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#1
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Anyone know where I can see a schematic of a common emitter power
supply? I've always read about using the emitter of a pass transistor as the positive terminal output (Common collector). Taking apart this trip lite power supply I see that they have the negative terminal connecting to the collector of the npn pass transistors. This seems like it would extremely complicate the regulation design. Can anyone explain the benefits, and where I can learn more about this design technique? |
#2
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"SMJ" wrote in message
ups.com... Anyone know where I can see a schematic of a common emitter power supply? I've always read about using the emitter of a pass transistor as the positive terminal output (Common collector). Taking apart this trip lite power supply I see that they have the negative terminal connecting to the collector of the npn pass transistors. This seems like it would extremely complicate the regulation design. Can anyone explain the benefits, and where I can learn more about this design technique? It sounds like a standard constant current supply circuit - the collector current is fairly constant with a varying load if the base is held at a fixed voltage. Leon -- Leon Heller, G1HSM http://www.geocities.com/leon_heller |
#3
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On 24 Feb 2005 18:49:06 -0800, "SMJ" wrote:
Anyone know where I can see a schematic of a common emitter power supply? I've always read about using the emitter of a pass transistor as the positive terminal output (Common collector). Taking apart this trip lite power supply I see that they have the negative terminal connecting to the collector of the npn pass transistors. This seems like it would extremely complicate the regulation design. Can anyone explain the benefits, and where I can learn more about this design technique? With the NPN collector as the negative output terminal, which is usually also connected the chassis ground, you can install the TO-3 transistors directly to the chassis without insulation :-). Seriously, the standard emitter follower configuration requires quite a lot of base current, especially if bad transistors, such as 2N3055 are used. These have a low current gain and high Vbe even at moderate currents. Now the question is, where does this current come from ? In high current supplies there are usually an other emitter follower driving the series pass transistors and this driver has also a Vbe drop. Thus, even higher voltages are needed to drive the base current into the driver. The regulator needs to operate quite a few voltages higher than the final output voltage. In addition some extra margin is needed to allow for the voltage drop during capacitor discharging. If you take the regulator voltage from the same capacitors as the series pass transistor, the capacitor voltage may have to be 5-10 V higher than the output voltage. This excessive voltage needs to be dissipated in the series pass transistors at high currents, creating a lot of heat. One way to avoid this, is to use a separate medium current secondary winding to drive the regulator at a higher voltage and use a slightly lower voltage, high current secondary winding. To avoid this a PNP transistor is used on the positive side or a NPN on the negative side. It may be easier to look at the situation with a PNP in the positive side. In this circuit, the current needed by the regulator flows from the positive capacitor end through the emitter and out from the base through the regulator to the negative end of the capacitor. Now the regulator voltage is below both the output voltage and the capacitor voltage and the emitter needs to be only about 1-2 V above the output voltage. You can even drive the series pass transistor into saturation (which requires quite a lot of base current) and hence reduce the capacitor-output voltage difference even further, since it is now easy to sink the base current. This is how the LDO (Low Drop Out voltage) regulators are implemented. Paul OH3LWR |
#4
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Hi,
try http://ftp.qrz.ru/pub/hamradio/schem...707_Manual.pdf and look on the page 11: FP-707 power supply circuit diagram. Transistor Q101 (2SK19-TM/BL) + R101 (56 ohm) acts as an Idss current source (6-14 mA for TM or 12-24 mA for BL), limiting supply output current to about: hFE(Q1) x hFE(Q102) x Idss. 73's de Chris SP7ICE Uzytkownik "SMJ" napisal w wiadomosci ups.com... Anyone know where I can see a schematic of a common emitter power supply? I've always read about using the emitter of a pass transistor as the positive terminal output (Common collector). Taking apart this trip lite power supply I see that they have the negative terminal connecting to the collector of the npn pass transistors. This seems like it would extremely complicate the regulation design. Can anyone explain the benefits, and where I can learn more about this design technique? |
#5
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....to help him out, I would suggest taking a look at National Semi's LDO
Tutorial -- all you have to do is plug "LDO" and "Compensation" in their search engine and the differences between NPN and PNP regulators are explained. "Paul Keinanen" wrote in message news ![]() On 24 Feb 2005 18:49:06 -0800, "SMJ" wrote: Anyone know where I can see a schematic of a common emitter power supply? I've always read about using the emitter of a pass transistor as the positive terminal output (Common collector). Taking apart this trip lite power supply I see that they have the negative terminal connecting to the collector of the npn pass transistors. This seems like it would extremely complicate the regulation design. Can anyone explain the benefits, and where I can learn more about this design technique? With the NPN collector as the negative output terminal, which is usually also connected the chassis ground, you can install the TO-3 transistors directly to the chassis without insulation :-). Seriously, the standard emitter follower configuration requires quite a lot of base current, especially if bad transistors, such as 2N3055 are used. These have a low current gain and high Vbe even at moderate currents. Now the question is, where does this current come from ? In high current supplies there are usually an other emitter follower driving