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#11
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On Jul 1, 6:20 pm, wrote:
Tim Wescott wrote: wrote: I have a 12volt home made power supply similar to Astron models. I was told it could handle 30A. The pass transistors are missing and I have some 50 amp NPN darlington transistors on hand I was considering using for replacements. Can you think of any reason these could/should not be used. Jimmie Tons, but all of them start with 'maybe'. The biggest one is 'maybe your power supply was designed for straight transistors' -- if it seems to have hefty current drive to the pass transistor bases, then that would be the case. Otherwise, go ahead and put in your pass transistors and see what happens. Keep in mind that those pass transistors may be missing for a reason, and the reason may be that the power supply never worked well in the first place -- so if what you have doesn't work, it may be the design or execution of your circuit, not the transistors themselves. -- Tim I made a few repairs that were obvious and discovered the power supply design was minimal at best. It does have what seems to be a very heavy duty transformer probably 30 amps CCS. There is no overcurrent/overvoltage protection. The heat sinks are small in comparison to my Pyramid brand 20 amp power supply. The transformer is center tapped but a paralelled pair of bridge rectifers are being used with the (-) leads disconnected. The regulator doesnt have its own power supply or even operate from higher voltage taps on the transformer. Oh well, I bought it for the transformer and it looks like I got a good deal on that and the box. Jimmie Personally I use a cheap FET,100 amps is like $3.00. With 0.004 ohms on resistance. Dual 30 amp schottky diodes for a 60 amp bridge. A TL431 as under voltage detector to clamp the gate to ground for short circuit protection. I gain a few extra volts because of the diode drop is lower and low on resistance of the FET. Which translates into more current from the same supply, that used bipolar transistors and regular diode bridge. 73, N8ZU |
#12
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![]() wrote: I have a 12volt home made power supply similar to Astron models. I was told it could handle 30A. The pass transistors are missing and I have some 50 amp NPN darlington transistors on hand I was considering using for replacements. Can you think of any reason these could/should not be used. Jimmie Ok, I went through the amp and it is a cheap made piece of junk probably made to power a CB amp. No over current/vpoltage protection except fuses on both the input an output. It does have a few things going for it. The power transformer is truly massive. I dont doubt it would do 50 amps intermittently. The computer grade capacitors are 120,000uf total. The rectifiers were a couple of 25 amp bridges paralelled. I got rid of that and replaced thm with some leadless rectifiers that came out of some old telco equipment. I think they were part of a 200 amp bridge. The main problem I have with it is the output transistors get hot, they are well heatsinked. The voltage on the collector of the pass transistors are 22volts. I think this is a little high. Is there a good way to bring this down. The transformer doesnt have any taps. I can put a big VARIAC on the front of of it to get it down but this is not my first choice. I think I remember that Sorenson used to make a power supply that used an SCR or TRIAC circuit on the primary side of the transformer as the control element of their regulator. Any ideas on how to make this a useful device would be appreciated Jimmie |
#13
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#14
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#15
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In article ,
cliff wright wrote: If a search tells you that they are Darlington devices get rid of them right off!!! Darlingtons have a minimum collector/emitter voltage of ~1.5 volts or more so they will get very hot indeed at 30 amps or so. Cliff- Are you sure that applies to Astron-type power supplies? The ones I'm familiar with do not operate with the pass transistors near saturation. Perhaps a Darlington device is not the best choice for some other reason, but I would think a pair of 50 Amp devices could handle 15 Amps each (30 Amps total) with sufficient cooling, if they are rated for at least 120 watts each. (I assume 22 volts input, 14 volts output, 8 * 15 = 120 Watts per device.) Fred K4DII |
#16
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On Mon, 14 Jul 2008 19:44:02 -0400, Fred McKenzie wrote:
In article , cliff wright wrote: If a search tells you that they are Darlington devices get rid of them right off!!! Darlingtons have a minimum collector/emitter voltage of ~1.5 volts or more so they will get very hot indeed at 30 amps or so. Cliff- Are you sure that applies to Astron-type power supplies? The ones I'm familiar with do not operate with the pass transistors near saturation. Perhaps a Darlington device is not the best choice for some other reason, but I would think a pair of 50 Amp devices could handle 15 Amps each (30 Amps total) with sufficient cooling, if they are rated for at least 120 watts each. (I assume 22 volts input, 14 volts output, 8 * 15 = 120 Watts per device.) Fred K4DII -------------------------------------------------------------------------------------- Fred is absolutely correct in saying that the pass transistors in most linear regulators such as those in the Astron supplies do not operate as saturated elements. Therefore, the higher CE saturation voltage of a darlington has no bearing in this discussion. On another point, the 120 watts per device that Fred mentions is at a case temperature of 25 deg, C. Heatsinks of reasonable size can't dissipate that much power and keep the case temperature at 25C. I have a few talking points that nobody has touched on directly. If the regulator was designed to use normal (non-darlington) pass transistors, and you substitute darlingtons in their place, some very bad things could (will) happen. The output of the regulator will likely try to go to its full input voltage rail (because of the high gain of the darlingtons). The feedback loop in the regulator will try to bring it back down to the set output voltage. It probably can't because the gain of the darlingtons is too high, and the output stays banged against the input rail (22V). Even if the regulator loop can bring it down, the control loop isn't compensated correctly for the high gain of the pass elements, and the regulator will oscillate wildly. Both conditions are catastrophic for a power supply. Another point that I would like to mention is that of a transistor's SOA or Safe Operating Area. There are two graphs in the datasheet for the transistors. The SOA graph shows the safe combinations of collector current and collector-emitter voltage AT A CASE TEMPERATURE OF 25 DEG C. The power derating graph shows how much power the transistor can safely dissipate at a given temperature. You MUST use thesse graphs when designing a pass element. They will help you choose the appropriate transistor types and will tell you how many transistors you have to use in the pass element to safely supply the design load current. In almost all cases, the current through each transistor in the pass element is limited to much less than the absolute maximum collector current spec. Thus, although a 2N3771 transistor has an absolute max Ic of 30A, it won't be able to pass that amount of current at any value of CE voltage. The datasheet gives the conditions for that current; the higher the collector current, the lower the CE voltage allowed. Sorry for being long-winded, but it's not a 2-sentence discussion. Cheers!!! ============== Dave M Remove all of the Xs from the reply address Dave M Never take a laxative and a sleeping pill at the same time!! |
