Lewallen, W7EL Ron wrote: What is the available power, Pa in picowatts, that can be extracted from a free space field of Ea microvolts per meter? A reference I have says it is: Pa = Ea squared multiplied by Ae (the antenna effective area) all divided by 2Zo, where Zo = 377 ohms, the impedance of free space. My question is why 2Zo rather than just Zo. Is it because only half of the power in the field can be extracted and delivered to a load? Ron, W4TQT |
#3
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My question is why 2Zo rather than just Zo. Is it because only half of the
power in the field can be extracted and delivered to a load? =============================== Yes. With the current induced in the receiving antenna it doubles as a radiator and re-radiates half the power back into the field. But only when the receiver and antenna are Z-matched. If not Z-matched then more than half of the energy is re-radiated and less than half of it is accepted by the receiver. It's a simple case of a conjugate match between a generator and a load which applies whether the antenna is resonant or not. In series with the antenna's radiation resistance there's a small conductor loss resistance and a corresponding small loss in power efficiency. The radiation resistance changes when in an off-resonance condition and so does efficiency. But apart from the change in efficiency, provided a conjugate match is maintained, the 50 percent receive/re-transmit condition always holds and even when well away from resonance a receiving antenna can have high efficiency. It is required only that radiation resistance be considerably greater than conductor loss resistance. Which is rather obvious whichever way one looks at it. --- Reg. |
#4
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On Wed, 08 Sep 2004 23:56:20 -0700, Roy Lewallen hath writ:
The fact that you can extract only half the power from a wave with a perfectly efficient antenna is already built into Ae. That is, Ae = P/S, where P is the power delivered to a conjugate load and S is the power density of the wave. I suspect that in your reference, Ea is the *peak*, not RMS, field strength, and that's why the factor of two. Incidentally, while you can extract only half the power from a wave with a perfectly efficient antenna, it is possible to extract *all* the power from a wave. An anechoic chamber extracts essentially all the power from waves generated within it. As well, the universe, in all it's vastness, eventually "...extracts essentially all the power from waves generated..." by _any_ source. HI!HI! Jonesy, W3DHJ -- | Marvin L Jones | jonz | W3DHJ | linux | Gunnison, Colorado | @ | Jonesy | OS/2 __ | 7,703' -- 2,345m | config.com | DM68mn SK |
#5
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Allodoxaphobia wrote:
Incidentally, while you can extract only half the power from a wave with a perfectly efficient antenna, it is possible to extract *all* the power from a wave. An anechoic chamber extracts essentially all the power from waves generated within it. As well, the universe, in all it's vastness, eventually "...extracts essentially all the power from waves generated..." by _any_ source. HI!HI! No it doesn't. Free space can't extract any energy whatsoever from EM waves travelling through it. Consider :- The cosmic microwave background hasn't had it's power extracted by the universe in all the time since the big bang. Conservation of energy applies everywhere. Just my opinion ;-) but it's allodoxOphobia. best Andy |
#6
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Andy Cowley wrote:
Allodoxaphobia wrote: As well, the universe, in all it's vastness, eventually "...extracts essentially all the power from waves generated..." by _any_ source. No it doesn't. Free space can't extract any energy whatsoever from EM waves travelling through it. Consider :- The cosmic microwave background hasn't had it's power extracted by the universe in all the time since the big bang. Conservation of energy applies everywhere. True so far, but just you wait till the *BIG CRUNCH*. You don't really think that our present Big Bang was the first one ever, do you? :-) -- 73, Cecil, W5DXP -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
#7
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Cecil, W5DXP wrote:
"You don`t really think that our present Big Bang was the first one ever, do you?" Suppose that in a time line of infinite length, with no beginning and no end, there are really no unique events? Everything repeats sooner or later, does it? Best regards, Richard Harrison, KB5WZI |
#8
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Anything which repeats itself is amenable to Fourier Analysis.
If there's a once-only event then Heaviside's Operational Calculus is appropriate. It's not more difficult. It's just a matter of getting used to it. ================================= "Richard Harrison" wrote - Cecil, W5DXP wrote: "You don`t really think that our present Big Bang was the first one ever, do you?" |
#9
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Sheeesh ! "Fourier Analysis of the universe". Now that's HEAVY!
I'll take a pass... Steve "Reg Edwards" wrote in message ... Anything which repeats itself is amenable to Fourier Analysis. If there's a once-only event then Heaviside's Operational Calculus is appropriate. It's not more difficult. It's just a matter of getting used to it. ================================= "Richard Harrison" wrote - Cecil, W5DXP wrote: "You don`t really think that our present Big Bang was the first one ever, do you?" |
#10
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Steve Nosko wrote:
Sheeesh ! "Fourier Analysis of the universe". Now that's HEAVY! I'll take a pass... Steve "Reg Edwards" wrote in message ... Anything which repeats itself is amenable to Fourier Analysis. If there's a once-only event then Heaviside's Operational Calculus is appropriate. It's not more difficult. It's just a matter of getting used to it. ================================= "Richard Harrison" wrote - Cecil, W5DXP wrote: "You don`t really think that our present Big Bang was the first one ever, do you?" No! Fourier analysis of the universe could improve the S/N ratio of Usenet--get all the cranks to go away until they've evaluated the integrals.... Cheers, Phil Hobbs |
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