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#1
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Hi all,
THis is my first message on this forum. I recently purchased a National Panasonic RF-5000A shortwave receiver. It works quite well. However, it didn't come with the AC adapter normally fitted in those units. This means that I presently run it off 6 D cell batteries. I tried plugging it through a wall-wart AC-DC adapter but get a lot of hum. Would anyone happen to have a spare Panasonic AC adapter for this model that you would be willing to part with? The model number of the AC Adapter (which fits inside the back of the radio) is RD-9451 (9vDC, 400mA). Alternatively, if someone has suggestions for another way to get (relatively) hum-free DC into it from house current, I'd love to hear them. Thanks, and best regards, --Robert |
#2
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![]() "Robert St-Louis" wrote in message om... Hi all, THis is my first message on this forum. I recently purchased a National Panasonic RF-5000A shortwave receiver. It works quite well. However, it didn't come with the AC adapter normally fitted in those units. This means that I presently run it off 6 D cell batteries. I tried plugging it through a wall-wart AC-DC adapter but get a lot of hum. Would anyone happen to have a spare Panasonic AC adapter for this model that you would be willing to part with? The model number of the AC Adapter (which fits inside the back of the radio) is RD-9451 (9vDC, 400mA). Alternatively, if someone has suggestions for another way to get (relatively) hum-free DC into it from house current, I'd love to hear them. Welcome! Radio Shack sells replacement adapters. You'll need a 9V adapter with 400mA minimum output. This assumes the six "D" cells are inserted in series (all end-to-end). Make sure the adapter is rated for audio equipment, to minimize hum. Here's an 9V 800mA adapter which should work: http://www.radioshack.com/product.as...uct%5Fid=273-1 770 |
#3
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![]() "DesignGuy" wrote in message news:3wQmd.519700$mD.11692@attbi_s02... "Robert St-Louis" wrote in message om... Hi all, THis is my first message on this forum. I recently purchased a National Panasonic RF-5000A shortwave receiver. It works quite well. However, it didn't come with the AC adapter normally fitted in those units. This means that I presently run it off 6 D cell batteries. I tried plugging it through a wall-wart AC-DC adapter but get a lot of hum. Would anyone happen to have a spare Panasonic AC adapter for this model that you would be willing to part with? The model number of the AC Adapter (which fits inside the back of the radio) is RD-9451 (9vDC, 400mA). Alternatively, if someone has suggestions for another way to get (relatively) hum-free DC into it from house current, I'd love to hear them. Welcome! Radio Shack sells replacement adapters. You'll need a 9V adapter with 400mA minimum output. This assumes the six "D" cells are inserted in series (all end-to-end). Make sure the adapter is rated for audio equipment, to minimize hum. Here's an 9V 800mA adapter which should work: http://www.radioshack.com/product.as...uct%5Fid=273-1 770 Sorry, URL above was wrapped, try this: http://tinyurl.com/3yt96 |
#4
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Frightening the yaks, Robert St-Louis just had to say:
Hi all, THis is my first message on this forum. How-DEE! Alternatively, if someone has suggestions for another way to get (relatively) hum-free DC into it from house current, I'd love to hear them. If you don't mind a tiny bit of surgery on your current converter.... Project requirements: electrolytic capacitor (see below); sharp knife; voltmeter (or other polarity indicating device); soldering iron & solder; electrician's tape. Likely, it was designed for something that didn't care if the DC was filtered or not. You can add in a nice electrolytic capacitor to the cord that comes from the unit to filter the power. You need to get a cap that's about 1000-2500 uF and rated for at least 12 volts (35 would be more than enough.) Axial style is best (leads sticking out of each end.) And you'll need to know which is the positive and which is the negative lead, so you should have some sort of voltmeter to check. Assuming the cord is two insulated wires laid side-by-side, carefully cut between them to separate the two wires. This should probably be close to the converter end. How long the separation should be depends on the capacitor you have. Keep reading and you'll know how to tell. At one end of the split, carefully strip the insulation off the wire for about 3/4" (2cm.) Temporarily wrap the bare wire around one of the capacitor's leads. Next step is figuring out where to strip the other wire so that the other lead can be wrapped with the other wire. Try it and see where the wire needs to be stripped; then go ahead and strip it. Now, the polarity of the wired must be determined. Using whatever means you have, figure which is positive and which negative. The capacitor MUST be installed with its positive lead to the positive wire. For a 9volt circuit, it wouldn't explode, but it just wouldn't work well; with higher voltages there would be real dangers. Trim the leads of the capacitor to about 1/2" (1cm) then wrap the bare lead wires around the appropriate ends of the cap and solder. Use some black electrician's tape to completely cover the added part. All done! -- To reply, DO NOT remove spam from the return address! *************************** This calls for a careful blend of clever psychology and extreme violence. *************************** |