#17
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On Mon, 14 Jul 2008 22:20:21 -0400, Dave M
wrote: On Mon, 14 Jul 2008 19:44:02 -0400, Fred McKenzie wrote: In article , cliff wright wrote: If a search tells you that they are Darlington devices get rid of them right off!!! Darlingtons have a minimum collector/emitter voltage of ~1.5 volts or more so they will get very hot indeed at 30 amps or so. Cliff- Are you sure that applies to Astron-type power supplies? The ones I'm familiar with do not operate with the pass transistors near saturation. Are you sure about that ? Have you looked at the capacitor voltage with an oscilloscope with full nominal current and minimum mains voltage ? The goal should be that the capacitor voltage just before the rectifier starts to conduct is only slightly above the output voltage. Another point that I would like to mention is that of a transistor's SOA or Safe Operating Area. There are two graphs in the datasheet for the transistors. The SOA graph shows the safe combinations of collector current and collector-emitter voltage AT A CASE TEMPERATURE OF 25 DEG C. The power derating graph shows how much power the transistor can safely dissipate at a given temperature. The SOA is important especially in the short circuit current limiting case, when both the current and voltage across the transistor is high. A fold-back current limiting solves this problem. The SOA derating usually starts above 5 V, so in a properly designed power supply the input-output voltage difference should be less than that, so in normal operation, the SOA is not very critical. Paul OH3LWR |
#18
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![]() happen. The output of the regulator will likely try to go to its full input voltage rail (because of the high gain of the darlingtons). The feedback loop in the regulator will try to bring it back down to the set output voltage. It probably can't because the gain of the darlingtons is too high, and the output stays banged against the input rail (22V). I dont understand what you mean by this. The voltage gain of the darlington transistors is less than unity in this case since they are being used as emitter followers. I am dropping 8.5 volts at 20 amps or 170 watts is being dissipated by the transistors. This may not be a real problem. I know my commercial power supply of similar size only provides about 18 volts to the collector of the pass transistors and this would result in about half as much power being wasted. What voltage would you normally expect at the the collector of the pass transistors. I have also thought that maybe I dont have that much of a real problem since I doubt if the power supply will ever be put under the same demands as it does working into my load bank. Also I think I should add two more transistors in paralell with the two I have. I think this would distribute the heat better over my heat sink and have less localized heating. I dont think the size of my heatsink is a problem, it is probably overkill. it is a 8in chimney type heat sink( i think that what you call them) 8x8x10 inches finned inside and out. The transistor body is mount on the outside withe the wires going down the inside of the chimney. The end of the chimney is designed to take a muffin fan. Jimmie |
#19
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#20
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The voltage gain of darlingtons is less that unity as a emitter
follower. but not the current gain. The base current is like 20 ma. and the collector is like 20 amps that's a gain of 100. A good regulator like a LM723 can regulate that easy. If the gain ain't there in the darlingtons you need a drive transistor. I use a 0.1 ohm 50watt resistor series with the output, that gives me an extra 2 volt drop that isn't across the transistor and keeps 40 watts from heating up the output. You still lose 40 watts. It just goes up in the resistor. The 0.1 ohm 50 watt is only good for like 22 amps. Put a fan on the heatsink. 170 watts will get hot all the time. I put a computer power supply fan on my supply, the output stays alot cooler. Once the current drops the fan cools it really fast. You have a high transformer voltage because it's a 50 amp supply and you are running it at only 20 amps. On Jul 15, 8:23*am, wrote: happen. The output of the regulator will likely try to go to its full input voltage rail (because of the high gain of the darlingtons). *The feedback loop in the regulator will try to bring it back down to the set output voltage. *It probably can't because the gain of the darlingtons is too high, and the output stays banged against the input rail (22V). I dont understand what you mean by this. The voltage gain of the darlington transistors is less than unity in this case since they are being used as emitter followers. I am dropping 8.5 volts at 20 amps or 170 watts is being dissipated by the transistors. This may not be a real problem. I know my commercial power supply of similar size only provides about 18 volts to the collector of the pass transistors and this *would result in about half as much power being wasted. What voltage would you normally expect at the the collector of the pass transistors. I have also thought that maybe I dont have that much of a real problem since I doubt if the power supply will ever be put under the same demands as it does working into my load bank. Also I think I should add two more transistors in paralell with the two I have. I think this would distribute the heat better over my heat sink and have less localized heating. I dont think the size of my heatsink is a problem, it is probably overkill. it is a 8in chimney type heat sink( i think that what you call them) 8x8x10 inches finned inside and out. The transistor body is mount on the outside *withe the wires going down the inside of the chimney. The end of the chimney is designed to take a muffin fan. Jimmie |
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