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#1
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Greetings,
Recently I bought a grab bag of mixed toroids from www.allelectronics.com . I bought some T-37's and T-50's. The problem is... they're not color coded, and not identified by mix. So I have mystery toroids T-37-?? and T-50-??... The question is, is there a way to come up w/ a rough estimate of the mix value? I wound some test coils and come up w/ these figures: T-50 15turns 30awg = ~150uH T-37 9turns 30awg = ~180uH Perhaps there is a chart or something similar somewhere that I have overlooked that will give me an idea. Thanks for all assistance. Jim Shrum - KC9FFX |
#2
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Look at the tables in the ARRL Handbook, in 2003 it was in Chapter 24, for
tables with the info you need to calculate the inductance on a given core with a certain number of windings. You need to solve for AL obviously since you want to find your core. Uwe in article , J Shrum at wrote on 4/21/04 18:55: Greetings, Recently I bought a grab bag of mixed toroids from www.allelectronics.com . I bought some T-37's and T-50's. The problem is... they're not color coded, and not identified by mix. So I have mystery toroids T-37-?? and T-50-??... The question is, is there a way to come up w/ a rough estimate of the mix value? I wound some test coils and come up w/ these figures: T-50 15turns 30awg = ~150uH T-37 9turns 30awg = ~180uH Perhaps there is a chart or something similar somewhere that I have overlooked that will give me an idea. Thanks for all assistance. Jim Shrum - KC9FFX |
#3
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Look at the tables in the ARRL Handbook, in 2003 it was in Chapter 24, for
tables with the info you need to calculate the inductance on a given core with a certain number of windings. You need to solve for AL obviously since you want to find your core. Uwe in article , J Shrum at wrote on 4/21/04 18:55: Greetings, Recently I bought a grab bag of mixed toroids from www.allelectronics.com . I bought some T-37's and T-50's. The problem is... they're not color coded, and not identified by mix. So I have mystery toroids T-37-?? and T-50-??... The question is, is there a way to come up w/ a rough estimate of the mix value? I wound some test coils and come up w/ these figures: T-50 15turns 30awg = ~150uH T-37 9turns 30awg = ~180uH Perhaps there is a chart or something similar somewhere that I have overlooked that will give me an idea. Thanks for all assistance. Jim Shrum - KC9FFX |
#4
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![]() The question is, is there a way to come up w/ a rough estimate of the mix value? I wound some test coils and come up w/ these figures: T-50 15turns 30awg = ~150uH T-37 9turns 30awg = ~180uH Perhaps there is a chart or something similar somewhere that I have overlooked that will give me an idea. The equation goes; Turns = 100SQR(uH/Al) where Al is the inductance in uH per 100 turns) and 15 = 100SQR(150/Al) and (0.15)^2 = 150/Al and 150/0.0225 = Al = 6666. You have ferrite not powdered iron. For Ferrite, it's just the conversion Turns = 1000SQR (mH/Al) where Al = mH/1000 turns 15 = 1000SQR(.15/Al) and 0.15/0.00225 =66 which looks like, (for T50 core) material 61 W4ZCB |
#5
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![]() The question is, is there a way to come up w/ a rough estimate of the mix value? I wound some test coils and come up w/ these figures: T-50 15turns 30awg = ~150uH T-37 9turns 30awg = ~180uH Perhaps there is a chart or something similar somewhere that I have overlooked that will give me an idea. The equation goes; Turns = 100SQR(uH/Al) where Al is the inductance in uH per 100 turns) and 15 = 100SQR(150/Al) and (0.15)^2 = 150/Al and 150/0.0225 = Al = 6666. You have ferrite not powdered iron. For Ferrite, it's just the conversion Turns = 1000SQR (mH/Al) where Al = mH/1000 turns 15 = 1000SQR(.15/Al) and 0.15/0.00225 =66 which looks like, (for T50 core) material 61 W4ZCB |
#6
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![]() and 0.15/0.00225 =66 which looks like, (for T50 core) material 61 And the T37 core, at 2200, looks like 75 material, look out for it's bulk resistivity which is pretty low. W4ZCB |
#7
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![]() and 0.15/0.00225 =66 which looks like, (for T50 core) material 61 And the T37 core, at 2200, looks like 75 material, look out for it's bulk resistivity which is pretty low. W4ZCB |
#8
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![]() "J Shrum" wrote in message news ![]() Greetings, Recently I bought a grab bag of mixed toroids from www.allelectronics.com .. I bought some T-37's and T-50's. The problem is... they're not color coded, and not identified by mix. So I have mystery toroids T-37-?? and T-50-??... The question is, is there a way to come up w/ a rough estimate of the mix value? I wound some test coils and come up w/ these figures: T-50 15turns 30awg = ~150uH Al = 150uH * square(1/15) = 667 T-37 9turns 30awg = ~180uH Al = 180uH * square(1/9) = 2200 See if these Al values look realistic. Even if not, this is the value of inductance of one turn for the core which some manufacturers used as Al many years ago when I worked with the devices. The inductance ratio varies as the square of the turns ratio. John |
#9
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![]() "J Shrum" wrote in message news ![]() Greetings, Recently I bought a grab bag of mixed toroids from www.allelectronics.com .. I bought some T-37's and T-50's. The problem is... they're not color coded, and not identified by mix. So I have mystery toroids T-37-?? and T-50-??... The question is, is there a way to come up w/ a rough estimate of the mix value? I wound some test coils and come up w/ these figures: T-50 15turns 30awg = ~150uH Al = 150uH * square(1/15) = 667 T-37 9turns 30awg = ~180uH Al = 180uH * square(1/9) = 2200 See if these Al values look realistic. Even if not, this is the value of inductance of one turn for the core which some manufacturers used as Al many years ago when I worked with the devices. The inductance ratio varies as the square of the turns ratio. John |
#10
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Greetings,
Recently I bought a grab bag of mixed toroids from www.allelectronics.com . I bought some T-37's and T-50's. The problem is... they're not color coded, and not identified by mix. So I have mystery toroids T-37-?? and T-50-??... The question is, is there a way to come up w/ a rough estimate of the mix value? I wound some test coils and come up w/ these figures: T-50 15turns 30awg = ~150uH T-37 9turns 30awg = ~180uH Perhaps there is a chart or something similar somewhere that I have overlooked that will give me an idea. Start at http://www.amidoncorp.com/aai_productselection.htm Follow the "Iron Powder Cores" and "Ferrite cores" links. The formulas, and the specific inductance index A(L) values for various toroid formulas, are on those pages. It's important to note that the A(L) values are stated in different units for the two toroid types. For iron-powder cores, it's given as "microhenries for 100 turns", while for ferrite cores it's "millihenries for 1000 turns". -- Dave Platt AE6EO Hosting the Jade Warrior home page: http://www.radagast.org/jade-warrior I do _not_ wish to receive unsolicited commercial email, and I will boycott any company which has the gall to send me such ads! |
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