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#1
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I'm trying to settle a debate with a friend, and my knowledge of
mixers is pretty rusty. Say you have a receiver whose IF is 455 kHz, and it's tuned to a station at 1500 kHz. If all's working OK, at the output of the mixer you should have four frequencies: 1500 (original signal) 1955 (oscillator signal - osc. working above the signal freq.) 3455 (sum) 455 (difference) My question is by what process does the mixer produce the 3455 and 455 frequencies. I say it's an add and subtract process, my friend says (via mathematics) it's a multiplication process. Who's right? thanks, Joe W9TXU |
#2
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Your friend is right.
If you simply add or subtract two waveforms, no new frequencies are created. You end up with only the frequencies you started with and no more. (Theoretically, you could make one or more disappear if one of the added waveforms contained a precise negative of one or more frequency components of the other -- but you can never get any new frequencies.) That's because addition is a linear process, with linear having a precise definition that's appeared here a number of times before. (Subtraction is just addition, with one waveform inverted before adding.) Multiplication, though, is a nonlinear process by the precise definition used in circuit analysis, and it does create additional frequencies. Multiplying the two original signals of 1500 and 1955 generates the two new frequencies of 455 and 3455, for a total of four frequencies after multiplication. Adding them wouldn't do it. Most good mixers are actually more like switches than multipliers, but they're still nonlinear -- very much so -- and don't do anything remotely like adding the two signals. A doubly balanced mixer produces the sum and difference frequencies while not letting the original two frequencies get through to the output. The generation of the new frequencies by multiplication of the two originals is easily shown mathematically, as your friend says, with a short derivation by means of a trig identity. I'll be glad to post the derivation if you or other readers are interested, although it's widely available elsewhere. Roy Lewallen, W7EL Joer wrote: I'm trying to settle a debate with a friend, and my knowledge of mixers is pretty rusty. Say you have a receiver whose IF is 455 kHz, and it's tuned to a station at 1500 kHz. If all's working OK, at the output of the mixer you should have four frequencies: 1500 (original signal) 1955 (oscillator signal - osc. working above the signal freq.) 3455 (sum) 455 (difference) My question is by what process does the mixer produce the 3455 and 455 frequencies. I say it's an add and subtract process, my friend says (via mathematics) it's a multiplication process. Who's right? thanks, Joe W9TXU |
#3
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Your friend is right.
If you simply add or subtract two waveforms, no new frequencies are created. You end up with only the frequencies you started with and no more. (Theoretically, you could make one or more disappear if one of the added waveforms contained a precise negative of one or more frequency components of the other -- but you can never get any new frequencies.) That's because addition is a linear process, with linear having a precise definition that's appeared here a number of times before. (Subtraction is just addition, with one waveform inverted before adding.) Multiplication, though, is a nonlinear process by the precise definition used in circuit analysis, and it does create additional frequencies. Multiplying the two original signals of 1500 and 1955 generates the two new frequencies of 455 and 3455, for a total of four frequencies after multiplication. Adding them wouldn't do it. Most good mixers are actually more like switches than multipliers, but they're still nonlinear -- very much so -- and don't do anything remotely like adding the two signals. A doubly balanced mixer produces the sum and difference frequencies while not letting the original two frequencies get through to the output. The generation of the new frequencies by multiplication of the two originals is easily shown mathematically, as your friend says, with a short derivation by means of a trig identity. I'll be glad to post the derivation if you or other readers are interested, although it's widely available elsewhere. Roy Lewallen, W7EL Joer wrote: I'm trying to settle a debate with a friend, and my knowledge of mixers is pretty rusty. Say you have a receiver whose IF is 455 kHz, and it's tuned to a station at 1500 kHz. If all's working OK, at the output of the mixer you should have four frequencies: 1500 (original signal) 1955 (oscillator signal - osc. working above the signal freq.) 3455 (sum) 455 (difference) My question is by what process does the mixer produce the 3455 and 455 frequencies. I say it's an add and subtract process, my friend says (via mathematics) it's a multiplication process. Who's right? thanks, Joe W9TXU |
