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#1
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Back in July I wrote:
I'm reading David Rutledge's excellent "The Electronics of Radio." In Chapter 10 -- Power Amplifiers, he discusses Class C amps and says, "In addition, if we drive the transistor clear to saturation, using the transistor as a switch, the dissipated power can be greatly reduced, because the saturation voltage is low. This is Class C amplification..." I'd always throught that in Class C, while you'd operate the device so that it was cutoff during most of the cycle, but not saturated. Is this just a different definition of Class C? I checked back with SSDRA and EMRFD, and didn't see anything about driving Class C amps into saturation? What says the group? Do we saturate in Class C or not? -------------------------------------------------------- I've been thinking about this some more. The 1980 ARRL handbook points out that "Solid State power amplifiers should be operated just below their saturation points for best efficiency and stability." Also, the formula that we use to determine load resistance (Rl=Vcc^2/2Po) implies that we are looking for a combination of Vcc, Load resistance and power out that will prevent saturation. And wouldn't we end up with far lower harmonic content if we only clip one side of the wave form (at cutoff) instead of both sides (cutoff and saturation)? I know there are more exotic modes beyond C, but for plain old ordinary ham radio applications, don't we normally avoid saturation in Class C amps? Also, what about this business of having the efficiency improve through saturation "because the saturation voltage is low" Could that be right? If you put a voltage across a conductor and generate a large current, you can't sit back and say "Great! Power consumption across the conductor is low because the voltage drop across it is now minimal!" 73 from London Bill M0HBR N2CQR CU2JL http://www.gadgeteer.us |
#3
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wrote:
Back in July I wrote: I'm reading David Rutledge's excellent "The Electronics of Radio." In Chapter 10 -- Power Amplifiers, he discusses Class C amps and says, "In addition, if we drive the transistor clear to saturation, using the transistor as a switch, the dissipated power can be greatly reduced, because the saturation voltage is low. This is Class C amplification..." I'd always throught that in Class C, while you'd operate the device so that it was cutoff during most of the cycle, but not saturated. Is this just a different definition of Class C? Look at it this way: If you had to drive the device into saturation before it was class C, then there could have been no class C tube amplifiers -- yet I see schematics for them all over my older amateur radio literature. The definition that _I_ was taught was all about conduction angle. I checked back with SSDRA and EMRFD, and didn't see anything about driving Class C amps into saturation? What says the group? Do we saturate in Class C or not? -------------------------------------------------------- I've been thinking about this some more. The 1980 ARRL handbook points out that "Solid State power amplifiers should be operated just below their saturation points for best efficiency and stability." Also, the formula that we use to determine load resistance (Rl=Vcc^2/2Po) implies that we are looking for a combination of Vcc, Load resistance and power out that will prevent saturation. And wouldn't we end up with far lower harmonic content if we only clip one side of the wave form (at cutoff) instead of both sides (cutoff and saturation)? I know there are more exotic modes beyond C, but for plain old ordinary ham radio applications, don't we normally avoid saturation in Class C amps? The "saturation" in bipolar transistor terminology means "current saturation", but it could just as well mean "carrier saturation". When the transistor is saturated the base region is stuffed full of carriers (holes, for an NPN transistor). It takes a while for those carriers to go away, during which the transistor stays on. This is a very nonlinear effect, and can be very slow. The old 74Sxx series logic put a schottkey diode from collector to base on the transistors to keep them out of saturation, and sped them up considerably. So yes, with an otherwise ordinary bipolar transistor you probably want to avoid saturation. Also, what about this business of having the efficiency improve through saturation "because the saturation voltage is low" Could that be right? If you put a voltage across a conductor and generate a large current, you can't sit back and say "Great! Power consumption across the conductor is low because the voltage drop across it is now minimal!" That's the whole point of the class D amplifier (AKA switching amp, or switching supply) at baseband, and the class E amplifier at RF -- you arrange the circuit so the transistor is either on with low voltage across it, or off with no current, with as little time in between as you can manage. But it's not class C, or at least it isn't _just_ class C. I don't think you could manage a class E amplifier with bipolar transistors at RF frequencies, although I'm willing to be surprised. -- Tim Wescott Wescott Design Services http://www.wescottdesign.com Posting from Google? See http://cfaj.freeshell.org/google/ "Applied Control Theory for Embedded Systems" came out in April. See details at http://www.wescottdesign.com/actfes/actfes.html |
#4
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Tim Wescott wrote:
