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#1
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Hi,
I have assembled a T2 phasing exciter (KK7B) and looked at its output spectrum with a spectrum analyzer. When pumping the exciter with quadrature sine wave signals it works as expected (output power roughly 3 mW, sideband supression better than 40 db). However, when pumping with quadrature squarewave signals of approximately the same power, the output power drops by a factor of at least 20 db! I would have expected much more power, similar to that obtained with sine wave pumping. The quadrature phase signal was generated with a 74F74, the quadrature signals being attenuated to give a power of approx. 10 dbm and output impedances of approx. 50 Ohms. There must be an explanation. Thanks Andreas |
#2
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"andreas magun" wrote in message
... Hi, I have assembled a T2 phasing exciter (KK7B) and looked at its output spectrum with a spectrum analyzer. When pumping the exciter with quadrature sine wave signals it works as expected (output power roughly 3 mW, sideband supression better than 40 db). However, when pumping with quadrature squarewave signals of approximately the same power, the output power drops by a factor of at least 20 db! I would have expected much more power, similar to that obtained with sine wave pumping. The quadrature phase signal was generated with a 74F74, the quadrature signals being attenuated to give a power of approx. 10 dbm and output impedances of approx. 50 Ohms. Have you checked the RF power from your quadrature driver with resistive loads? It can be very misleading if you measure it whilst connected to the mixers. Leon |
#3
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Leon Heller wrote:
"andreas magun" wrote in message Thanks for your reply, I have checked the output power (voltage) from my quadrature driver with a 50 Ohm load. The output voltage dropped by a factor 2, indicating a good match. The same happened when I attached the mixers (SBL-1) instead. I assumed that the LO-input resistance of an SBL-1 at 7 MHz is close to 50 Ohm and purely resistive. If there is not a plausible explanation for my results I will redo the measurements, to exclude measuring errors. Andreas ... Hi, I have assembled a T2 phasing exciter (KK7B) and looked at its output spectrum with a spectrum analyzer. When pumping the exciter with quadrature sine wave signals it works as expected (output power roughly 3 mW, sideband supression better than 40 db). However, when pumping with quadrature squarewave signals of approximately the same power, the output power drops by a factor of at least 20 db! I would have expected much more power, similar to that obtained with sine wave pumping. The quadrature phase signal was generated with a 74F74, the quadrature signals being attenuated to give a power of approx. 10 dbm and output impedances of approx. 50 Ohms. Have you checked the RF power from your quadrature driver with resistive loads? It can be very misleading if you measure it whilst connected to the mixers. Leon |
#4
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"andreas magun" wrote in message
... Leon Heller wrote: "andreas magun" wrote in message Thanks for your reply, I have checked the output power (voltage) from my quadrature driver with a 50 Ohm load. The output voltage dropped by a factor 2, indicating a good match. The same happened when I attached the mixers (SBL-1) instead. I assumed that the LO-input resistance of an SBL-1 at 7 MHz is close to 50 Ohm and purely resistive. Diode mixers make a real mess of the input LO signal, if you look at what happens to it with a 'scope. They have to be fed from a 50 ohm resistive source, but they are not really resistive themselves. Leon |
#5
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On Wed, 23 Feb 2005 04:28:27 -0000, "Leon Heller"
wrote: Diode mixers make a real mess of the input LO signal, if you look at what happens to it with a 'scope. They have to be fed from a 50 ohm resistive source, but they are not really resistive themselves. yes they do. I've also used square wave drive and found that you have to be sure your really driving them with 7-10DBM. A 74F74 really can't do that though it looks that way. I found I had to use a parallel group of 74HCT244 buffers (minimum of three) to get good drive. Allison |
#6
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wrote in message
... On Wed, 23 Feb 2005 04:28:27 -0000, "Leon Heller" wrote: Diode mixers make a real mess of the input LO signal, if you look at what happens to it with a 'scope. They have to be fed from a 50 ohm resistive source, but they are not really resistive themselves. yes they do. I've also used square wave drive and found that you have to be sure your really driving them with 7-10DBM. A 74F74 really can't do that though it looks that way. I found I had to use a parallel group of 74HCT244 buffers (minimum of three) to get good drive. I suppose what the OP needs is the square wave equivalent of a +7 dBm sine wave. I'm not sure what that is. Leon |
#7
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"Leon Heller" wrote in message
... wrote in message ... On Wed, 23 Feb 2005 04:28:27 -0000, "Leon Heller" wrote: Diode mixers make a real mess of the input LO signal, if you look at what happens to it with a 'scope. They have to be fed from a 50 ohm resistive source, but they are not really resistive themselves. yes they do. I've also used square wave drive and found that you have to be sure your really driving them with 7-10DBM. A 74F74 really can't do that though it looks that way. I found I had to use a parallel group of 74HCT244 buffers (minimum of three) to get good drive. I suppose what the OP needs is the square wave equivalent of a +7 dBm sine wave. I'm not sure what that is. To answer my own post: I think it should be 1V p-p for the equivalent square wave, which is the same power as a 0.5V rms sine wave into 50 ohms (+7 dBm). Leon |
#8
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![]() To answer my own post: I think it should be 1V p-p for the equivalent square wave, which is the same power as a 0.5V rms sine wave into 50 ohms (+7 dBm). Leon 1 Vpp square wave into 50 Ohms would be +13 dbm. What is the maximum power a SBL-1 mixer will survive? Andreas |
#9
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"andreas magun" wrote in message
... To answer my own post: I think it should be 1V p-p for the equivalent square wave, which is the same power as a 0.5V rms sine wave into 50 ohms (+7 dBm). Leon 1 Vpp square wave into 50 Ohms would be +13 dbm. I don't think it is, the average value (same as RMS) will be 0.5V, which is +7 dBm. What is the maximum power a SBL-1 mixer will survive? I think it will take +13 dBm, performance will suffer if it is overdriven. 73, Leon -- Leon Heller, G1HSM http://www.geocities.com/leon_heller |
#10
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Keepthis in mind:
+7dbm (the recommended RMS input for a level 7 mixer) is about 1.5Vpp sine. This holds up to reason, as a DBM has two diode-drops that the LO must overcome in order to switch the diodes properly. Therefore, if you use a square wave, you also need to supply about 1.5Vpp, or the diodes won't switch. There are two common misconceptions many people hold about these devices. One is that they are inherently 50 ohm devices. In reality you will only see 50 ohms on a given port if the other two ports are also terminated in 50 ohms. You could run the device just as well at 75 ohms if you keep it balanced properly. Also, many people think that the LO input is power dependent. This only partially true. It's really voltage dependent, requiring sufficient drive voltage to turn on the diodes and pump an amount of current through them that is large compared to the expected input RF signal. There is no magic in these things. They're just diode DPDT switches that reverse the polarity of the RF signal at a rate determined by the LO frequency. This is essentially the same as multiplying the RF signal by +/-1 at the LO rate. Simple math shows that this multiplication process yields the sum and difference frequency products. The more symmetrical the LO switching waveform, the more perfect the multiplication. This is why square wave LO drive is preferred. Joe W3JDR "andreas magun" wrote in message ... To answer my own post: I think it should be 1V p-p for the equivalent square wave, which is the same power as a 0.5V rms sine wave into 50 ohms (+7 dBm). Leon 1 Vpp square wave into 50 Ohms would be +13 dbm. What is the maximum power a SBL-1 mixer will survive? Andreas |
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