Home |
Search |
Today's Posts |
#41
![]() |
|||
|
|||
![]()
On Tue, 28 Jun 2005 15:39:57 -0700, Frank Gilliland
wrote: The energy in a coax travels on the conductors -and- in the dielectric -and- within the magnetic fields. The propogation delay of a line is the combined phase delays of distributed capacitance -and- distributed inductance in the line. The dielectric constant only -seems- to be the determining factor of coax propogation delay because the conductors are straight. IOW, if you replace the center conductor with a coil you will introduce an additional propogation delay into the coax which is -independent- of the dielectric constant (and will have constructed a device known to us old farts as a 'helical resonantor'). Regardless, it has no relevance to this discussion. ***** Well the dielectric constant does have a direct effect on the capacitance as well as the spacing between the two conductors. Still the TEM wave propogates through the dielectric and induces currents in the center and outer conductor. Propogation of a TEM wave can be mathematically describe by the Pyonting Vector. The TEM wave is an alternating E and H field. The currents induced into the conductors have depth only to that of sigma or the skin depth. I am not sure a coiled center conductor would introduce anymore delays than a solid or even stranded center conductor. On face evidence it would seem that it might but only if the coil's turns per inch were suffieciently low enough as to not appear to the traveling wave as a solid conductor. james |
#42
![]() |
|||
|
|||
![]()
if you have over a 2:1 standing wave you can do damage to your finals
or linear Oh brother. Here we go again with more nonsense and myths about SWR! 73 Tom |
#43
![]() |
|||
|
|||
![]()
On Tue, 28 Jun 2005 15:39:57 -0700, Frank Gilliland
wrote: One of the most misunderstood terms in radio is "common-mode current". It simply means that current is moving in the same direction, and in phase, on two or more conductors. It occurs in a coax when current on the -inside- of the shield is in phase with the current on the center conductor. Any RF current on the -outside- of a coax has -nothing- to do with common-mode currents -- it's simply the result of RF spilling out of the coax or being induced onto it from an external field. ******* Yes misunderstood. I have yet to really see any coax of decent quality that has suffiecient gaps in the shield to allow a 27 Mhz wave to have appreciable leakage. Even with 80% coverage the holes in the shield are so little of a wavelength that I would dare say less than 1/10,000 of the energy of the TEM wave propogating down the coax can "leak" out. As for common mode currents the coax itself can have induced currents in the chield from fields radiated from the antenna. Depending on where the coax is located to a conducting surface, you can develope various intensity of currents. Yes you need two conductors minimum to have comnmon mode. Earth can be one of those conductors. |
#44
![]() |
|||
|
|||
![]()
On Tue, 28 Jun 2005 15:39:57 -0700, Frank Gilliland
wrote: Often common mode currents are also rich in harmonic energy and that is what reradiates and cause TVI and interference. Hogwash. Harmonics don't just appear because of common-mode currents. They must come from a source -- i.e, the transmitter. And conductors of common-mode currents don't have any magical properties that let them conduct or radiate harmonics any better than the fundamental frequency. That's RF voodoo. ***** Harmonics are not there due to just common mode. My mistake there. What I was thinking and what I wrote were not well alligned. To generate harmonics off a the shield of the coax from an external induced current, one needs a means of rectification. That can come from two dissimilar metals that are not properly electrically connected. Then the shield can become a radiator of externally induced currents. It is the diode effect of two dissimilar metals that is the source of harmonics. james |
#45
![]() |
|||
|
|||
![]()
Reg Edwards wrote:
Roy, to cut things short, why don't you just say SWR meters don't measure SWR on anything. He did, he just felt compelled to add a page or so of explaination. All they do is indicate whether or not the transmitter is terminated with its correct load resistance. So they are quite useful. Well, to be picky all they do is indicate the divergence from the Zo of the meter, in a certain way. If the TX is designed for that Zo then they do what you say, and they're quite useful. They won't even tell you what the load resistance actually is unless the load is exactly correct. Yes Stop fooling and confusing yourselves. The solution to everybody's problems is simple - just change the name of the thing to TLI. (Transmitter Loading Indicator). Hmm. I'll stick with SWR meter -- which it is if it's used properly. -- ------------------------------------------- Tim Wescott Wescott Design Services http://www.wescottdesign.com |
#46
![]() |
|||
|
|||
![]()
Buck wrote:
I believe he is right. Radios drop power when they don't like the SWR and raise it when it does. That depends on the radio. Without SWR protection one with a class C final, like the ones in the little QRP rigs I have lying around, will deliver more power if it sees a lower RF impedance at the final transistor than it was designed for. It will also overheat said final transistor* and possibly damage it. This will happen for some SWR mismatches but not all. Again without SWR protection one with a class AB or B final, properly tuned for a 50 ohm resistive load, will deliver less power for some mismatches (the same mismatches that would be _higher_ power for the class C final). With other mismatches it would exhibit higher gain but more distortion. At some mismatch and level of drive you could probably expose the finals to too much power dissipation, too high an RF current or too high an RF voltage, and do damage. This depends _heavily_ on the design of the final stage. With SWR protection, of course, the radio will automatically back off, perhaps even in a way that will do some good. So I will use an SWR meter to keep the transmitter happy, and a field strength meter to make sure my antenna is doing it's job. * assuming I got the heatsink design right, neither overly conservative nor overly optimistic. ------------------------------------------- Tim Wescott Wescott Design Services http://www.wescottdesign.com |
