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#1
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Hi everybody, I am troubled with transmission line vswr, I hope this is
the right place to ask this question. Is the sr formula same with unmatched generator? I mean I know that SWR = ( 1 + |Gamma_Load| ) / ( 1 - |Gamma_Load| ) Gamma_Load is reflection coefficient at load side. But I think there is a problem with this formula when generator is unmatched to the transmission line so that there is also a reflection at generator side. Is that correct or am i making a mistake somewhere? Thanx in advance. Arif. |
#2
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On 3 Jan 2005 20:31:57 -0800, "ozgun.harmanci"
wrote in .com: Hi everybody, I am troubled with transmission line vswr, I hope this is the right place to ask this question. Is the sr formula same with unmatched generator? I mean I know that SWR = ( 1 + |Gamma_Load| ) / ( 1 - |Gamma_Load| ) Gamma_Load is reflection coefficient at load side. But I think there is a problem with this formula when generator is unmatched to the transmission line so that there is also a reflection at generator side. Is that correct or am i making a mistake somewhere? Thanx in advance. Arif. You are correct. There can be more than one mismatch in a system. Group your system components so you have only two parts: Effective Source (generator + transmission line) Effective Load (load) Then regroup the system again: Effective Source (generator) Effective Load (transmission line + load) The number of possible mismatches depends on the number of components in the system. For example, if your system has five components you can have four possible mismatches. Does that help? |
#3
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![]() "ozgun.harmanci" wrote in message oups.com... Hi everybody, I am troubled with transmission line vswr, I hope this is the right place to ask this question. Is the sr formula same with unmatched generator? I mean I know that SWR = ( 1 + |Gamma_Load| ) / ( 1 - |Gamma_Load| ) Gamma_Load is reflection coefficient at load side. But I think there is a problem with this formula when generator is unmatched to the transmission line so that there is also a reflection at generator side. Is that correct or am i making a mistake somewhere? Why would the generator be "unmatched" in your case is the first question to ask. However to answer your question I would say no. The logic proceeds as follows. Another common formula for calculating SWR is based on measuring the forward and reflected power from the load. SWR=(1+sqrt(Pref/Rfwd))/(1-sqrt(Pref/Pfwd)) In the case of a matched generator there is no power reflected from it. In the mismatched case power is reflected and simply adds to the forward power from the generator towards the miss matched load. Since the generator is now miss matched it does not put out full power, it can't by definition of a conjugally matched generator which can only put out max power in to a matched load. This extra power is partly absorbed by the load and some is reflected back toward the generator where it is again reflected back towards the load. At some point this process of reflections and re-reflections settles out to a steady state. http://home.iag.net/~w2du1/Appendix%207.pdf Look at examples A, B and C diagrams. http://home.iag.net/~w2du1/Appendix%206.pdf http://home.iag.net/~w2du1/Chapter%2023.pdf The power absorbed by the load and what is reflected back is only a function of the load miss match. The generator miss match only alters the forward power. The load miss match controls the reflected power towards the generator, which is always a fixed fraction of the forward power whatever it maybe. Thus I would say the SWR is not dependent on the generator miss match to the line, but can the generator miss match can affect the measured forward power seen on the line. Also when you're measuring the miss match on the line you are generaly interested in the "load miss match" which as I stated above is stricly a function of the forward power sent to the load, and the power reflected from it back towards the generator. -- Leland C. Scott KC8LDO Wireless Network Mobile computing on the go brought to you by Micro$oft Thanx in advance. Arif. |
#4
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![]() "ozgun.harmanci" wrote in message oups.com... Hi everybody, I am troubled with transmission line vswr, I hope this is the right place to ask this question. Is the sr formula same with unmatched generator? I mean I know that SWR = ( 1 + |Gamma_Load| ) / ( 1 - |Gamma_Load| ) Gamma_Load is reflection coefficient at load side. But I think there is a problem with this formula when generator is unmatched to the transmission line so that there is also a reflection at generator side. Is that correct or am i making a mistake somewhere? Thanx in advance. Arif. You may have something there for the first few microseconds of the transmission but after a quiescent state is reached all that matters is the impedance of the line and the load. It has been argued if not settled that power sent back to the generator is not reflected again but either adds or subtracts from the generator power. |
#5
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Testicles.. I only want testicles. LickingMyFreakinAssOrally
"Leland C. Scott" wrote in message ... "ozgun.harmanci" wrote in message oups.com... Hi everybody, I am troubled with transmission line vswr, I hope this is the right place to ask this question. Is the sr formula same with unmatched generator? I mean I know that SWR = ( 1 + |Gamma_Load| ) / ( 1 - |Gamma_Load| ) Gamma_Load is reflection coefficient at load side. But I think there is a problem with this formula when generator is unmatched to the transmission line so that there is also a reflection at generator side. Is that correct or am i making a mistake somewhere? Why would the generator be "unmatched" in your case is the first question to ask. However to answer your question I would say no. The logic proceeds as follows. Another common formula for calculating SWR is based on measuring the forward and reflected power from the load. SWR=(1+sqrt(Pref/Rfwd))/(1-sqrt(Pref/Pfwd)) In the case of a matched generator there is no power reflected from it. In the mismatched case power is reflected and simply adds to the forward power from the generator towards the miss matched load. Since the generator is now miss matched it does not put out full power, it can't by definition of a conjugally matched generator which can only put out max power in to a matched load. This extra power is partly absorbed by the load and some is reflected back toward the generator where it is again reflected back towards the load. At some point this process of reflections and re-reflections settles out to a steady state. http://home.iag.net/~w2du1/Appendix%207.pdf Look at examples A, B and C diagrams. http://home.iag.net/~w2du1/Appendix%206.pdf http://home.iag.net/~w2du1/Chapter%2023.pdf The power absorbed by the load and what is reflected back is only a function of the load miss match. The generator miss match only alters the forward power. The load miss match controls the reflected power towards the generator, which is always a fixed fraction of the forward power whatever it maybe. Thus I would say the SWR is not dependent on the generator miss match to the line, but can the generator miss match can affect the measured forward power seen on the line. Also when you're measuring the miss match on the line you are generaly interested in the "load miss match" which as I stated above is stricly a function of the forward power sent to the load, and the power reflected from it back towards the generator. -- Leland C. Scott KC8LDO Wireless Network Mobile computing on the go brought to you by Micro$oft Thanx in advance. Arif. |
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