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#21
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![]() "Reg Edwards" wrote in message ... ............................. Yes, Rho CAN exceed unity when the termination is a passive network. For example, when on a real line, Zo = Ro - jXo and the termination Zt = Rt + jXt then Rho can exceed unity. Rho has an absolute maximum value which approaches 1 + Sqrt(2) = 2.4142 which occurs when the angle of Zo approaches -45 degrees and Zt is purely inductive. It arises because of a weak resonant effect between -jXo and + jXt. The angle of Zo of real lines always becomes more negative as frequency decreases. Mr Smith's Chart does not recognise this. He did it knowingly and deliberately. There are other departures from reality. But at least it is fit for its few intended purposes. ---- Reg, G4FGQ That is exacly what is in a book I have. Tam |
#22
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On Sun, 19 Jun 2005 10:58:15 +0000 (UTC), "Reg Edwards"
wrote: Rho can never be greater than one going into a passive network. Only when you have an active device, or gain, can you move outside of the unity circle on the Smith Chart. Slick ================================== Yes, Rho CAN exceed unity when the termination is a passive network. For example, when on a real line, Zo = Ro - jXo and the termination Zt = Rt + jXt then Rho can exceed unity. Thanks Reg, you beat Tom to it. [g] This was beaten to death (well, I guess it *wasn't* beaten to death, here it is again) over and over again. Chipman in section 7.6 "Complex characteristic impedance" deals with this and concurs with what Reg says above and below. Rho has an absolute maximum value which approaches 1 + Sqrt(2) = 2.4142 which occurs when the angle of Zo approaches -45 degrees and Zt is purely inductive. It arises because of a weak resonant effect between -jXo and + jXt. The angle of Zo of real lines always becomes more negative as frequency decreases. Mr Smith's Chart does not recognise this. He did it knowingly and deliberately. There are other departures from reality. But at least it is fit for its few intended purposes. ---- Reg, G4FGQ |
#24
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Wes Stewart wrote:
He states in part, "To establish that the principle of conservation of energy is not violated on a transmission line even when the magnitude of the reflection coefficient at a point on the line exceeds unity......." Isn't it the same principle as a capacitor in a resonant circuit being able to develop a higher voltage than the voltage incident upon the resonant circuit? -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 100,000 Newsgroups ---= East/West-Coast Server Farms - Total Privacy via Encryption =--- |
#25
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That is exacly what is in a book I have.
Tam ======================== Good! That proves your book is correct. Is it by Kraus or Terman? |
#26
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![]() "Reg Edwards" wrote in message ... That is exacly what is in a book I have. Tam ======================== Good! That proves your book is correct. Is it by Kraus or Terman? Adler, Fano & Chu. It is the book Chipman used in his course. Tam |
#27
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Wes Stewart wrote:
"Go ahead Tom, you have the honor. " It's not worth the effort, Wes. He wasn't willing (or perhaps he was just unable) to do the math last year, and I suppose he isn't this year either. He was willing to call me a liar instead of getting ahold of Besser himself and verifying that Besser long ago corrected that typo about using the complex conjugate in the formula for reflection coefficient. Anyone willing to start with the very basic idea that forward and reverse waves on uniform TEM lines are independent and the ratio of voltage to current in each of them is equal to the line impedance, plus a few other elementary ideas like the sum of currents into a node is zero can, with a bit of algebraic facility, verify the derivation of reflection coefficient expressed in terms of line and load impedance. Or, they can look in the archives (via Google, etc.) to see it presented in past threads here. Cheers, Tom |
#28
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K7ITM wrote:
Anyone willing to start with the very basic idea that forward and reverse waves on uniform TEM lines are independent and the ratio of voltage to current in each of them is equal to the line impedance, ... What? You mean reflected energy doesn't "slosh" around? :-) -- 73, Cecil http://www.qsl.net/w5dxp |
#29
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![]() K7ITM wrote: Wes Stewart wrote: "Go ahead Tom, you have the honor. " It's not worth the effort, Wes. He wasn't willing (or perhaps he was just unable) to do the math last year, and I suppose he isn't this year either. He was willing to call me a liar instead of getting ahold of Besser himself and verifying that Besser long ago corrected that typo about using the complex conjugate in the formula for reflection coefficient. And a liar you still are, apparently. Besser has NOT corrected it, because it isn't a typo! The ARRL also agrees. Slick |
#30
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![]() Tam/WB2TT wrote: "Owen" wrote in message ... ............................. I do note that my ARRL Antenna Handbook (18th edition) and ARRL Handbook (2000) both use rho, however they reckon that rho=(Za-Zo*)/(Za+Zo) (where Zo* means the conjugate of Zo). They do this without derivation, and seem to be in conflict with the derivation in most texts. I suppose the derivation is buried in some article in QST and in the members only section of the ARRL website. Thank you, Owen. Les Besser agrees with the ARRL. However, in almost all practical calculations, Zo is purely real, so that gamma=(Za-Zo)/(Za+Zo) is used in most texts, and the results are the same. Owen, There was a big discussion about this last year, and somebody posted that the ARRL was going to eliminate the conjugate reference. Tam/WB2TT Going to? It says 2000 on that ARRL Handbook! They are NOT going to eliminate the conjugate reference, because it's correct. Slick |
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