. . . The "saturation" in bipolar transistor terminology means "current saturation", but it could just as well mean "carrier saturation". When the transistor is saturated the base region is stuffed full of carriers (holes, for an NPN transistor). It takes a while for those carriers to go away, during which the transistor stays on. This is a very nonlinear effect, and can be very slow. The old 74Sxx series logic put a schottkey diode from collector to base on the transistors to keep them out of saturation, and sped them up considerably. The very slow saturation recovery you see in saturated switch applications (unless using a gold-doped transistor) is largely absent in typical RF power applications. The reason is the bipolar drive usually employed -- there's typically a large amount of negative base current available to suck the stored charge out of the base region in a hurry. . . . Roy Lewallen, W7EL |
#5
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wrote:
Back in July I wrote: I'm reading David Rutledge's excellent "The Electronics of Radio." In Chapter 10 -- Power Amplifiers, he discusses Class C amps and says, "In addition, if we drive the transistor clear to saturation, using the transistor as a switch, the dissipated power can be greatly reduced, because the saturation voltage is low. This is Class C amplification..." I'd always throught that in Class C, while you'd operate the device so that it was cutoff during most of the cycle, but not saturated. Is this just a different definition of Class C? I checked back with SSDRA and EMRFD, and didn't see anything about driving Class C amps into saturation? What says the group? Do we saturate in Class C or not? -------------------------------------------------------- I've been thinking about this some more. The 1980 ARRL handbook points out that "Solid State power amplifiers should be operated just below their saturation points for best efficiency and stability." Also, the formula that we use to determine load resistance (Rl=Vcc^2/2Po) implies that we are looking for a combination of Vcc, Load resistance and power out that will prevent saturation. And wouldn't we end up with far lower harmonic content if we only clip one side of the wave form (at cutoff) instead of both sides (cutoff and saturation)? I know there are more exotic modes beyond C, but for plain old ordinary ham radio applications, don't we normally avoid saturation in Class C amps? Also, what about this business of having the efficiency improve through saturation "because the saturation voltage is low" Could that be right? If you put a voltage across a conductor and generate a large current, you can't sit back and say "Great! Power consumption across the conductor is low because the voltage drop across it is now minimal!" 73 from London Bill M0HBR N2CQR CU2JL http://www.gadgeteer.us As far as I'm concerned... saturation has nothing to do with the class the amplifier is running. I can saturate an amplifier in any class. Saturation is most ofen an undesireable effect... that causes distortion in amplifiers. www.telstar-electronics.com |
#6
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ORIGINAL MESSAGE:
On 5 Nov 2006 10:26:11 -0800, "Telstar Electronics" wrote: Saturation is most ofen an undesireable effect... that causes distortion in amplifiers. ------------ REPLY FOLLOWS ------------ Saturation is only undesirable in LINEAR amplifiers. In non-linear amps which are often used for CW, RTTY or FM, saturation is good because it improves efficiency. Distortion in those applications is unimportant. Bill, W6WRT |
#7
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Roy Lewallen wrote:
Tim Wescott wrote: . . . The "saturation" in bipolar transistor terminology means "current saturation", but it could just as well mean "carrier saturation". When the transistor is saturated the base region is stuffed full of carriers (holes, for an NPN transistor). It takes a while for those carriers to go away, during which the transistor stays on. This is a very nonlinear effect, and can be very slow. The old 74Sxx series logic put a schottkey diode from collector to base on the transistors to keep them out of saturation, and sped them up considerably. The very slow saturation recovery you see in saturated switch applications (unless using a gold-doped transistor) is largely absent in typical RF power applications. The reason is the bipolar drive usually employed -- there's typically a large amount of negative base current available to suck the stored charge out of the base region in a hurry. . . . I didn't think of that -- in spite of having applied it in a small switching regulator application, per an ap note by Zetex. D'oh. Thanks for pointing it out -- perhaps I'll remember this second application. Perhaps when the third one comes around I'll put one and one together... -- Tim Wescott Wescott Design Services http://www.wescottdesign.com Posting from Google? See http://cfaj.freeshell.org/google/ "Applied Control Theory for Embedded Systems" came out in April. See details at http://www.wescottdesign.com/actfes/actfes.html |
#8
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"Telstar Electronics" wrote in
