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#1
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Hi, the early '90s ARRL handbooks had construction information for a
simple folded dipole made of 300 oHm twinlead. The article was not in the '96 edition or later. The antenna was made of 300 ohm twinlead. It was fed in the center by a 300 ohm twinlead feeder to a matching capacitor which made it aproximate 50 ohms. The capacitor could be either a regular capacitor (I used silver mica WWII surplus) or a "stub" of more twinlead. At the end of the feed line, which was part of the antenna, you could attach it directly to a 50 omh unbalanced transciever or a 50 ohm coax of any length. The length of the antenna was one half wavelength without the velocity factor and then shorted at the wavelength points compensating for the velocity factor. For example, if it was 10 meters long for a 20 meter dipole, the shorts were about 4 meters from the center for twinlead with a velocity factor of 0.8. If anyone has a copy of the article and could scan it for me, I'd appreicate it, or even better yet, a pointer to an online version of it. Thanks in advance and 73, BTW, if you are also in Israel and asking yourself "where does he get the twinlead"? I don't. I brought it with me when I moved here in '96. Geoff. -- Geoffrey S. Mendelson, Jerusalem, Israel N3OWJ/4X1GM IL Voice: (07)-7424-1667 IL Fax: 972-2-648-1443 U.S. Voice: 1-215-821-1838 Visit my 'blog at http://geoffstechno.livejournal.com/ |
#2
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Geoffrey S. Mendelson wrote:
Hi, the early '90s ARRL handbooks had construction information for a simple folded dipole made of 300 oHm twinlead. The article was not in the '96 edition or later. The antenna was made of 300 ohm twinlead. It was fed in the center by a 300 ohm twinlead feeder to a matching capacitor which made it aproximate 50 ohms. The capacitor could be either a regular capacitor (I used silver mica WWII surplus) or a "stub" of more twinlead. At the end of the feed line, which was part of the antenna, you could attach it directly to a 50 omh unbalanced transciever or a 50 ohm coax of any length. The length of the antenna was one half wavelength without the velocity factor and then shorted at the wavelength points compensating for the velocity factor. For example, if it was 10 meters long for a 20 meter dipole, the shorts were about 4 meters from the center for twinlead with a velocity factor of 0.8. If anyone has a copy of the article and could scan it for me, I'd appreicate it, or even better yet, a pointer to an online version of it. Thanks in advance and 73, BTW, if you are also in Israel and asking yourself "where does he get the twinlead"? I don't. I brought it with me when I moved here in '96. Geoff. Sounds like a scaled up version of an antennas I built from a design called 'The Mighty Wide 6M Dipole'... The design came from the internet I think, I seem to recall G0IER published it on his website. I have also seen the scaling information for other bands... Hope that's of some help... -- 73, Iain M0PCB/P |
#3
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Iain Kelly wrote:
Sounds like a scaled up version of an antennas I built from a design called 'The Mighty Wide 6M Dipole'... The design came from the internet I think, I seem to recall G0IER published it on his website. I have also seen the scaling information for other bands... Thanks, but it led to some questions. Here is the web page I found for it: http://www.qsl.net/g3pto/6m_dipole.html From my calculations, assuming his center frequency was 51 mHz, he used a size factor of 142.494 for the total length of the antenna. This seems odd to me, as it would translate to 467.5 feet which is number I've never seen before. Either something is amiss in my calculations, or he used a different center frequency or just an unusual number. The shorted length makes perfect sense, the ratio of total to shorted is ..8425 which is a reasonable velocity factor for 300 ohm twinlead. The length of the stub makes no sense to me at all, but I'm sure he had his reasons. Using the proportions he used, I wrote a perl program to calculate the size for any frequency. For six meters, it matches his dimensions with a center frequency of 50.1 mHz: for frequency 50.100 mHz. total length 9 feet 3 inches or 2.844 meters. shorted length length 8 feet 10 inches or 2.396 meters. difference length length 0 feet 8 inches or 0.224 meters. stub length length 0 feet 11 inches or 0.298 meters. For 20 meters (14.175 mHz center frequency) I got: for frequency 14.175 mHz. total length 32 feet 11 inches or 10.052 meters. shorted length length 32 feet 9 inches or 8.469 meters. difference length length 0 feet 7 inches or 0.792 meters. stub length length 0 feet 5 inches or 1.052 meters. Anyone have any ideas? Will this work? How do I calculate the stub length? The ARRL Handbook antenna (not to be confused with the ARRL Antenna Handbook, which he used) was slightly different, although this would work too if my calculations are correct. Geoff. -- Geoffrey S. Mendelson, Jerusalem, Israel N3OWJ/4X1GM IL Voice: (07)-7424-1667 IL Fax: 972-2-648-1443 U.S. Voice: 1-215-821-1838 Visit my 'blog at http://geoffstechno.livejournal.com/ |
