Home |
Search |
Today's Posts |
#1
![]() |
|||
|
|||
![]() I'm simply trying to establish the radiation resistance of a non-ideal antenna so I can reasonably match it to the output impedance of the transmitter PA stage. ========================= The input impedance of a 1/2-wave resonant dipole is about 70 ohms. But this may be at a considerable distance from the transmitter output terminals. What do you have in mind to put in between? Then all you have to do is find the purely resistive load the transmitter would be most happy with. Almost certainly it will not correspond to an impedance match. ---- Reg G4FGQ |
#2
![]() |
|||
|
|||
![]()
On Mon, 8 Dec 2003 15:29:59 +0000 (UTC), "Reg Edwards"
wrote: [snip] Hi Reg, It so happens the uniformly distributed radiation resistance is exactly twice the radiation resistance of a 1/2-wave dipole when concentrated at its centre. So the uniformly distributed radiation resistance along a 1/2-wave dipole is about 140 ohms. It cannot be measured. It can be calculated from aerial dimensions. But best just to remember the approximate number 140. It does depend to small extent on wire diameter and 'end-effect'. It's annoying, because the tx output Z I'm trying to match is (by a strange coincidence) 140 ohms! So a folded dipole would be ideal, I guess. However - and it's a big *however* - I can't use one. I'm stuck with a telescopic whip and a ground plane the size of a box of Swan Vestas. I imagine the radiation resistance of such a non-ideal antenna is pretty low, but until someone can gimme a ballpark figure for it, I can't even begin to think about how to go about matching it. :-( -- "I expect history will be kind to me, since I intend to write it." - Winston Churchill |
#3
![]() |
|||
|
|||
![]() It's annoying, because the tx output Z I'm trying to match is (by a strange coincidence) 140 ohms! So a folded dipole would be ideal, I guess. However - and it's a big *however* - I can't use one. I'm stuck with a telescopic whip and a ground plane the size of a box of Swan Vestas. I imagine the radiation resistance of such a non-ideal antenna is pretty low, but until someone can gimme a ballpark figure for it, I can't even begin to think about how to go about matching it. :-( Depending on frequency in use, could you do it experimentally? The way I tune up antennas for ham bands is to hook up a mfj 249 and the tuner to the antenna, get a best fit with the 249 and then replace the 249 with the radio and fine tune from there. There always seems to be some small differance between the result from the mfj and the meter built into the tuner, and at full power I would rather trust the meter built into the tuner (a Millen transmatch jr). You could build an L match with a tapped inductor and variable cap, then experiment with values until you get somewhere in the ballpark of being matched. From there it is is just small adjustments to get perfect matching. thanks, John. KC5DWD |
#4
![]() |
|||
|
|||
![]()
Hi,
For a whip, much shorter than a quarter wave against a poor ground - who knows? However, you want a number? So here's a number; 2 - j500 and it won't be too far wrong. The name of the game in such a situation is "Suck-it and see." Make an intelligent guess at what the impedance is likely to be, rig up a far-field meter and adjust the tap/link/network until it peaks. Then go out for a curry and maybe a drink or two or... Alternatively, buy an antenna book and RTFM :-) Cheers - Joe |
#5
![]() |
|||
|
|||
![]()
I can see from the way you have made your enquiry you havn't the foggiest
idea about what you are trying to accomplish. Do you know the frequency? What transmitter power output do you have in mind - 10 milliwatts or 1KW? For starters forget all about folding anything - you've been reading the wrong books. However you now mention a short whip above a groundplane of unknown construction. The input radiation resistance at the base of a very short vertical antenna, say less than 1/10th of a wavelength, is given by - Rrad = Squareroot( 20 * Height in metres / Wavelength in metres ) ohms. Rrad will be in the order of a few tenths of an ohm at 2 MHz but increases fast as the square of frequency. In series with this radiation resistance is a high value of capacitative reactance which has to be tuned out somewhere by a lot of micro-henries. Best located at or near the antenna base. For a very crude guess the input reactance will be in the order of - Xin = -300 * Cotangent( Angle ) ohms. where Angle = 360 * Height / Wavelength degrees. You will then have the task of winding the correct number of turns on a coil former, of your chosen length and diameter, to provide an