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#31
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I think that you are confusing the _RATE_
or _SLOPE_ of each individually with the differential increase per dB of input signal "Ian Jackson" wrote in message ... In message t, Old Ed writes The original author observed that many practical devices (e.g., mixers) exhibit distortion levels that rise as the "power" of the product in question. For example, third-order distortion rises 3 times as fast (dB scale) as the desired (linear) signal. Snip Ed, where the increasing intermodulation distortion is simply a result of increasing the level of the signals at the input of the mixer (or amplifier), third order distortion actually rises TWICE as fast as the desired signal. Third order distortion DOES rise on a 'three dB per dB' basis, but the wanted signal also rises - at 1dB per dB. The difference is 2dB. So the relationship is 2dB per dB. |
#32
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Let's talk loosely, and talk about money.
If I've got twice as much money than Ian has, then I've got 3dB more. How much do I have? Don't know. If Ian has three times as much as Richard, then he has 4.7 dB more than Richard, and I have 3 + 4.7 =7.7dB more than Richard. How much do I have? Don't know. How much does Ian have? Don't know. How much does Richard have? Don't know. OK, assuming that we could deal in 1/10ths of a cent (1 milli-dollar!) let's assume that Richard has $100 = 50dBm. Ian therefore has 50 + 4.7 = 54.7 dBm. And I have 54.7 + 3 = 57.7 dBm. The answer to your question is that you can start off with an actual reading in dBm, but everything else relative to that is in dB only (although it does give a result in dBm). If the above doesn't answer your question, then, sorry, but I give up. (Which doesn't mean that my interest is 0dBm but -173 dBm, ie, indiscernible below the noise) "Jason" wrote in message oups.com... But why we can add or minus gain and IP3 which are in different unit(db and dbm)? Anyone knows? Thank you rgds Jason |
#33
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Hello All the Kind and Clever People
I think I got what you all explained for me. I will reread them carefully before asking more in order to save your precious time. I am thankful to you all. Thank you so much for people who wrote above with great efforts Jason |
#34
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Thank-you for promoting a genuine discussion in this NG.
"Jason" wrote in message ups.com... Hello All the Kind and Clever People I think I got what you all explained for me. I will reread them carefully before asking more in order to save your precious time. I am thankful to you all. Thank you so much for people who wrote above with great efforts |
#35
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Airy R.Bean wrote:
Thank-you for promoting a genuine discussion in this NG. We had a lot of gin-ur-wine discussions in college. -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 100,000 Newsgroups ---= East/West-Coast Server Farms - Total Privacy via Encryption =--- |
#36
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Wow -- well written Ian
-- Caveat Lector (Reader Beware) Help The New Hams Someone Helped You Or did You Forget That ? "Ian Jackson" wrote in message ... In message .com, Jason writes But why we can add or minus gain and IP3 which are in different unit(db and dbm)? Anyone knows? Thank you rgds Jason Think of it this way: dBm indicates an absolute value. db indicates a relative value. For example: 0dBm = 1mW 0dBm + 3dB = 1mW x 2 = 2mW = 3dBm 0dBm + 10dB = 1mW x 10 = 10mW = 10dBm 3dBm + 10dB = 2mW x 10 = 20mW = 13dBm 20dBm - 30dB = 100mW/1000 = 0.1mW = -10dBm What you can't do is to add dBm values directly. If you have power combiner, and add 10dBm and 13dBm, you can't add 10dBm and 13dBm and get 23dBm. 23dBm would be 200mW (because 20dB is x 100, 3dB is x 2, so 100 x 2 =200), and this is incorrect. What you have to do is to convert the dBm values into mW, then add the mW. 10dBm = 10mW 13dBm = 20mW Total power = 30mW (and not 200mW) 30mW can then be converted back into dBm (= appx 14.5dBm) Do you see the pattern? Ian. -- |
#37
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In message MF9Nd.29160$xt.24350@fed1read07, Caveat Lector
writes Wow -- well written Ian After over 40 years in Cable TV, I think I am beginning to get the hang of it! Ian ; )) -- |
#38
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Hi Ian -