#4
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![]() For 20 meters (14.175 mHz center frequency) I got: for frequency 14.175 mHz. total length 32 feet 11 inches or 10.052 meters. shorted length length 32 feet 9 inches or 8.469 meters. difference length length 0 feet 7 inches or 0.792 meters. stub length length 0 feet 5 inches or 1.052 meters. Anyone have any ideas? Will this work? How do I calculate the stub length? Think you have some errant decimal points in the last three English/metric conversions W4OP |
#5
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Dale Parfitt wrote:
Think you have some errant decimal points in the last three English/metric conversions Thanks for noticing that. I had the feet part of them being zero, when they should have been greater. It was stupid testing, it worked right at 51 mHz, where they were zero. I didn't look at the 14.1 mHz numbers closely enough. Here is the correct numbers: for frequency 14.100 mHz. total length 33 feet 1 inches or 10.106 meters. shorted length length 32 feet 11 inches or 8.514 meters. difference length length 2 feet 7 inches or 0.796 meters. stub length length 3 feet 5 inches or 1.057 meters. Just another proof that programmers should NOT do quality assurance on their own work. 73, Geoff. -- Geoffrey S. Mendelson, Jerusalem, Israel N3OWJ/4X1GM IL Voice: (07)-7424-1667 IL Fax: 972-2-648-1443 U.S. Voice: 1-215-821-1838 Visit my 'blog at http://geoffstechno.livejournal.com/ |
#6
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Geoffrey S. Mendelson wrote:
Hi, the early '90s ARRL handbooks had construction information for a simple folded dipole made of 300 oHm twinlead. The article was not in the '96 edition or later. I have the '93 edition and cannot find it but I remember how to do it. The antenna was made of 300 ohm twinlead. It was fed in the center by a 300 ohm twinlead feeder to a matching capacitor which made it aproximate 50 ohms. The capacitor could be either a regular capacitor (I used silver mica WWII surplus) or a "stub" of more twinlead. Assuming the SWR on the 300 ohm twinlead is 1:1, you want to install a capacitor that causes an SWR of 6:1 on the twinlead between the capacitor and the 1:1 choke/balun. 300+j0 in parallel with 0-jXc needs to result in 60-j120 ohms. The reactance of the capacitor should be -j150 ohms and it should be positioned 0.062 wavelength from the 1:1 choke/balun. For instance, for 7.2 MHz, the capacitor should be 147pf and be positioned 7.7 ft. from the 1:1 choke/balun assuming a VF of 0.9. -- 73, Cecil http://www.qsl.net/w5dxp |
#7
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Geoffrey S. Mendelson wrote:
From my calculations, assuming his center frequency was 51 mHz, he used a size factor of 142.494 for the total length of the antenna. This seems odd to me, as it would translate to 467.5 feet which is number I've never seen before. 468/f is the length of a dipole adjusted for end effects. Anyone have any ideas? Will this work? How do I calculate the stub length? Why not use a Xc = -j150 cap? I get 0.176 wavelength for a capacitive stub which may be inconvenient at HF. -- 73, Cecil http://www.qsl.net/w5dxp |
#8
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Geoffrey S. Mendelson wrote:
. . . The shorted length makes perfect sense, the ratio of total to shorted is .8425 which is a reasonable velocity factor for 300 ohm twinlead. . . . Actually, shorting the antenna at an intermediate point between the center and ends rather than just at the ends doesn't make much sense. The feedpoint impedance of a folded dipole consists of four times (or other ratio if the conductors are different in size or there are more than two folded conductors) the impedance of a standard dipole, in parallel with two series connected shorted stubs. The dipole consists of the two conductors in parallel. This behaves as a single fat wire which has the effective velocity factor of ordinary insulated wire, around 0.97 or 0.98 that of bare wire. That's why a folded dipole is about the same overall length as a standard dipole. The stubs have the physical length of half the dipole, or a bit shy of a quarter free space wavelength. Unlike the dipole part, they operate as transmission lines, so their velocity factor is around 0.8 -- a value which varies somewhat with cable construction. Folded dipoles are sometimes shorted about 0.8 of the way from the center to the ends in an apparent attempt to make the stubs an electrical quarter wavelength, resulting in their impedance being very high as seen at the feedpoint. But if the intermediate short circuit isn't done, the effect of the somewhat longer stubs is only to add a bit of capacitive reactance across the feedpoint. This lowers the antenna resonant frequency roughly 50 kHz at 14 MHz, and has very little effect on the feedpoint resistance. Antenna resonance can be restored by simply shortening the antenna a little. So why bother with the intermediate short? Roy Lewallen, W7EL |
