Hi,

Anybody know about the electrical length of the coaxial adaptors, for
example the N adaptor (m/m, m/f, f/f).
what is the formula? how to calculated?

"Jzhao" wrote in
oups.com:

Hi,

Anybody know about the electrical length of the coaxial adaptors, for
example the N adaptor (m/m, m/f, f/f).
what is the formula? how to calculated?


Ask this question in: rec.radio.amateur.antenna

N connectors maintain impedance, So maybe its just the physical length of
the adaptor. I'm not sure how it might effect the velocity factor.

SC

Hello Jzhao:

A lot of guys want to use the N type connector believing they have lower
loss. Probably not a hole lot of difference in the loss between a N type
and a PL-259 connector. The PL-259 connector will take way more power
than the N type connector, experience has shown us that.

I would think the length of the connector and a ball park VF of 80
percent would get you real close.

What ya need that info for?

Jay in the Mojave

Jzhao wrote:
Hi,

Anybody know about the electrical length of the coaxial adaptors, for
example the N adaptor (m/m, m/f, f/f).
what is the formula? how to calculated?

On Fri, 14 Apr 2006 05:12:43 -0700, Jay in the Mojave
wrote:

+Hello Jzhao:
+
+A lot of guys want to use the N type connector believing they have lower
+loss. Probably not a hole lot of difference in the loss between a N type
+and a PL-259 connector. The PL-259 connector will take way more power
+than the N type connector, experience has shown us that.
+
*****

The gain in slightly lower loss for N connectors is due to the
constant impedance the connector provides. PL-259 are not guaranteed
constant 50 Ohm impedance.

Still one is argueing over about 0.25 dB. At CB and most Ham
frequencies below VHF, this loss is really minimal. As for power
handling the N connector install properly and kept clean internally
should have power handling capabilities to 1 KW.

james

+I would think the length of the connector and a ball park VF of 80
+percent would get you real close.
+

The length of the connector is so little a wavelength at CB
frequencies that it is really not worth worrying about.

james

Hi, James,

thanks for your formula, but, one question is what is 299.8 for?
by the way, something should be defined, i need the answer of this
question based on the RF 50 Ohm and when it is working on high
frequency (GHz).

the insertion loss of the adaptor can be calculated approximative.
with the intention that sometime we need to know the electrical length
on test measurement technology.

On 17 Apr 2006 00:32:58 -0700, "Jzhao" wrote:

+Hi, James,
+
+thanks for your formula, but, one question is what is 299.8 for?
+by the way, something should be defined, i need the answer of this
+question based on the RF 50 Ohm and when it is working on high
+frequency (GHz).
+
+the insertion loss of the adaptor can be calculated approximative.
+with the intention that sometime we need to know the electrical length
+on test measurement technology.
*****

That is the distance that light travels in meters in one second in
free space.

james