ps.com: wrote: Back in July I wrote: I'm reading David Rutledge's excellent "The Electronics of Radio." In Chapter 10 -- Power Amplifiers, he discusses Class C amps and says, "In addition, if we drive the transistor clear to saturation, using the transistor as a switch, the dissipated power can be greatly reduced, because the saturation voltage is low. This is Class C amplification..." I'd always throught that in Class C, while you'd operate the device so that it was cutoff during most of the cycle, but not saturated. Is this just a different definition of Class C? I checked back with SSDRA and EMRFD, and didn't see anything about driving Class C amps into saturation? What says the group? Do we saturate in Class C or not? -------------------------------------------------------- I've been thinking about this some more. The 1980 ARRL handbook points out that "Solid State power amplifiers should be operated just below their saturation points for best efficiency and stability." Also, the formula that we use to determine load resistance (Rl=Vcc^2/2Po) implies that we are looking for a combination of Vcc, Load resistance and power out that will prevent saturation. And wouldn't we end up with far lower harmonic content if we only clip one side of the wave form (at cutoff) instead of both sides (cutoff and saturation)? I know there are more exotic modes beyond C, but for plain old ordinary ham radio applications, don't we normally avoid saturation in Class C amps? Also, what about this business of having the efficiency improve through saturation "because the saturation voltage is low" Could that be right? If you put a voltage across a conductor and generate a large current, you can't sit back and say "Great! Power consumption across the conductor is low because the voltage drop across it is now minimal!" 73 from London Bill M0HBR N2CQR CU2JL http://www.gadgeteer.us As far as I'm concerned... saturation has nothing to do with the class the amplifier is running. I can saturate an amplifier in any class. Saturation is most ofen an undesireable effect... that causes distortion in amplifiers. www.telstar-electronics.com Don't worry about saturation. CB'ers think over saturation produces a better sounding signal. Of course, on ham radio we would call them Lids. SC |
#9
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![]() "Telstar Electronics" wrote in message ps.com... wrote: Back in July I wrote: I'm reading David Rutledge's excellent "The Electronics of Radio." In Chapter 10 -- Power Amplifiers, he discusses Class C amps and says, "In addition, if we drive the transistor clear to saturation, using the transistor as a switch, the dissipated power can be greatly reduced, because the saturation voltage is low. This is Class C amplification..." I'd always throught that in Class C, while you'd operate the device so that it was cutoff during most of the cycle, but not saturated. Is this just a different definition of Class C? I checked back with SSDRA and EMRFD, and didn't see anything about driving Class C amps into saturation? What says the group? Do we saturate in Class C or not? -------------------------------------------------------- I've been thinking about this some more. The 1980 ARRL handbook points out that "Solid State power amplifiers should be operated just below their saturation points for best efficiency and stability." Also, the formula that we use to determine load resistance (Rl=Vcc^2/2Po) implies that we are looking for a combination of Vcc, Load resistance and power out that will prevent saturation. And wouldn't we end up with far lower harmonic content if we only clip one side of the wave form (at cutoff) instead of both sides (cutoff and saturation)? I know there are more exotic modes beyond C, but for plain old ordinary ham radio applications, don't we normally avoid saturation in Class C amps? Also, what about this business of having the efficiency improve through saturation "because the saturation voltage is low" Could that be right? If you put a voltage across a conductor and generate a large current, you can't sit back and say "Great! Power consumption across the conductor is low because the voltage drop across it is now minimal!" 73 from London Bill M0HBR N2CQR CU2JL http://www.gadgeteer.us As far as I'm concerned... saturation has nothing to do with the class the amplifier is running. I can saturate an amplifier in any class. Saturation is most ofen an undesireable effect... that causes distortion in amplifiers. www.telstar-electronics.com It can be messy. The class of amplifier is determined by the cut-off (or lack thereof). A class A amplifier neither hits saturation nor hits cut-off. Maximum theoretical efficiency (of a sinusodal waveform) of a class A amp is 50%, but 25% is typical. Very low distortion, of course. Class B amplifiers are biased at cutoff and only conduct for 50% of the cycle. They shouldn't saturate, however. Efficiencies are around 60%. Class C amps are typically biased well into cut-off and only conduct for perhaps 90 degrees (25%) of the cycle and can run 70% efficient. However, there are class D and E amplifiers and they are switchmode amplifiers. They run on or off (cut off or in full saturation). They are normally used for CW or FM and there was a circuit (and components) available from a university to build a cw transmitter using switchmode. The thing ran about 93% efficient! To add to the confusion, with solid state it *is* possible to use the darn things as a *linear* amplifier! Yep, commercial radio stations now use these things. The problem is that the control circuitry (which, I believe, controls the voltage fed to the final) is very complex and expensive and will be found neither in amateur nor cb equipment for a long time. 73 from Rochester, NY Jim |
#10
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Thanks to all who responded. I think I'm starting to understand this.
