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#1
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Keith wrote:
"Why the resistance to explaining this case?" Because it should be obvious to anyone who knows enough to ask the question. Nevertheless, I assume the questioner is sincere so here is a simple answer. It`s in Terman if you want more details. Zo = sq rt Z/Y Z = R + j omega L = line series impedance per unit length, ohms. Y = G + j omega C = line shunt admittance per unit length, ohms. For r-f in good lines, this reduces to: Zo = sq rt L/C For d-c, this reduces to: Zo = sq rt R/G Obviously line immpedance at d-c is likely quite different from line impedance at r-f. Best regards, Richard Harrison, KB5WZI |
#2
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Richard Harrison wrote:
Keith wrote: "Why the resistance to explaining this case?" Because it should be obvious to anyone who knows enough to ask the question. Nevertheless, I assume the questioner is sincere so here is a simple answer. It`s in Terman if you want more details. The question was, indeed, sincere. Zo = sq rt Z/Y Z = R + j omega L = line series impedance per unit length, ohms. Y = G + j omega C = line shunt admittance per unit length, ohms. For r-f in good lines, this reduces to: Zo = sq rt L/C For d-c, this reduces to: Zo = sq rt R/G But we were discussing ideal lines, for which, if I recall correctly, R and G are both 0. This leaves us with Z0 = jwL/jwC (w being my font challenged excuse for Omega) which should, in the limit as w approaches 0, leave us with the same answer as for RF. Or have I forgotten how to do math (which is quite possible). In any case, a slight modification to the experiment can get around this difficulty. We'll just perform the experiment at a frequency sufficiently low as to be indistinguishable from 0 given the duration of the experiment. Obviously line immpedance at d-c is likely quite different from line impedance at r-f. This would certainly be true for real world lines where the luxury of R=G=0 does not exist. ....Keith |
#3
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wrote:
But we were discussing ideal lines, for which, if I recall correctly, R and G are both 0. Heck, let's discuss ideal Gods whose whims control everything in an ideal way. This would certainly be true for real world lines where the luxury of R=G=0 does not exist. The luxury of R=G=0 does not exist anywhere in the known universe. Your math model is predicated upon things that don't (can't?) exist. Does that give you some sort of hint? Seems to me this is just one more case of seduction by the idealized steady-state model. "I think it, therefore it exists". -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
#5
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wrote:
If you explanations work only the complexities of the real world but collapse in the simplicities of the ideal world, then you should cast grave suspicions on your explanations. That's exactly what my Baptist Preacher tells me every Sunday. You and my preacher both must assume a supernatural realm for your ideas to work. So first you (and my preacher) must prove that a supernatural realm exists. I've been waiting for proof for 65 years. Please feel free to proceed. -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
#6
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Jim Kelley wrote:
"It may not be a terribly useful thing to know, but it isn`t a ficticious quantity." Agreed. Instantaneous power is real. My point is: Work is power x time. If time is zero, no work is done. Best regards, Richard Harrison, KB5WZI |
#7
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![]() Jim Kelley wrote: "It may not be a terribly useful thing to know, but it isn`t a ficticious quantity." Agreed. Instantaneous power is real. My point is: Work is power x time. If time is zero, no work is done. Best regards, Richard Harrison, KB5WZI Is the rate of doing work zero at all instances of time? Nope. Power is the time rate of change for doing work. It's supposed to be important to know the formula for finding the instantaneous rate of doing work so you can ultimately find the average rate. Maybe you think this is unimportant. I wonder why textbook authors think it is? 73, Tom Donaly, KA6RUH |
#8
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Tdonaly wrote:
Is the rate of doing work zero at all instances of time? Nope. Power is the time rate of change for doing work. It's supposed to be important to know the formula for finding the instantaneous rate of doing work so you can ultimately find the average rate. Maybe you think this is unimportant. I wonder why textbook authors think it is? Point is, one cannot have a time rate of change without a changing time. Zero time is not changing. An electron cannot even wiggle in zero time. -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
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