inductance of similar value of reactance as presented by the whip. Download program SOLNOID3 for coil design. In series with Rrad and Xin there will be a loss resistance due to the connection to the ground plane. If the ground plane is a vehicle then you can expect a loss resistance between 3 and 15 ohms. If the ground plane consists of a cigarette-pack size metal plate buried in your back yard then expect a ground loss resistance between 500 and 5,000 ohms. Overall antenna input resistance is then Rin = Rrad + Rcoil + Rground. If it is your intention to connect the antenna directly to the transmitter, or via a very, very, short length of coaxial line, then Rin is the resistance which has to be matched to your 150-ohm transmitter by using an L and C impedance matching network. Frankly, it may be easier to redesign the transmitter to match the antenna ;o) But you won't get very far without an impedance measuring device such as a borrowed, begged or stolen antenna analyser. As I have no idea of the purpose of the transmitter + antenna I suggest you ask around for sombody who has already solved the problem and copy his. It may be that a very short miniature centre-loaded dipole would do the job. It doesn't need a groundplane and can be driven via a 150-ohm balanced, twisted-pair line and, if needed at the transmitter end, a simple 150-ohm, 1-to-1 balun. Download program MIDLOAD and amuse yourself. It also designs the loading coil. I KNOW it works. Been there - done that! ---- .................................................. .......... Regards from Reg, G4FGQ For Free Radio Design Software go to http://www.btinternet.com/~g4fgq.regp .................................................. ......... "Paul Burridge" wrote - . "Reg Edwards" [snip] Hi Reg, It so happens the uniformly distributed radiation resistance is exactly twice the radiation resistance of a 1/2-wave dipole when concentrated at its centre. So the uniformly distributed radiation resistance along a 1/2-wave dipole is about 140 ohms. It cannot be measured. It can be calculated from aerial dimensions. But best just to remember the approximate number 140. It does depend to small extent on wire diameter and 'end-effect'. It's annoying, because the tx output Z I'm trying to match is (by a strange coincidence) 140 ohms! So a folded dipole would be ideal, I guess. However - and it's a big *however* - I can't use one. I'm stuck with a telescopic whip and a ground plane the size of a box of Swan Vestas. I imagine the radiation resistance of such a non-ideal antenna is pretty low, but until someone can gimme a ballpark figure for it, I can't even begin to think about how to go about matching it. :-( -- "I expect history will be kind to me, since I intend to write it." - Winston Churchill |
#6
![]() |
|||
|
|||
![]()
Paul Burridge wrote in message . ..
.... It's annoying, because the tx output Z I'm trying to match is (by a strange coincidence) 140 ohms! So a folded dipole would be ideal, I guess. However - and it's a big *however* - I can't use one. I'm stuck with a telescopic whip and a ground plane the size of a box of Swan Vestas. I imagine the radiation resistance of such a non-ideal antenna is pretty low, but until someone can gimme a ballpark figure for it, I can't even begin to think about how to go about matching it. :-( Paul, it would be reeeeally helpful if you'd include enough info so we could give you a ballpark figure. What wavelength (or frequency)? How long is the antenna? How big is that box? (Will someone be holding it during operation?) Yeah, someone did offer a ballpark figure, but that depends a whole lot on what fraction of a wavelength you have for your antenna and your ground plane. (Or perhaps the posting in which you explained all that hasn't made it to this corner of the universe.) Cheers, Tom |
#7
![]() |
|||
|
|||
![]()
On Mon, 8 Dec 2003 21:32:52 +0000 (UTC), "Reg Edwards"
wrote: I can see from the way you have made your enquiry you havn't the foggiest idea about what you are trying to accomplish. Do you know the frequency? What transmitter power output do you have in mind - 10 milliwatts or 1KW? For starters forget all about folding anything - you've been reading the wrong books. However you now mention a short whip above a groundplane of unknown construction. Perhaps you didn't see the earlier posts on the subject. The frequency is 40Mhz (radio control band) and the tx output stage as it stands puts out maximum power of 475mW with a 140 ohm resistor as load. I only *need* 50mW ERP., however, so can stand to see quite a bit of loss from an inefficient antenna. The antenna I will be using is a telescopic whip - exactly the same set-up as you see with model vehicle radio control transmitters- which is what it is, in fact. It ain't rocket science. Someone out there must know the radiation resistance of such a telescopic whip (which has a ground plane of just around 16 square inches contained within the remote control handset) and the best way to couple it to a PA with a 140 ohm output impedance? -- "I expect history will be kind to me, since I intend to write it." - Winston Churchill |
