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#1
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![]() How does the so-called SWR, Forward pwr, Reflected pwr meter work? (Or how gullible can you get?) A small fraction of the line voltage is tapped off. This is V1. A small resistor is inserted in series with the line. The voltage across it is V2. The resistors are proportioned such that when the meter is terminated with 50 ohms, V1 = V2. The meter can be switched to indicate the magnitudes of either V1+V2 or V1-V2. V1+V2 is calibrated to indicate Fwd.Pwr. V1-V2 is calibrated to indicate Ref.Pwr and SWR. It's a sort of confidence trick which works provided a lot of assumptions are made. Whatever is inside the box, a little toroid or tiny fraction of wavelength of line, they all work in exactly the same way. By the way, they make excellent little transmitter-loading indicators and, provided the transmitter is loaded with exactly 50 ohms, they will also indicate the power dissipated in it. Otherwise - - - ??? ---- Reg, G4FGQ |
#2
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Reg Edwards wrote:
The meter can be switched to indicate the magnitudes of either V1+V2 or V1-V2. V1+V2 is calibrated to indicate Fwd.Pwr. V1-V2 is calibrated to indicate Ref.Pwr and SWR. The key to the functionality of such is that the addition and subtraction involve two phasors so the phase angle between the voltage and current is taken into account. Assuming the meter is calibrated for Z0 and actually in a Z0 environment, the necessary conditions for functionality are met for all Smith Chart impedance points on a particular SWR circle. -- 73, Cecil, W5DXP |
#3
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![]() "Cecil Moore" wrote in message ... Reg Edwards wrote: The meter can be switched to indicate the magnitudes of either V1+V2 or V1-V2. V1+V2 is calibrated to indicate Fwd.Pwr. V1-V2 is calibrated to indicate Ref.Pwr and SWR. The key to the functionality of such is that the addition and subtraction involve two phasors so the phase angle between the voltage and current is taken into account. Assuming the meter is calibrated for Z0 and actually in a Z0 environment, the necessary conditions for functionality are met for all Smith Chart impedance points on a particular SWR circle. -- 73, Cecil, W5DXP ============================= Assumptions, assumptions, assumptions. Imagination, imagination, imagination. And what on earth has it to do with a Smith Chart? I've never used one in anger in the whole of my life! Don't have one! Cec, don't worry about it. ;o) Let's not confuse the gullible younger generation. Is the transmitter loaded with X ohms or is it not? ---- Reg, G4FGQ. |
#4
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Reg Edwards wrote:
And what on earth has it to do with a Smith Chart? The phase angle between the total voltage and total current can be had from the Smith Chart. Here's a procedure that I use that works well for ladder-line fed dipoles. 1. Model the antenna feedpoint impedance. Plot it as a point on the Smith Chart. Draw an SWR circle through that point. 2. Knowing the length of the ladder-line and the VF, follow the SWR circle toward the source for the appropriate wavelength(s). Mark that point as the calculated impedance seen by the 50 ohm SWR meter. 3. Measure the 50 ohm SWR. The difference in the calculated lossless SWR and the actual SWR reading indicates the variations plus losses. The above exercise gets me into the ballpark (almost) every time. -- 73, Cecil, W5DXP |
#5
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Reg, G4FGQ wrote:
"Whatever is inside the box, a little toriod or tiny fraction of wavelength of line, they all work in exactly the same way." In-line power meters separate reflected power from incident power for determinations. My second edition of the RSGB "Test Equipment For The Radio Amateur" has an in-line wattmeter diagram on page 4.7 which uses a toriod but operates much like a Bird wattmeter. The RSGB meter uses a 4-inch longth of coax which is grounded only on one end. It carries the power to be measured through the center of the toroid, and this coax forms a 1-turn primary for the toroidal transformer. A center-tapped secondary is wound on the toroid. A capaciitive voltage divider is connected between the coaz center conductor and ground. This voltage divider and the transformer center tap share a common load resistor. The capacitive ratio of the divider is adjusted so that its voltage out is equal to that of the magnetically induced secondary voltage on either side of the center tap. The capacitively supplied voltage is proportional to the coax voltage. The magnetically supplied voltage is proportional to the coax current. Reflected current is flowing in the opposite direction in the coax from forward current in the short piece of coax, so in the direction of current flow where induced volts in the transformer secondary add to those capacitively coupled to the common load the total is douple either contribution. Output of the combo is proportional to the power represented by the current and voltage samples. Reflected power doesn`t affect forward power determination in this instance because its voltage and current samples are out-of-phase and exactly cancel. Since the start and finish of the toroid`s secondary winding are 180-degrees out-of-phase, when the start of the coil is phased with the capacitive sample to produce an output proportional to reverse (reflected) power, the finish end of the coil is phased with the capacitive sample contribution to produce an output proportional to the forward (incident) power. Calibration procedure is given in the book. Best regards, Richard Harrison, KB5WZI |
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