the series pass transistors and this driver has also a Vbe drop. Thus, even higher voltages are needed to drive the base current into the driver. The regulator needs to operate quite a few voltages higher than the final output voltage. In addition some extra margin is needed to allow for the voltage drop during capacitor discharging. If you take the regulator voltage from the same capacitors as the series pass transistor, the capacitor voltage may have to be 5-10 V higher than the output voltage. This excessive voltage needs to be dissipated in the series pass transistors at high currents, creating a lot of heat. One way to avoid this, is to use a separate medium current secondary winding to drive the regulator at a higher voltage and use a slightly lower voltage, high current secondary winding. To avoid this a PNP transistor is used on the positive side or a NPN on the negative side. It may be easier to look at the situation with a PNP in the positive side. In this circuit, the current needed by the regulator flows from the positive capacitor end through the emitter and out from the base through the regulator to the negative end of the capacitor. Now the regulator voltage is below both the output voltage and the capacitor voltage and the emitter needs to be only about 1-2 V above the output voltage. You can even drive the series pass transistor into saturation (which requires quite a lot of base current) and hence reduce the capacitor-output voltage difference even further, since it is now easy to sink the base current. This is how the LDO (Low Drop Out voltage) regulators are implemented. Paul OH3LWR |
#6
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![]() Thanks for all the feedback. I tryed some of the websites you suggested but came up with nothing. Anyone know where I can find a book, or something online to learn more about this? |
#7
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On Fri, 25 Feb 2005 10:04:41 +0200, Paul Keinanen wrote:
On 24 Feb 2005 18:49:06 -0800, "SMJ" wrote: Anyone know where I can see a schematic of a common emitter power supply? I've always read about using the emitter of a pass transistor as the positive terminal output (Common collector). Taking apart this trip lite power supply I see that they have the negative terminal connecting to the collector of the npn pass transistors. This seems like it would extremely complicate the regulation design. Can anyone explain the benefits, and where I can learn more about this design technique? With the NPN collector as the negative output terminal, which is usually also connected the chassis ground, you can install the TO-3 transistors directly to the chassis without insulation :-). Seriously, the standard emitter follower configuration requires quite a lot of base current, especially if bad transistors, such as 2N3055 are used. These have a low current gain and high Vbe even at moderate currents. Now the question is, where does this current come from ? In high current supplies there are usually an other emitter follower driving the series pass transistors and this driver has also a Vbe drop. Thus, even higher voltages are needed to drive the base current into the driver. The regulator needs to operate quite a few voltages higher than the final output voltage. In addition some extra margin is needed to allow for the voltage drop during capacitor discharging. If you take the regulator voltage from the same capacitors as the series pass transistor, the capacitor voltage may have to be 5-10 V higher than the output voltage. This excessive voltage needs to be dissipated in the series pass transistors at high currents, creating a lot of heat. One way to avoid this, is to use a separate medium current secondary winding to drive the regulator at a higher voltage and use a slightly lower voltage, high current secondary winding. To avoid this a PNP transistor is used on the positive side or a NPN on the negative side. It may be easier to look at the situation with a PNP in the positive side. Just what I was going to suggest the O/P do. Apart from the earthing the neg terminal, using a PNP pass as an afterburner makes a helluva lot of sense. I did that on my very first home-made bench PSU where a 723 drives the external PNP (darlington) to 15A. I chose this configuration because the available transformer didn't provide enough headroom for cascaded emitter followers. (and I absolutely HATE 2N3055's with a passion, for the reasons you state - low HFE at any sort of current worth having). In this circuit, the current needed by the regulator flows from the positive capacitor end through the emitter and out from the base through the regulator to the negative end of the capacitor. Now the regulator voltage is below both the output voltage and the capacitor voltage and the emitter needs to be only about 1-2 V above the output voltage. You can even drive the series pass transistor into saturation (which requires quite a lot of base current) and hence reduce the capacitor-output voltage difference even further, since it is now easy to sink the base current. This is how the LDO (Low Drop Out voltage) regulators are implemented. |
#8
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On 25 Feb 2005 09:12:48 -0800, "SMJ" wrote:
Thanks for all the feedback. I tryed some of the websites you suggested but came up with nothing. Anyone know where I can find a book, or something online to learn more about this? Look at data sheets for typical integrated regulators and they usually have sections on external pass transistors for boosted current capability. Most often these show both an NPN emitter follower and a PNP arrangement. Your unit sounds like the PNP configuration inverted. |
#9
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August 1984 73 Magazine has one called the Cheap Power Ploy. I built one
years ago, it works great. Page 10 tom "SMJ" wrote in message ups.com... Anyone know where I can see a schematic of a common emitter power supply? I've always read about using the emitter of a pass transistor as the positive terminal output (Common collector). Taking apart this trip lite power supply I see that they have the negative terminal connecting to the collector of the npn pass transistors. This seems like it would extremely complicate the regulation design. Can anyone explain the benefits, and where I can learn more about this design technique? |
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