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#1
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Hi I have a 12 volt in 600 out [dm35] It takes 18 amps to turn it over When I connect it to a 25 amp P.S. It puts the P.S. into protection How do you know which is pos. or neg. on the dynamotor? I wanted to run a 274n transmitter with out building a P.S. thanks 73 Darryl
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#2
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![]() "griddip4" wrote in message ... Hi I have a 12 volt in 600 out [dm35] It takes 18 amps to turn it over When I connect it to a 25 amp P.S. It puts the P.S. into protection How do you know which is pos. or neg. on the dynamotor? I wanted to run a 274n transmitter with out building a P.S. thanks 73 Darryl -- griddip4 I am not an expert on dynamotors but this doesn't sound right. A dynamotor is a motor connected to a generator. The load on the motor should reflect the load on the generator so that when the generator is running open circuit the motor should not draw much current. Make sure the bearings are not seized, that is that the shaft turns easily (if you can get to it). Its possible either the motor or generator windings are shorted. -- -- Richard Knoppow Los Angeles WB6KBL |
#3
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On Fri, 29 Jun 2012 02:55:20 +0000, griddip4
wrote: Hi I have Hi there. I'm not I have but still pleased to meet you. a 12 volt in 600 out [dm35] It takes 18 amps to turn it over When I connect it to a 25 amp P.S. It puts the P.S. into protection How do you know which is pos. or neg. on the dynamotor? I don't know. I haven't seen your dynamotor. I wanted to run a 274n transmitter with out building a P.S. thanks 73 Darryl You want to run a transmitter in an outbuilding? -- griddip4 =-=-=-=-==-=-=-= God is a spirit. 0% proof! |
#4
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I am not familiar with that particular dynamotor, so I am unable to tell you
which lead is positive and which negative (although it should not be too difficult to determine it). In all cases, please be informed that dynamotors typically have a very high inrush current. If you use a modern stabilized power supply, the overcurrent protection will surely trip. Possible solutions a - to use a plain suitably-sized non-stabilized power supply (just a transformer, diodes and a capacitor) - to feed the dynamotor with a car battery kept steadily charged by (any) suitable power supply After problem will be solved, I fear you will anyway want to build an ad-hoc P.S. replacing the dynamotor. Most often dynamotors are so noisy one can't stand them! Tony I0JX Rome, Italy "griddip4" ha scritto nel messaggio ... Hi I have a 12 volt in 600 out [dm35] It takes 18 amps to turn it over When I connect it to a 25 amp P.S. It puts the P.S. into protection How do you know which is pos. or neg. on the dynamotor? I wanted to run a 274n transmitter with out building a P.S. thanks 73 Darryl -- griddip4 |
#5
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Others have pointed out that the inrush current (starting current) will be
far greater than your 25 amp P.S. Using a battery, and just charging it with your 25 amp power supply may work. I have used a protected power supply by disabling the over current protection circuit. (not something I recommend, however) Old Chief Lynn "griddip4" wrote in message ... Hi I have a 12 volt in 600 out [dm35] It takes 18 amps to turn it over When I connect it to a 25 amp P.S. It puts the P.S. into protection How do you know which is pos. or neg. on the dynamotor? I wanted to run a 274n transmitter with out building a P.S. thanks 73 Darryl -- griddip4 |
#6
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Antonio I0JX wrote:
I am not familiar with that particular dynamotor, so I am unable to tell you which lead is positive and which negative (although it should not be too difficult to determine it). Some of them will run properly in reverse, and of course you get reverse voltage on the output. In all cases, please be informed that dynamotors typically have a very high inrush current. If you use a modern stabilized power supply, the overcurrent protection will surely trip. Figure if you have a 25A running current that your starting current is 50-75 amps. Not for very long, only for a very short time. Adding a big capacitance can help if you're stuck using a current-limited supply. HOWEVER, if you see anything higher than 25A running current under load and it's rated for that, something is wrong. Before I would fire up an old dynamotor, I would pull the thing apart, remove all old grease on bearings, and relube everything with modern lubricants, and I would check the brushes at the same time. Old and crusty lube will increase your starting and running current and eventually damage the bearings and overheat the motor windings. After problem will be solved, I fear you will anyway want to build an ad-hoc P.S. replacing the dynamotor. Most often dynamotors are so noisy one can't stand them! That's why you put it in the trunk of the car where it belongs. --scott -- "C'est un Nagra. C'est suisse, et tres, tres precis." |