#4
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Yes, your friend is right, but there is a grain of truth in what you are
saying also. A mixer multiplies two signals as your friend says and as said in the posting by W7EL. Signals can be represented by cosines, and the product of two cosines is: cosA * cosB = 0.5(cos(A-B) - cos(A+B) ) See product identities on http://www.swt.edu/slac/math/trigrev/trigrev.html and let A=2*pi*f1 and B=2*pi*f2. So while the operation of the mixer is that signals are _multiplied_, the frequencies will _add_ or subtract. -- Sverre Holm, LA3ZA --------------------------------- www.qsl.net/la3za |
#5
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Yes, your friend is right, but there is a grain of truth in what you are
saying also. A mixer multiplies two signals as your friend says and as said in the posting by W7EL. Signals can be represented by cosines, and the product of two cosines is: cosA * cosB = 0.5(cos(A-B) - cos(A+B) ) See product identities on http://www.swt.edu/slac/math/trigrev/trigrev.html and let A=2*pi*f1 and B=2*pi*f2. So while the operation of the mixer is that signals are _multiplied_, the frequencies will _add_ or subtract. -- Sverre Holm, LA3ZA --------------------------------- www.qsl.net/la3za |
#6
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Roy Lewallen wrote:
Multiplying the two original signals of 1500 and 1955 generates the two new frequencies of 455 and 3455, for a total of four frequencies after multiplication. Adding them wouldn't do it. Part of the confusion is that audio engineers talk about "mixing" where they actually mean adding. Mixing - as RF engineers use the term - is precisely what they don't want! -- 73 from Ian G3SEK 'In Practice' columnist for RadCom (RSGB) Editor, 'The VHF/UHF DX Book' http://www.ifwtech.co.uk/g3sek |
#7
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Roy Lewallen wrote:
Multiplying the two original signals of 1500 and 1955 generates the two new frequencies of 455 and 3455, for a total of four frequencies after multiplication. Adding them wouldn't do it. Part of the confusion is that audio engineers talk about "mixing" where they actually mean adding. Mixing - as RF engineers use the term - is precisely what they don't want! -- 73 from Ian G3SEK 'In Practice' columnist for RadCom (RSGB) Editor, 'The VHF/UHF DX Book' http://www.ifwtech.co.uk/g3sek |
#8
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Mixers are amplitude modulators.
One signal modulates the amplitude of the other. Trigonometrically we have - 2*Sin(A)*Sin(B) = Cos(A-B) - Cos(A+B) Where the A-B and A+B terms are appropriately described as "the products". In practice there are a great number of unwanted products output from a mixer because many harmonics of A and B are generated in the process and all continue to inter-modulate each other. The wanted product, the IF, is usually A-B or A+B. --- .................................................. .......... Regards from Reg, G4FGQ For Free Radio Design Software go to http://www.btinternet.com/~g4fgq.regp .................................................. .......... |
#9
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Mixers are amplitude modulators.
One signal modulates the amplitude of the other. Trigonometrically we have - 2*Sin(A)*Sin(B) = Cos(A-B) - Cos(A+B) Where the A-B and A+B terms are appropriately described as "the products". In practice there are a great number of unwanted products output from a mixer because many harmonics of A and B are generated in the process and all continue to inter-modulate each other. The wanted product, the IF, is usually A-B or A+B. --- .................................................. .......... Regards from Reg, G4FGQ For Free Radio Design Software go to http://www.btinternet.com/~g4fgq.regp .................................................. .......... |
#10
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![]() "Ian White, G3SEK" a écrit dans le message news: ... Roy Lewallen wrote: Multiplying the two original signals of 1500 and 1955 generates the two new frequencies of 455 and 3455, for a total of four frequencies after multiplication. Adding them wouldn't do it. Part of the confusion is that audio engineers talk about "mixing" where they actually mean adding. Mixing - as RF engineers use the term - is precisely what they don't want! Well, ear is also somewhat non linear. So they are also doing mixing. Fred. |
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