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#1
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Hi Guys,
Ages ago I saw a very simple circuit - a CT transformer, couple of caps, 4 rectifiers and a change over switch. With the switch in one position, the circuit was a bridge rectifier, in the other, a voltage doubler. Pointers please, I have forgotten where I saw this... Thanks, Mark |
#2
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On Nov 28, 9:23*pm, MarkAren wrote:
Hi Guys, Ages ago I saw a very simple circuit - a CT transformer, couple of caps, 4 rectifiers and a change over switch. With the switch in one position, the circuit was a bridge rectifier, in the other, a voltage doubler. Pointers please, I have forgotten where I saw this... Thanks, Mark Just draw a standard bridge rectifier circuit, bridge across the full transformer secondary, filter capacitor at the bridge output. Now-- break the connection from the capacitor (-) to the bridge, and put in a SPDT switch, wiper to the cap (and to ground, if you will) and the two possible connections to either the bridge negative output, or to the transformer secondary center tap. There's no problem connecting to the transformer center tap with the bridge (-) floating. You can also use this basic circuit to supply two voltages at once: connect up a bridge circuit, and ground the bridge/cap (-), and also put a cap from transformer CT to ground. The bridge output (peak) will be nominally 1.4* the RMS transformer full secondary (minus a couple diode drops), and the CT output will be half that. Or, you can ground the CT and have + and - nominally equal voltages, assuming the loads on both sides are similar. Cheers, Tom |
#3
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#4
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On Sun, 29 Nov 2009 00:33:13 -0800 (PST), MarkAren
wrote: Bingo ! http://www.idesignz.org/misc/Simple%...tage%20PSU.pdf Thanks, Mark This is a circuit that does not suffer from temporary abcense of power during switching. And it is using a transformer with a single secundary winding. http://www.gigawatts.nl/co/projects/...bel/switch.jpg Joop |
#5
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Hi Joop,
Interesting circuit. Where does the R1/D1/Q/.Q2 reference point connect to ? I assume the parasitic diodes in Q1/Q2 form a current path ? -Mark On Nov 30, 2:54*am, Joop wrote: On Sun, 29 Nov 2009 00:33:13 -0800 (PST), MarkAren wrote: Bingo ! http://www.idesignz.org/misc/Simple%...tage%20PSU.pdf Thanks, Mark This is a circuit that does not suffer from temporary abcense of power during switching. And it is using a transformer with a single secundary winding.http://www.gigawatts.nl/co/projects/...bel/switch.jpg Joop |
#6
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On Nov 29, 9:42*am, MarkAren wrote:
Hi Joop, Interesting circuit. Where does the R1/D1/Q/.Q2 reference point connect to ? I assume the parasitic diodes in Q1/Q2 form a current path ? -Mark .... The idea is that by using two MOSFETs in (anti)series like that, the parasitic diodes can't conduct through from q1.drain to q2.drain. However, they (the parasitic diodes) insure that q1.source=q2.source is at most a diode drop higher than the lower of q1.drain and q2.drain. Then if the photocoupler is "on", the gates are pulled up toward close to the most positive voltage in the circuit, limited of course by the zener diode to protect against gate-source breakdown. In that state, both Q1 and Q2 are hard on. They are happy to conduct as "on" FETs in either direction. If the photocoupler is "off," the gate-source potential drops to essentially zero, and both FETs are off, leaving only the back-to-back parasitic diodes. Essentially the same circuit is used in certain optically coupled relays, such as the Panasonic "PhotoMOS" relays, and in other places. Although the "on" resistance is twice as high as a single MOSFET of the same type, the circuit blocks both polarities when "off," and conducts either direction when "on." Cheers, Tom |
#7
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On Nov 29, 5:54*am, Joop wrote:
On Sun, 29 Nov 2009 00:33:13 -0800 (PST), MarkAren wrote: Bingo ! http://www.idesignz.org/misc/Simple%...tage%20PSU.pdf Thanks, Mark This is a circuit that does not suffer from temporary abcense of power during switching. And it is using a transformer with a single secundary winding.http://www.gigawatts.nl/co/projects/...bel/switch.jpg Joop But should note that it puts out twice the voltage from the same transformer as compared with the bridge/CT circuit. On the other hand, both voltages use the whole secondary, so the safe available output power is nominally the same for either voltage, whereas the output power in the full-wave CT circuit is somewhat less than in the bridge configuration (assuming negligible loss in the diodes). Cheers, Tom |
#8
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![]() The idea behind http://www.gigawatts.nl/co/projects/...bel/switch.jpg is the same as the PC PSUs: you close a connection and it works on 115Vac, you open it and plug the PSU into 230V. And if you go as in http://www.idesignz.org/misc/Simple%...tage%20PSU.pdf you're right that the full-wave center-tap mode does not make full use of the transformer copper (by the way, just adding an electrolytic on the center-tap in place of the switch you can have the two output voltages simultaneously). It's unavoidable, unless wou have two independent secondaries, of course: put both in series or both in parallel. But if you are looking for having two different output voltages (not same DC voltage with 115 or 230 mains), and want to make the best use of your electrolytics (specially if they are big ones), you should need a means to put them in parallel for the low setting, and series for the high. I did it with a DPDT non-shortcircuiting switch. No center-tap (becomes a full-wave doubler as in the gigawatts link). If you are interested I will gladly send it to your address, but you can help me and the Group if you can suggest a convenient way to post files somewhere (not a volatile place such as rapidshare). |
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