#9
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The 1986 handbook has the details for this type of antenna on page 33-14,
under the title of "Simple Antennas for HF Portable Operation." For 7.15 MHz, the value of the capacitor is 152 pF, and the length of the matching stub is 6'11-1/2". An open-end stub, made from twin lead, of length 20'-1/2" can be substituted for the capacitor. "Roy Lewallen" wrote in message ... Geoffrey S. Mendelson wrote: . . . The shorted length makes perfect sense, the ratio of total to shorted is .8425 which is a reasonable velocity factor for 300 ohm twinlead. . . . Actually, shorting the antenna at an intermediate point between the center and ends rather than just at the ends doesn't make much sense. The feedpoint impedance of a folded dipole consists of four times (or other ratio if the conductors are different in size or there are more than two folded conductors) the impedance of a standard dipole, in parallel with two series connected shorted stubs. The dipole consists of the two conductors in parallel. This behaves as a single fat wire which has the effective velocity factor of ordinary insulated wire, around 0.97 or 0.98 that of bare wire. That's why a folded dipole is about the same overall length as a standard dipole. The stubs have the physical length of half the dipole, or a bit shy of a quarter free space wavelength. Unlike the dipole part, they operate as transmission lines, so their velocity factor is around 0.8 -- a value which varies somewhat with cable construction. Folded dipoles are sometimes shorted about 0.8 of the way from the center to the ends in an apparent attempt to make the stubs an electrical quarter wavelength, resulting in their impedance being very high as seen at the feedpoint. But if the intermediate short circuit isn't done, the effect of the somewhat longer stubs is only to add a bit of capacitive reactance across the feedpoint. This lowers the antenna resonant frequency roughly 50 kHz at 14 MHz, and has very little effect on the feedpoint resistance. Antenna resonance can be restored by simply shortening the antenna a little. So why bother with the intermediate short? Roy Lewallen, W7EL |
#10
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John, N9JG wrote:
The 1986 handbook has the details for this type of antenna on page 33-14, under the title of "Simple Antennas for HF Portable Operation." For 7.15 MHz, the value of the capacitor is 152 pF, and the length of the matching stub is 6'11-1/2". An open-end stub, made from twin lead, of length 20'-1/2" can be substituted for the capacitor. It might be interesting to some to explain how/why this works. On a feedline with reflections, there are purely resistive current maximum points existing every half-wavelength up and down the feedline. Since the resistance at the current maximum point is often in the ballpark of 50 ohms, this is often a logical point at which to connect the transmitter/tuner. That's why I feed my 130 foot dipole at a current maximum point on each HF band. However, for a folded dipole with a 300 ohm resonant impedance fed with 300 ohm feedline, there are no reflections and therefore no current maximum points because there are no standing waves. So the trick is to cause a 50 ohm current maximum point to occur by causing reflections and standing waves on a short piece of series matching section. A parallel capacitor can often accomplish this function. Obviously, a capacitive stub can do the same thing. Note: the following calculations were done with a paper Smith Chart and therefore suffer from some inaccuracies. A parallel capacitive reactance of -j150 ohms will shift the 300+j0 ohm impedance to 60-j120 ohms. Some may want to refresh their memories on the parallel/series and series/parallel impedance equations. 60-j120 ohms will cause an SWR of ~6:1 from the point where the capacitor is installed on a flat 300 ohm feedline to the necessary 1:1 choke/balun. If we divide the 300 ohm Z0 by the SWR, we will obtain the resistance at the 6:1 SWR current maximum point. That value is 300/6 = 50 ohms and it exists ~0.062 wavelengths farther along than the 60-j120 point where the cap is located. The cap needs to cause an SWR of 9:1 if flat 450 ohm line is used and 12:1 if flat 600 ohm line in used. Needless to say, the Z0 of the line determines the value of capacitive reactance that is necessary to accomplish that function. -- 73, Cecil http://www.qsl.net/w5dxp |
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