#5
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Lars Janqqvist wrote:
Frightening the yaks, Robert St-Louis just had to say: Hi all, THis is my first message on this forum. How-DEE! Alternatively, if someone has suggestions for another way to get (relatively) hum-free DC into it from house current, I'd love to hear them. If you don't mind a tiny bit of surgery on your current converter.... Project requirements: electrolytic capacitor (see below); sharp knife; voltmeter (or other polarity indicating device); soldering iron & solder; electrician's tape. Likely, it was designed for something that didn't care if the DC was filtered or not. You can add in a nice electrolytic capacitor to the cord that comes from the unit to filter the power. You need to get a cap that's about 1000-2500 uF and rated for at least 12 volts (35 would be more than enough.) Axial style is best (leads sticking out of each end.) And you'll need to know which is the positive and which is the negative lead, so you should have some sort of voltmeter to check. Assuming the cord is two insulated wires laid side-by-side, carefully cut between them to separate the two wires. This should probably be close to the converter end. How long the separation should be depends on the capacitor you have. Keep reading and you'll know how to tell. At one end of the split, carefully strip the insulation off the wire for about 3/4" (2cm.) Temporarily wrap the bare wire around one of the capacitor's leads. Next step is figuring out where to strip the other wire so that the other lead can be wrapped with the other wire. Try it and see where the wire needs to be stripped; then go ahead and strip it. Now, the polarity of the wired must be determined. Using whatever means you have, figure which is positive and which negative. The capacitor MUST be installed with its positive lead to the positive wire. For a 9volt circuit, it wouldn't explode, but it just wouldn't work well; with higher voltages there would be real dangers. Trim the leads of the capacitor to about 1/2" (1cm) then wrap the bare lead wires around the appropriate ends of the cap and solder. Use some black electrician's tape to completely cover the added part. All done! -- To reply, DO NOT remove spam from the return address! *************************** This calls for a careful blend of clever psychology and extreme violence. *************************** THOSE RECOMMENDATIONS ARE USUSUALLY EFFECTIVE,however in MY case I hadda buy a few parts and make a 3-terminal regulator LM317 REQUIRES HEAT SINK Adjustable power supply using LM317 I +-------+ O Vin (+) o-----+---| LM317 |---+--------------+-----o Vout (+) | +-------+ | | | | A / | | | \ R1 = 240 | | | / | ___ _|_ C1 | | +_|_ C2 |_0_| LM317 ___ .01 +-------+ ___ 1 uF | | 1 - Adjust | uF | - | |___| 2 - Output | \ | ||| 3 - Input | / R2 | 123 | \ | | | | Vin(-) o------+-------+----------------------+-----o Vout (-) For the LM317: R2 = (192 x Vout) - 240, where R2 in ohms, Vout is in volts and must be at between 1.2 V and 35 V. Vin should be at least 2.5V greater than Vout. Select a wall adapter with a voltage at least 2.5 V greater than your regulated output at full load Maximum output current is 1 A. Use proper heatsink for LM317 if it has to dissipate more than 1W. The tab of the LM317 is connected to the center pin. Equation for calculating the output voltage when R1 and R2 are known: Vout = 1.25V * (1 + R2/R1) + Iadj * R2 Where Iadj is typically in the range of 50 microamperes. from http://www.dxzone.com/cgi-bin/search...?ID=472&ID=472 |
#6
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Yodar wrote in message ...
Lars Janqqvist wrote: Frightening the yaks, Robert St-Louis just had to say: Alternatively, if someone has suggestions for another way to get (relatively) hum-free DC into it from house current, I'd love to hear them. If you don't mind a tiny bit of surgery on your current converter.... THOSE RECOMMENDATIONS ARE USUSUALLY EFFECTIVE,however in MY case I hadda buy a few parts and make a 3-terminal regulator LM317 REQUIRES HEAT SINK Thank you to both Lars and Tomi! I'll try Lars' solution and if the results aren't totally satisfactory with my setup, I might try Tomi's (which may be a little beyond my electronics capabilities, but who knows...). I'll do the surgery on my Radio Shack adapter this weekend. Looking forward to getting into shortwave listening again (it's been 20-25 years since I've done much of it). My other installation will be a suitable external antenna. Cheers!! --Robert |
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