#47
![]() |
|||
|
|||
![]()
james wrote:
Lancer wrote: So thats all my tuner does, lengthen or shorten the coax? Are you sure about that? Essentially yes. Without having to go into detailed mathematics, it is the simplest form to explain what is happening. If you include the possibility of changing the Z0 of the coax as well as the length, you will be closer to the truth. -- 73, Cecil http://www.qsl.net/w5dxp ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 100,000 Newsgroups ---= East/West-Coast Server Farms - Total Privacy via Encryption =--- |
#48
![]() |
|||
|
|||
![]()
Buck wrote:
I believe he is right. Radios drop power when they don't like the SWR and raise it when it does. This is an illustration of a common problem. It's really improper *impedances* presented to the radio that disturb it; it doesn't know or care about the actual SWR on whatever transmission line may or may not be connected. Transmitters typically specify and show this load impedance as "SWR". But they can't tell the difference between a half wavelength 50 ohm line with 100 ohm load, which has a line SWR of 2:1; any length of 100 ohm line with a 100 ohm load, which has a line SWR of 1:1; a quarter wavelength of 300 ohm line with a 900 ohm load, which has a line SWR of 3:1; or a 100 ohm resistor. All these and an infinite number of other combinations will present 100 ohms to the rig, all will cause the rig's SWR meter to read 2:1, and all will have exactly the same effect. Roy Lewallen, W7EL |
#49
![]() |
|||
|
|||
![]()
On Tue, 28 Jun 2005 21:01:52 -0700, "Steveo"
wrote: if you have over a 2:1 standing wave you can do damage to your finals or linear ***** Only if you are exceeding the power dissapation of the devices. Considering the way most CBers use radios and amplifiers, your statement maybe more ture than false. Generaly if the power disapation of the finals is not exceeded and there is sufficient margin to handle the reflected power, it will just dissapate as heat in the output circuits and the fianls. Then this is only true if the reflection coefficient of the radio is zero. If other than zero then there will be some of the antenna power reflected back to the transmitter reflected back to the load. Then the rest is dissapated as heat. Then you get all kinds of funny things happening inside the coax. But that is another subject. james "Frank Gilliland" wrote in message .. . On 28 Jun 2005 17:51:10 -0700, "K7ITM" wrote in . com: snip But there's a real problem in communicating this. If you hook a 50 ohm SWR meter to the input of a 75 ohm, 300 ohm, or line of any impedance other than 50 ohms, the meter reading won't be the SWR on the transmission line. That can mislead people into thinking that the SWR is changing with line length when it actually isn't. In addition, most hams (and other non-professionals -- and even many professionals) don't bother to check that their SWR meter is properly calibrated to the impedance they think it is. Most are nominally 50 ohms, but they can be built for any practical line impedance. Checking calibration is not all that difficult, if you take the time to do it. In addition, your nominally 50 ohm line (or 75 or whatever) can have an actual impedance 10% or more from the nominal value. If you have properly calibrated your meter to 50 ohms, and your line is 60 ohms, you would read 1.2:1 SWR when your line is actually 1:1. And if the SWR on the 60 ohm line is 1.2:1, that 50 ohm SWR meter can read anything between 1:1 and 1.44:1, depending on the line length and its load. Finally, though you may have checked that the meter to reads 1:1 with a 50 ohm load and infinity to 1 with a short or open load, the construction of inexpensive meters may cause them to have significant errors at other load impedances. Impedance matching of an SWR meter is generally unimportant since most SWR meters used for HF have a directional coupler that is much shorter than the operating wavelength. Regardless, I'm not a big fan of SWR meters -- they are good for detecting a major malfunction but that's about it. Antenna tuning/matching is best done with a field strength meter. ----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==---- http://www.newsfeeds.com The #1 Newsgroup Service in the World! 120,000+ Newsgroups ----= East and West-Coast Server Farms - Total Privacy via Encryption =---- |
#50
![]() |
|||
|
|||
![]()
On Wed, 29 Jun 2005 11:07:17 -0400, "Fred W4JLE"
wrote: What is the reason a 2:1 SWR can cause such havoc? How can I avoid this catastrophic condition? I feed my dipoles with 450 Ohm ladder line, but the last 20 feet or so is 50 Ohm coax, I guess that makes it work ok. I haven't blown up my finals yet. Lions and tigers and bears Oh my... ***** Actually can happen if you push the finals to where there is insufficeint margin to the maximum heat dissapation. Tubes are a bit more forgiving. Transistor inadequately heatsinked and overdriven, typical CB usage, often have little of no margin for heat dissapation. If the transmitter has a refelction coefficient of zero and the load say .3, then that reflected power from the load is dissapated as heat in the output circuits and any final transistors or tubes. Now if the radio has a reflection coefficient other than zero that will lessen the heat dissapation on the transimiiter. Now you get load and source reflections convoluting within the transmission line. You ought to model a 400 Mhz square wave with source and load refelctions coefficients other than zero. It can get ugly james |
Reply |
Thread Tools | Search this Thread |
Display Modes | |
|
|