Thanks for trying to clarify, but I think you misread my post somehow. I said "...third-order distortion rises 3 times as fast (dB scale) as the desired (linear) signal." You said "Third order distortion DOES rise on a 'three dB per dB' basis, but the wanted signal also rises - at 1dB per dB." The content of our statements is the same. But you went on to address the slope DIFFERENCE, which I did not discuss. I believe Airy is making the same point I am making here with his (2/5/05 8:25) post. 73, Ed, W6LOL "Ian Jackson" wrote in message ... In message t, Old Ed writes SNIP The original author observed that many practical devices (e.g., mixers) exhibit distortion levels that rise as the "power" of the product in question. For example, third-order distortion rises 3 times as fast (dB scale) as the desired (linear) signal. Snip Ed, where the increasing intermodulation distortion is simply a result of increasing the level of the signals at the input of the mixer (or amplifier), third order distortion actually rises TWICE as fast as the desired signal. Third order distortion DOES rise on a 'three dB per dB' basis, but the wanted signal also rises - at 1dB per dB. The difference is 2dB. So the relationship is 2dB per dB. If you continued to increase the signal levels, you might expect that the level of the intermodulation would eventually catch up with - and overtake - the level of the wanted signal (it doesn't, of course). The third order intercept point is simply the hypothetical level where the level of the intermodulation would have risen so much (at 2dB per dB) that it equals the level of the wanted signal. Ian. -- |
#39
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Hi again -
A couple of added thoughts he 1. The term "mixer" has at least two quite different definitions in the electronics world. To the RF guy, "mixer" means a nonlinear and/or time-variant device that is used to create sum and difference frequencies between an input signal and a local oscillator. But to the audio guy, "mixer" means a highly linear device used to add or combine audio signals WITHOUT producing distortion products. 2. As implied above, an RF mixer does not have to be nonlinear; it can also be implemented as a linear/time-variant device. (Think of a highly linear switch being chopped at the LO frequency.) However, the most common practical mixers are those that can be modelled as non-linear/time-invariant and those that can be modelled as non-linear/time-variant. 73, Ed, W6LOL "Airy R.Bean" wrote in message ... Why, Thank-you! In the case of amplifiers, presumably we are talking about the effects of unwanted strong signals driving the amplifier into its non-linear region (and therefore acting as a mixer)? "Wes Stewart" wrote in message ... On Fri, 4 Feb 2005 16:31:00 -0000, "Airy R.Bean" wrote: From off the top of my head, without any revision..... Pretty good explanation for a mixer, however, IP3 relates equally well to amplifiers. In receivers, IP3 is used as a figure of merit and describes how a receiver will handle weak signals in the presence of other stronger signals. It is as explained earlier, a theoretical value. |
#40
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Hi Airy -
I'm not sure what "answer" you're referring to here. But if you're referring to the question about IP3 applying to amplifiers, the answer is a resounding "yes"--as noted in posts above. As a matter of fact, IP3 is often most useful when applied to an entire chain of cascaded devices such as mixers and amplifiers. Regarding your comment about an amplifier possibly "clipping... before non-linearity," that is impossible by definition--because clipping IS a non-linearity. But it is possible to find amplifiers that are extremely linear below clipping, and which clip very abruptly. Such amplifiers may show relatively poor conformity to the intercept point model, which was based on more gradual nonlinearities. 73, Ed, W6LOL "Airy R.Bean" wrote in message ... I don't know the answer to that, and you are as capable of looking it up as I am. If an amplifier, then perhaps you'd run into clipping problems or rail problems before non-linearity? "Reg Edwards" wrote in message ... "Airy R.Bean" wrote - The better a mixer is, the higher is IP3 for the outputs of the mixer. Am I correct in assuming the device need not be a mixer? Could it be an amplifier? In which case some of the better or worse parameters would just become meaningless. |
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