LTSpice helps a lot. I set up a class C amp and looked out power dissipated in the transistor vs. power dissipated in the load. The big efficiency gains that come with saturation were very apparent. To better understand WHY this happens, I set up a spreadsheet that looked at power dissipated in a variable resistor as it swept from .1 ohms to 10 ohms. It had a fixed 10 ohm resistor in series and 10 volts DC across both of them. Yes indeed, the power disspated in the variable resistor drops off dramatically when the resistance (and hence the voltage across it) gets very low. I guess is why this happens in the saturating Class C amp, Right? But I still have some questions. When we design a Class A amp, the familiar formula Rload = (Vcc-Ve)^2/2Pout allows us to come up with a load value that will prevent the amplifier from saturating. A load of this value will cause the voltage across the transistor (collector to emitter) to vary from zero to twice Vcc. But it won't go into saturation. Why then do so many of the books (EMRFD, SSDRA, the W1FB books) call for the use of essentially the same formula for the load when selecting a load for Class C amps? We're no longer worried about staying out of saturation, correct? In fact, we want to saturate. So why the same formula? In fact, it seems to me that if you have a Class C amplifier that is designed with this formula and is operating just below saturation, you can get it to saturate just by increasing the value of the load presented to the collector. Power out and efficiency immediately improves. Linearity, of course, does not. Thanks, 73 Bill M0HBR http://www.gadgeteer.us On Nov 4, 6:34 pm, wrote: Back in July I wrote: I'm reading David Rutledge's excellent "The Electronics of Radio." In Chapter 10 -- Power Amplifiers, he discusses Class C amps and says, "In addition, if we drive the transistor clear to saturation, using the transistor as a switch, the dissipated power can be greatly reduced, because the saturation voltage is low. This is Class C amplification..." I'd always throught that in Class C, while you'd operate the device so that it was cutoff during most of the cycle, but not saturated. Is this just a different definition of Class C? I checked back with SSDRA and EMRFD, and didn't see anything about driving Class C amps into saturation? What says the group? Do we saturate in Class C or not? -------------------------------------------------------- I've been thinking about this some more. The 1980 ARRL handbook points out that "Solid State power amplifiers should be operated just below their saturation points for best efficiency and stability." Also, the formula that we use to determine load resistance (Rl=Vcc^2/2Po) implies that we are looking for a combination of Vcc, Load resistance and power out that will prevent saturation. And wouldn't we end up with far lower harmonic content if we only clip one side of the wave form (at cutoff) instead of both sides (cutoff and saturation)? I know there are more exotic modes beyond C, but for plain old ordinary ham radio applications, don't we normally avoid saturation in Class C amps? Also, what about this business of having the efficiency improve through saturation "because the saturation voltage is low" Could that be right? If you put a voltage across a conductor and generate a large current, you can't sit back and say "Great! Power consumption across the conductor is low because the voltage drop across it is now minimal!" 73 from London Bill M0HBR N2CQR CU2JLhttp://www.gadgeteer.us |
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