#8
![]() |
|||
|
|||
![]()
Its not a simple matter of matching the transmitter to the radiation
resistance. First a short antenna is going to have a capacitive reactance. You must add an equal amount of inductive reactance (a loading coil) in order to cancel the capacitive reactance and make the antenna resonant at the operating frequency. Then what the transmitter needs to match is the total load impedance of the antenna "system". The load impedance includes the radiation resistance plus the resistance of the loading inductance plus the ground losses. The hardest thing to get a handle on will be the ground losses. The physical size of the transmitter housing is a small portion of a wavelength and losses will change as you handle the unit. |
#9
![]() |
|||
|
|||
![]()
Paul Burridge wrote:
... the best way to couple it to a PA with a 140 ohm output impedance? Use a loading coil to resonate the antenna to 40MHz. Use a transformer or tank circuit to transform the impedance. -- 73, Cecil http://www.qsl.net/w5dxp -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
#10
![]() |
|||
|
|||
![]()
On Tue, 09 Dec 2003 00:04:00 +0000, Paul Burridge wrote:
On Mon, 8 Dec 2003 21:32:52 +0000 (UTC), "Reg Edwards" wrote: I can see from the way you have made your enquiry you havn't the foggiest idea about what you are trying to accomplish. Do you know the frequency? What transmitter power output do you have in mind - 10 milliwatts or 1KW? For starters forget all about folding anything - you've been reading the wrong books. However you now mention a short whip above a groundplane of unknown construction. Perhaps you didn't see the earlier posts on the subject. The frequency is 40Mhz (radio control band) and the tx output stage as it stands puts out maximum power of 475mW with a 140 ohm resistor as load. I only *need* 50mW ERP., however, so can stand to see quite a bit of loss from an inefficient antenna. The antenna I will be using is a telescopic whip - exactly the same set-up as you see with model vehicle radio control transmitters- which is what it is, in fact. It ain't rocket science. Someone out there must know the radiation resistance of such a telescopic whip (which has a ground plane of just around 16 square inches contained within the remote control handset) and the best way to couple it to a PA with a 140 ohm output impedance? You have had quite a few answers which seem pretty good to me. I have a few comments. Stop saying "radiation resistance" and start saying "input impedance" or "feed impedance." Once you know the input impedance, getting maximum power transfer is a straightforward matching problem that can be solved in a variety of ways. True, you won't know for sure how much power is "getting out," but some of the posts in this thread have given you some estimates. If that isn't good enough, then you will have to measure by putting a receive antenna in the far field. Anyway, if you want to measure the input impedance, you should be able to do it with a two-channel oscilloscope and a 40 MHz function generator. Drive the antenna with the function generator and simultaneously measure the input voltage and current, including the phase relationship between them. The input impedance is V/I. To measure the current, put a suitably sized resistor in series with the antenna and measure the voltage across it. The voltage across the resistor should be small compared to the voltage into the antenna. If it is too small to see, use a bigger resistor until you can see it. Make sure both oscilloscope probes are grounded in the same place. Unless you have a differential probe (in which case, use it to measure the voltage across the current sensing resistor). From what others have already said, it sounds like the input will be extremely capacitive with a small series resistance. Once you know the details, however, it will be easy to tell you how to match this to your amplifier. That's my $0.02. Mac |
Reply |
|
Thread Tools | Search this Thread |
Display Modes | |
|
|
![]() |
||||
Thread | Forum | |||
Radial loading coil | Antenna | |||
Internal Resistance (?) | Antenna | |||
50 Ohms "Real Resistive" impedance a Misnomer? | Antenna |