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On Thu, 24 Feb 2005 11:05:46 GMT, "Verizon News"
wrote: Keepthis in mind: +7dbm (the recommended RMS input for a level 7 mixer) is about 1.5Vpp sine. This holds up to reason, as a DBM has two diode-drops that the LO must overcome in order to switch the diodes properly. Therefore, if you use a square wave, you also need to supply about 1.5Vpp, or the diodes won't switch. There are two common misconceptions many people hold about these devices. One is that they are inherently 50 ohm devices. In reality you will only see 50 ohms on a given port if the other two ports are also terminated in 50 ohms. You could run the device just as well at 75 ohms if you keep it balanced properly. Also, many people think that the LO input is power dependent. This only partially true. It's really voltage dependent, requiring sufficient drive voltage to turn on the diodes and pump an amount of current through them that is large compared to the expected input RF signal. There is no magic in these things. They're just diode DPDT switches that reverse the polarity of the RF signal at a rate determined by the LO frequency. This is essentially the same as multiplying the RF signal by +/-1 at the LO rate. Simple math shows that this multiplication process yields the sum and difference frequency products. The more symmetrical the LO switching waveform, the more perfect the multiplication. This is why square wave LO drive is preferred. Joe W3JDR Thank you. I've worked with them for years and the number of myths are amazing. An SBL-1 is an amazingly rugged device and +13Dbm is not a problem. One problem with using digital logic, especially ttl to drive them is that TTL is a current and voltage limited output with a variable output impedence. A logic low can sink more current that a logic high can source and that means significant non-linear behavour. Also bipolar TTL logic high is not 5V, typically is around 3.2-3.5V at rated current load and worse at higher currrent. When you drive a DBM with it that tends to show as degraded signals, spurs, level problems. When I drive a DBM with logic I use CMOS drivers as they offer near symetrical drive for both levels and better overall output voltage. So it's important to know the driver can supply the current (about 30ma P-P) and the average 74F74 can do that only marginally and if there is any attenuation between the '74 and the DBM it's not going to work. Buffer it with a 74CH244 (octal buffer) with 4 buffers in parallel and you can easily push the 60maP-P at 5VP-P and allow for a 50ohm 5db attenuator for a more correct level. However, pay attention to grounding and bypassing the CMOS under those uses they can send annoying high current spikes into the power sources. Allison |
#12
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Verizon News wrote:
Keepthis in mind: +7dbm (the recommended RMS input for a level 7 mixer) is about 1.5Vpp sine. This holds up to reason, as a DBM has two diode-drops that the LO must overcome in order to switch the diodes properly. Therefore, if you use a square wave, you also need to supply about 1.5Vpp, or the diodes won't switch. There are two common misconceptions many people hold about these devices. One is that they are inherently 50 ohm devices. In reality you will only see 50 ohms on a given port if the other two ports are also terminated in 50 ohms. You could run the device just as well at 75 ohms if you keep it balanced properly. Also, many people think that the LO input is power dependent. This only partially true. It's really voltage dependent, requiring sufficient drive voltage to turn on the diodes and pump an amount of current through them that is large compared to the expected input RF signal. There is no magic in these things. They're just diode DPDT switches that reverse the polarity of the RF signal at a rate determined by the LO frequency. This is essentially the same as multiplying the RF signal by +/-1 at the LO rate. Simple math shows that this multiplication process yields the sum and difference frequency products. The more symmetrical the LO switching waveform, the more perfect the multiplication. This is why square wave LO drive is preferred. Joe W3JDR Thank you all for your help, suggestions and especially for the simple explanation that the mixer diode pairs need enough voltage for switching. I will remeasure with higher voltages and use buffers that supply enough current to drive the mixer. Andreas |
#13
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Did the audio go through a LPF for the phasing unit?
Remember that a square wave is made up of the sum of many harmonics - most of these will have been removed and the amplituyde of the fundamental may not be that large. Richard andreas magun wrote: Hi, I have assembled a T2 phasing exciter (KK7B) and looked at its output spectrum with a spectrum analyzer. When pumping the exciter with quadrature sine wave signals it works as expected (output power roughly 3 mW, sideband supression better than 40 db). However, when pumping with quadrature squarewave signals of approximately the same power, the output power drops by a factor of at least 20 db! I would have expected much more power, similar to that obtained with sine wave pumping. The quadrature phase signal was generated with a 74F74, the quadrature signals being attenuated to give a power of approx. 10 dbm and output impedances of approx. 50 Ohms. There must be an explanation. Thanks Andreas |
#14
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Thanks for replying.
The problem, was that I had not enough LO-power from the 74F74 outputs. I have buffered them with a 50 Ohm TTL Driver 74AS804 that could deliver plenty of current into the LO-inputs. I have limited it to approx 10 mA by a series resistor of 300 Ohm. At a voltage drop of approximately .550 mVpp across the LO-inputs (approx. 5 mW) the exciter works now as expected. Andreas Richard Hosking wrote: Did the audio go through a LPF for the phasing unit? Remember that a square wave is made up of the sum of many harmonics - most of these will have been removed and the amplituyde of the fundamental may not be that large. Richard andreas magun wrote: Hi, I have assembled a T2 phasing exciter (KK7B) and looked at its output spectrum with a spectrum analyzer. When pumping the exciter with quadrature sine wave signals it works as expected (output power roughly 3 mW, sideband supression better than 40 db). However, when pumping with quadrature squarewave signals of approximately the same power, the output power drops by a factor of at least 20 db! I would have expected much more power, similar to that obtained with sine wave pumping. The quadrature phase signal was generated with a 74F74, the quadrature signals being attenuated to give a power of approx. 10 dbm and output impedances of approx. 50 Ohms. There must be an explanation. Thanks Andreas |
#15
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On Mon, 07 Mar 2005 17:47:56 +0100, andreas magun
wrote: Thanks for replying. The problem, was that I had not enough LO-power from the 74F74 outputs. I have buffered them with a 50 Ohm TTL Driver 74AS804 that could deliver plenty of current into the LO-inputs. I have limited it to approx 10 mA by a series resistor of 300 Ohm. At a voltage drop of approximately .550 mVpp across the LO-inputs (approx. 5 mW) the exciter works now as expected. That is good to hear. I've had excellent results with T2 using squarewave drive. Allison |
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