#7
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On Mon, 02 Jul 2012 10:01:02 -0400, Scott Dorsey wrote:
Antonio I0JX wrote: I am not familiar with that particular dynamotor, so I am unable to tell you which lead is positive and which negative (although it should not be too difficult to determine it). Some of them will run properly in reverse, and of course you get reverse voltage on the output. In all cases, please be informed that dynamotors typically have a very high inrush current. If you use a modern stabilized power supply, the overcurrent protection will surely trip. Figure if you have a 25A running current that your starting current is 50-75 amps. Not for very long, only for a very short time. Adding a big capacitance can help if you're stuck using a current-limited supply. HOWEVER, if you see anything higher than 25A running current under load and it's rated for that, something is wrong. Before I would fire up an old dynamotor, I would pull the thing apart, remove all old grease on bearings, and relube everything with modern lubricants, and I would check the brushes at the same time. Old and crusty lube will increase your starting and running current and eventually damage the bearings and overheat the motor windings. After problem will be solved, I fear you will anyway want to build an ad-hoc P.S. replacing the dynamotor. Most often dynamotors are so noisy one can't stand them! That's why you put it in the trunk of the car where it belongs. --scott I'm speaking as a guy who controls motors for a living, not someone who's ever even touched a Dynamotor. So size your grain of salt appropriately. First, everything that Scott says about making sure that the Dynamotor is up to snuff before you start is good advice. I would add to Scott's advice that while you're checking brushes, you make sure the commutators are in good shape -- if they're all corroded, then you should be thinking of rebuilding the thing. Check both the generator side and the motor side. I'm not sure about the start-up current only being 3x the run current, unless that's run current while loaded, and an unloaded start. DC motors _really_ like to run at a speed determined by their terminal voltage, and will draw _lots_ of current starting from a stop. If you have a power supply that gracefully limits the current to 10 or 20% higher than the unloaded run speed or just enough to overcome the starting bearing friction, whichever is higher, then it'll almost certainly bring the motor up to speed, albeit more slowly than just strapping the thing onto +12V (or whatever its run voltage is). If your power supply does something unsociable in the face of too-high current, like shutting off, you can try this dodge: 1: measure the terminal resistance of the motor. Do this while rotating the motor in small increments, stopping, then measuring -- the resistance will change depending on the brush position on the armature. Choose the lowest resistance measured for the next step. 2: find the resistance that you can hang off of your supply such that at rated voltage you don't exceed the maximum supply current. Subtract the motor armature resistance from step 1. Remember this number. 2a: if you're lazy, just assume 0 ohms of armature resistance in the motor, and calculate your resistance from the supply's rated voltage and current. 3: calculate the resistor dissipation (P = I^2 * R). Go shopping for a resistor. You can probably go about 1/3 as much power as you calculate, because if the motor starts at all it won't draw that much current for very long (and if it doesn't start, you know enough to slap the power switch off, don't you). 4: wire your resistor in series with your dynamotor, with a switch to short out the resistor at need. 5: switch the switch off -- this is your start position. Turn on your power supply. If the motor starts spinning -- horay! If it doesn't -- slap that there switch off before you burn up your resistor. 6: when the motor seems to be going as fast as it'll go (or if you have an ammeter in there, when it seems to settle out to a minimum), switch the switch on. There should be a current spike (hopefully not enough to screw up your power supply), then the motor should settle out at a slightly higher speed. 7a: tell your loved ones not to sue me if you die 7: turn the HV side on -- My liberal friends think I'm a conservative kook. My conservative friends think I'm a liberal kook. Why am I not happy that they have found common ground? Tim Wescott, Communications, Control, Circuits & Software http://www.wescottdesign.com |
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